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Đặt \(A=1+2+2^2+...+2^{32}\)
\(\Rightarrow2A=2+2^2+2^3+...+2^{33}\)
\(\Rightarrow2A-A=\left(2+2^2+2^3+...+2^{33}\right)-\left(1+2+2^2+...+2^{32}\right)\)
\(\Rightarrow A=2^{33}-1\)
\(\Rightarrow n=33\)
Vậy n = 33
_Chúc bạn học tốt_
1+2+2^2+2^3+2^4+...+2^32=2^n-1 (1)
=>2+2^2+2^3+...+2^33=2^(n+1)-2 (2)
=>trừ (2) cho (1) ta có : 2^33-1=(2-1)*(2^n-1)
=>2^33-1=2^n-1
=>n=33
vậy n=33
k cho mình nha
![](https://rs.olm.vn/images/avt/0.png?1311)
\(\frac{2}{7}< \frac{1}{n}< \frac{4}{7}\)
\(0,\left(285714\right)< \frac{1}{n}< 0,\left(571428\right)\)
\(\Rightarrow n\in\left\{2;3\right\}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
\(3.3^{n-1}\left(6.3^{n+2}+3\right)-2.3^n\left(3^{n+3}-1\right)=405\)
\(\Leftrightarrow18.3^{2n+1}+3.3^n-2.3^{2n+3}+2.3^n=405\)
\(\Leftrightarrow54.3^{2n}+5.3^n-2.3^3.3^{2n}=405\)
\(\Leftrightarrow3^n=81\)
\(\Leftrightarrow n=4\)
![](https://rs.olm.vn/images/avt/0.png?1311)
Rút gọn vế trái ta được 2^33-1
=> n = 33
Đặt \(A=1+2+2^2+2^3+......+2^{31}+2^{32}\)
Ta có:
\(A=1+2+2^2+2^3+......+2^{31}+2^{32}\)
\(\Leftrightarrow2A=2+2^2+2^3+......+2^{32}+2^{33}\)
\(\Leftrightarrow2A-A=\left(2+2^2+2^3+......+2^{32}+2^{33}\right)-\left(1+2+2^2+2^3+......+2^{31}+2^{32}\right)\)
\(\Leftrightarrow A=2^{33}-1\)
Mặt khác \(A=2^n-1\)
\(\Rightarrow2^{33}-1=2^n-1\)
\(\Rightarrow2^{33}-1-2^n+1=0\)
\(\Rightarrow2^{33}-2^n=0\)
\(\Rightarrow2^{33}=2^n\)
\(\Rightarrow n=33\)
Vậy n=33