Có ai bt lm bài này k giúp mk vs mk đang rất rất cần mong các bn giúp cho I.Change into passive voice.Chuyển các câu sau sang bị động 1. She had built a house for her parents in Da Lat ………………………………………………………………………………… 2. Somebody must do something for these poor men. ………………………………………………………………………………… 3. Nobody has made mistakes. ………………………………………………………………………………… 4. The teacher promised Jane a prize if she worked well. ………………………………………………………………………………… 5. Nobody spoke to me like that before. ………………………………………………………………………………… 6. Teachers should make lessons more interesting for school children. ………………………………………………………………………………… 7. We are locking the house up for summer . ………………………………………………………………………………… 8. People will tell us how much they expect of us. …………………………………………………………………………………
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1A house had been built for her parents in Da Lat by her
2.Something must be done for these poor man
3. Mistakes haven't been made
4.Jane was promised a prize by the teacher if she worked well
5. I wasn't spoken like that before
1. She had built a house for her parents in Da Lat ……A house had been built for her parents in Da Lat by her……………………………………………………………………………
2. Somebody must do something for these poor men. ………Something must be done for these poor man…………………………………………………………………………
3. Nobody has made mistakes. …………Mistakes haven't been made………………………………………………………………………
4. The teacher promised Jane a prize if she worked well. ………Jane was promised a prize by the teacher if she worked well…………………………………………………………………………
5. Nobody spoke to me like that before. …………I wasn't spoken like that before……………………………………………………………
a.
- Thử với lượng nhỏ mỗi chất.
| dd HCl | dd H2SO4 | |
| dd BaCl2 | Không hiện tượng | Kết tủa trắng |
\(H_2SO_4+BaCl_2\rightarrow BaSO_4\downarrow\left(trắng\right)+2HCl\)
b.
- Thử với lượng nhỏ mỗi chất.
| dd KCl | dd K2SO4 | |
| dd BaCl2 | Không hiện tượng | Kết tủa trắng |
\(K_2SO_4+BaCl_2\rightarrow BaSO_4\downarrow\left(trắng\right)+2KCl\)
c.
a.
- Thử với lượng nhỏ mỗi chất.
| dd K2SO4 | dd H2SO4 | |
| Qùy tím | Không đổi màu | Hóa đỏ |
Bài 3:
\(a,=\sqrt[3]{\left(x-1\right)^3}-\sqrt[3]{\left(5x+1\right)^3}=x-1-5x-1=-4x-2\\ b,=6a-6a+20a=20a\)
Bài 2:
\(a,=2\sqrt[3]{6}+3\sqrt[3]{5}-4\sqrt[3]{6}-2\sqrt[3]{5}=\sqrt[3]{5}-2\sqrt[3]{6}\\ b,=\sqrt[3]{8}-4\sqrt[3]{27}+2\sqrt[3]{64}=2-12+16=6\\ c,=\sqrt[3]{64}+\sqrt[3]{48}+\sqrt[3]{36}-\sqrt[3]{48}-\sqrt[3]{36}-\sqrt[3]{27}=4-3=1\\ d,=\sqrt[3]{162\left(-2\right)\cdot\dfrac{2}{3}}=\sqrt[3]{-216}=-6\)