5.32+60:2^2-(11-6)^2=
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5*32 +60:22-(11-6)2
=160+60:4-52
=160+15-25
=175-25=150
đúng tick cho mk nha
5.32+60:22-(11-6)2 =160+15-25=175-25=150
17.85+15.17-120=17.(85+15)-120=17.100-120=1700-120=1580
135.52+48.136=7020+6528=13548
17.85+15.17-120
=17.(85+15)-120
=17.100-120
=1700-120
=1580
\(750:\left\{32-\left[22+\left(5.32-420\right)\right]\right\}+100\)
\(=750:\left\{32-\left[22+\left(160-420\right)\right]\right\}+100\)
\(=750:\left\{32-\left[22+\left(-260\right)\right]\right\}+100\)
\(=750:\left[32-\left(-238\right)\right]+100\)
\(=750:270+100\)
\(=\dfrac{25}{9}+100\)
\(=\dfrac{925}{9}\)
Mình ko chắc có đúng hông, có gì thông kẻm nha fen
750 :{32-[22+(5.32-420)]}+100
=750:{32-[22+(160-420)]}+100
=750:{32-[22-260]}+100
=750:{32+238}+100
=750:270+100
=25/9+100
=925/9
tick giùm
a, 27.75 + 25.27 – 150
= 2025 + 675 – 150 = 2550
b, 142 – [50 – ( 2 3 .10 – 2 3 .5)]
= 142 – [50 – (80 – 40)] = 132
c, 375:{32 – [4+( 5 . 3 2 – 42]} – 14
= 375:{32 – [4+(45 – 42)]} – 14
= 375:(32 – 7) – 14 = 15 – 14 = 1
d, {210:[16+3.(6+3. 2 2 )]} – 3
= [210:(16+3.18)] – 3
= 210 : 70 – 3 = 3 – 3 = 0
a, 27.75 + 25.27 – 150
= 2025 + 675 – 150 = 2550
b, 142 – [50 – ( 2 3 .10 – 2 3 .5)]
= 142 – [50 – (80 – 40)] = 132
c, 375:{32 – [4+( 5 . 3 2 – 42]} – 14
= 375:{32 – [4+(45 – 42)]} – 14
= 375:(32 – 7) – 14 = 15 – 14 = 1
d, {210:[16+3.(6+3. 2 2 )]} – 3
= [210:(16+3.18)] – 3
= 210 : 70 – 3 = 3 – 3 = 0
1+2+3+4+5+6+7+8+9=45
10+20+39+40+50+60+70+80+90=459(Chắc bạn bấm nhầm 30->39)
11+22+33+44+55+66+77+88+99=495
Đặt \(A=\frac{1}{21}+\frac{1}{22}+...+\frac{1}{60}\)
\(A=\left(\frac{20}{20.21}+\frac{21}{21.22}+..+\frac{39}{39.40}\right)+\left(\frac{40}{40.41}+\frac{41}{41.42}+...+\frac{59}{59.60}\right)\)
\(\Rightarrow A>20.\left(\frac{1}{20.21}+\frac{1}{21.22}+...+\frac{1}{39.40}\right)+40.\left(\frac{1}{40.41}+\frac{1}{41.42}+...+\frac{1}{59.60}\right)\)
\(A>20\cdot\left(\frac{1}{20}-\frac{1}{40}\right)+40\cdot\left(\frac{1}{40}-\frac{1}{60}\right)=\frac{5}{6}>\frac{11}{15}\)
Mặt khác : \(A< 40\cdot\left(\frac{1}{20.21}+\frac{1}{21.22}+...+\frac{1}{38.40}\right)+60\cdot\left(\frac{1}{40.41}+\frac{1}{41.42}+...+\frac{1}{59.60}\right)\)
\(A< 40\cdot\left(\frac{1}{20}-\frac{1}{40}\right)+60\cdot\left(\frac{1}{40}-\frac{1}{60}\right)=\frac{3}{2}\)
Vậy ....
5.32+60:22-(11-6)2
= 5.32+60:4-25
= 160+15-25
= 175-25
= 150
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