giúp mik vs ạ gấp lắm!!!
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Những câu hỏi liên quan
28 tháng 1 2022
1. D => bỏ
2. C
3. C
4. A => the
5. A
6. C => next
7. C => taught
8. C => the most
9. D => from
10. B => would
II
1. I wish I would become a singer.
2. She used to walk to school when she was a child.
3. If I were you, I would learn Chinese
4. The man who I met yesterday was my uncle
5. The trees are watered by me everyday
2 tháng 1 2023
Bài 34:
a: =>x+28=0
=>x=-28
b: =>27-x=0 hoặc x+9=0
=>x=27 hoặc x=-9
c: =>x(x-43)=0
=>x=0 hoặc x=43
PL
2
30 tháng 8 2021
Câu 3:
a: Ta có: \(2x\left(3x-1\right)-\left(x-3\right)\left(6x+2\right)\)
\(=6x^2-2x-6x^2-2x+18x+6\)
=14x+6
b: Ta có: \(2x\left(x+7\right)-3x\left(x+1\right)\)
\(=2x^2+14x-3x^2-3x\)
\(=-x^2+11x\)
30 tháng 8 2021
Câu 2:
a: Ta có: \(\left(-8x^5+12x^3-16x^2\right):4x^2\)
\(=-8x^5:4x^2+12x^3:4x^2-16x^2:4x^2\)
\(=-2x^3+3x-4\)
b: Ta có: \(\left(12x^3y^3-18x^2y+9xy^2\right):6xy\)
\(=12x^3y^3:6xy-18x^2y:6xy+9xy^2:6xy\)
\(=2x^2y^2-3x+\dfrac{3}{2}y\)
c: Ta có: \(\dfrac{x^3-11x^2+27x-9}{x-3}\)
\(=\dfrac{x^3-3x^2-8x^2+24x+3x-9}{x-3}\)
\(=x^2-8x+3\)
d: Ta có: \(\dfrac{6x^4-13x^3+7x^2-x-5}{3x+1}\)
\(=\dfrac{6x^4+2x^3-15x^3-5x^2+12x^2+4x-5x-\dfrac{5}{3}-\dfrac{10}{3}}{3x+1}\)
\(=2x^3-5x^2+4x-\dfrac{5}{3}-\dfrac{\dfrac{10}{3}}{3x+1}\)
9 tháng 9 2021
\(4Na+O_2\rightarrow2Na_2O\)
\(Ca+\dfrac{1}{2}O_2\rightarrow CaO\)
\(S+O_2\xrightarrow[]{t^o}SO_2\)
\(Na_2O+H_2O\rightarrow2NaOH\)
\(K+H_2O\rightarrow KOH+\dfrac{1}{2}H_2\uparrow\)
\(SO_3+H_2O\rightarrow H_2SO_4\)
\(2KMnO_4\xrightarrow[]{t^o}K_2MnO_4+MnO_2+O_2\uparrow\)
\(Zn+2HCl\rightarrow ZnCl_2+H_2\)
\(Fe+H_2SO_4\rightarrow FeSO_4+H_2\)
\(H_2+\dfrac{1}{2}O_2\xrightarrow[]{t^o}H_2O\)
\(CuO+H_2\xrightarrow[]{t^o}Cu+H_2O\)
\(H_2+PbO\xrightarrow[]{t^o}Pb+H_2O\)
15 tháng 1 2022
Bài 1:
a: 4/9=4/9
5/3=15/9
b: 3/14=-18/84
-5/6=-70/84
c: -2/25=-14/175
-3/35=-15/175
d: -7/20=-35/100
-11/25=-44/100
e: -25/75=-1/3=-5/15
-12/30=-2/5=-6/15
\(a,4x^2-49=0\\ \Leftrightarrow\left(2x-7\right)\left(2x+7\right)=0\\ \Leftrightarrow\left[{}\begin{matrix}x=\dfrac{7}{2}\\x=-\dfrac{7}{2}\end{matrix}\right.\\ b,x^2+36=12x\\ \Leftrightarrow x^2-12x+36=0\\ \Leftrightarrow\left(x-6\right)^2=0\\ \Leftrightarrow x=6\\ c,\dfrac{1}{16}x^2-x+4=0\\ \Leftrightarrow\left(\dfrac{1}{4}x-2\right)^2=0\\ \Leftrightarrow\dfrac{1}{4}x-2=0\\ \Leftrightarrow x=8\\ d,x^3-3\sqrt{3}x^2+9x-3\sqrt{3}=0\\ \Leftrightarrow\left(x-\sqrt{3}\right)^3=0\\ \Leftrightarrow x=\sqrt{3}\)
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