\(\frac{1}{9}\).27x =9.25
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Tổng quát: \(\frac{1}{n}-\frac{1}{n+1}=\frac{n+1}{n\left(n+1\right)}-\frac{n}{n\left(n+1\right)}=\frac{1}{n\left(n+1\right)}\) (với mọi số tự nhiên n khác 0)
Ta có: \(\frac{1}{2.3}+\frac{1}{3.4}+\frac{1}{4.5}+....+\frac{1}{99.100}=\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+\frac{1}{4}-\frac{1}{5}+...+\frac{1}{99}-\frac{1}{100}\)
\(=\frac{1}{2}-\frac{1}{100}<\frac{1}{2}\) (vì \(\frac{1}{100}>0\) )
=>đpcm
\(\frac{9.25-63}{9.10+153}\)=\(\frac{9.25-9.7}{9.10+9.17}\)=\(\frac{9.\left(25-7\right)}{9.\left(10+17\right)}\)=\(\frac{9.18}{9.27}\)=\(\frac{1.2}{1.3}\)=\(\frac{2}{3}\)
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\(b)\) Đặt \(A=\frac{1}{2.3}+\frac{1}{3.4}+\frac{1}{4.5}+...+\frac{1}{99.100}\) ta có :
\(A=\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+\frac{1}{4}-\frac{1}{5}+...+\frac{1}{99}-\frac{1}{100}\)
\(A=\frac{1}{2}-\frac{1}{100}< \frac{1}{2}-0=\frac{1}{2}\)
\(\Rightarrow\)\(A< \frac{1}{2}\) ( đpcm )
Vậy \(A< \frac{1}{2}\)
Chúc bạn học tốt ~
\(a)\frac{9.25-63}{3.30+153}\)
\(=\frac{9.25-9.7}{3.30+3.51}\)
\(=\frac{9.\left(25-7\right)}{3.\left(30+51\right)}\)
\(=\frac{9.18}{3.81}\)
\(=\frac{1.6}{1.9}\)
\(=\frac{6}{9}\)
\(=\frac{2}{3}\)
b ) \(\frac{1}{2.3}+\frac{1}{3.4}+...+\frac{1}{99.100}\)
\(\Rightarrow\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+...+\frac{1}{99}-\frac{1}{100}\)
\(\Rightarrow\frac{1}{2}-\frac{1}{100}< \frac{1}{2}\left(Đpcm\right)\)
Chúc bạn học tốt !!!
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3^3.8^5.9.50/6^9.25^3
=3^3.8^5.3^2.2.25/2^9.3^9.25^3
=3^5.2^15.2.25/2^9.3^9.25^3
=2^6/2^8.3^4.25^2
=1/2^2.3^4.25^2
hơi khó nhìn tí nhưng cố gắng học nha bạn
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\(ĐặtA=\frac{-5}{9.13}-\frac{7}{9.25}-\frac{13}{19.25}-\frac{31}{19.69}\)
\(\frac{-1}{2}.A=\frac{5}{13.18}+\frac{7}{18.25}+\frac{13}{25.38}+\frac{31}{38.69}\)
\(\frac{-1}{2}.A=\frac{1}{13}-\frac{1}{18}+\frac{1}{18}-\frac{1}{25}+\frac{1}{25}-\frac{1}{38}+\frac{1}{38}-\frac{1}{69}\)
\(\frac{-1}{2}.A=\frac{1}{13}-\frac{1}{69}\)
\(\frac{-1}{2}.A=\frac{56}{897}\)
\(A=\frac{56}{897}:\left(-\frac{1}{2}\right)\)
\(A=\frac{56}{897}.\left(-2\right)\)
\(A=\frac{-112}{897}\)
Đề của bn sai nên mk sửa lại
Ủng hộ mk nha ^_^
Đặt \(A=\frac{-5}{9.13}-\frac{7}{9.25}-\frac{-13}{19.25}-\frac{31}{19.69}\)
\(\frac{A}{2}=\frac{-5}{18.13}-\frac{7}{18.25}-\frac{-13}{38.25}-\frac{31}{38.69}\)
Đến đây tự làm