Thực hiện phép tính:
a) ( 23 + 15) . 10000 + 0 : ( 32 + 50) + 12 : 1
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a) 23 x 5 - 10
= ( 23 x 10 ) - 5
= 225
b) 150 + 50 : 5 - 32
= ( 150 + 50 ) : 5 - 32
= 200 : 5 - 32
= 40 - 32
= 8
c) 80 - ( 83 - ( 12 - 32 )
= 83 - 12 - 80 - 32
= 71 - 48
= 23
a) − 105 + − 25 + ( − 105 ) + 50
= 105 + 25 + ( - 105) + 50
= [105 + ( -105)] + ( 25 + 50 )
= 0 + 75 = 75
b) 465 + − 38 + − 465 − 12 − − 42
= 465 + ( - 38) + ( -465) – 12 – 42
= [ 465 + (- 465) ] – ( 12 + 42 )
= 0 – 54 = 0 + ( -54 ) = -54
c) 65. − 19 + − 19 .24 + − 19 .11
= ( - 19) . ( 65 + 24 + 11 )
= ( -19) . 100 = -1900
d) − 3 2 + 2 3 − − 5 2 + 4 3
= 9 + 8 – 25 + 64 = 56
a)
-37 +14 +26+37=(-37+37)+(14+26)=30
b) =(-24+24)+(6+10)=16
c)=(-23+23)+(25+15)=40
d)=(-33+33)+(-50+60)=10
e)=(-209+209)+[-14+(-16)]=-30
\(98.42-50\left[\left(18-2^3\right):2+3^2\right]\\ =4116-50\left[\left(18-8\right):2+9\right]\\ =4116-50\left[10:2+9\right]\\ =4116-50\left[5+9\right]\\ =4116-50.14\\ =4116-700\\ =3416\)
98.42-50.[(18-23):2 +32]
=98.42-50.[(18-8):2+32]
=98.42-50.[10:2+3]
=98.42-50.[5+3]
=98.42-50.8
= 4116-400
=3716
a) \(3.5^2+15.2^2-26\div2\)
= 3.25 + 15.4 - 13
= 75 + 60 - 13
= 135 - 13
= 122
b) \(5^3.2-100\div4+2^3.5\)
= 125.2 - 25 + 8.5
= 250 - 25 + 40
= 225 + 40
= 265
c)\(6^2\div9+50.2-3^3.33\)
= 36 : 9 + 100 - 9.33
= 4 + 100 - 297
= 104 - 297
= -193
d)\(3^2.5+2^3.10-81\div3\)
= 9.5 + 8.10 - 27
= 45 + 80 - 27
= 125 - 27
= 98
e) \(5^{13}\div5^{10}-25.2^2\)
= 53 - 25.4
= 125 - 100
= 25
f) \(20\div2^2+5^9\div5^8\)
= 20 : 4 + 5
= 5 + 5
= 10
a, \(\dfrac{7}{15}\)+\(\dfrac{18}{54}\)
= \(\dfrac{7}{15}\)+ \(\dfrac{1}{3}\)
= \(\dfrac{7}{15}\)+\(\dfrac{5}{15}\)
= \(\dfrac{12}{15}\) = \(\dfrac{4}{5}\) =0,8
b, \(\dfrac{12}{25}\)+\(\dfrac{23}{75}\)-\(\dfrac{1}{4}\)
= \(\dfrac{59}{75}\) -\(\dfrac{1}{4}\)
= \(\dfrac{161}{300}\)
a, 27.75 + 25.27 – 150
= 2025 + 675 – 150 = 2550
b, 142 – [50 – ( 2 3 .10 – 2 3 .5)]
= 142 – [50 – (80 – 40)] = 132
c, 375:{32 – [4+( 5 . 3 2 – 42]} – 14
= 375:{32 – [4+(45 – 42)]} – 14
= 375:(32 – 7) – 14 = 15 – 14 = 1
d, {210:[16+3.(6+3. 2 2 )]} – 3
= [210:(16+3.18)] – 3
= 210 : 70 – 3 = 3 – 3 = 0
a, 27.75 + 25.27 – 150
= 2025 + 675 – 150 = 2550
b, 142 – [50 – ( 2 3 .10 – 2 3 .5)]
= 142 – [50 – (80 – 40)] = 132
c, 375:{32 – [4+( 5 . 3 2 – 42]} – 14
= 375:{32 – [4+(45 – 42)]} – 14
= 375:(32 – 7) – 14 = 15 – 14 = 1
d, {210:[16+3.(6+3. 2 2 )]} – 3
= [210:(16+3.18)] – 3
= 210 : 70 – 3 = 3 – 3 = 0
\(\left[32-\left(-15\right)\right]+\left[-12-45\right]-\left[15+\left(-41\right)-12\right]\)
\(=32+15-12-45-15+41+12\)
\(=32-45+41+\left(15-15\right)+\left(12-12\right)\)
\(=28\)
\(\left(2^3+1^5\right).1000^0+0:\left(3^2+5^0\right)+1^2+1\)
\(=\left(2^3+1\right).1+0:\left(3^2+5\right)+1:1\)
\(=2^3+1+0+1\)
\(=8+1+1\)
\(=10\)
a) \(\left(2^3+1^5\right).1000^0+0:\left(3^2+5^0\right)+1^2:1\)
\(=2^3+1+0+1\)
\(=10\)