tìm số nguyên x
-(x+2)-(X+3)=x
-(x+2)+x+3=x
x+2+x+3=x
trả lời gấp nha.thanks.
love
Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.
a) \(\left(x+5\right)+9-x=x+2\)
\(\Leftrightarrow\left(x+5\right)+9-x-\left(x+2\right)=0\)
\(\Leftrightarrow x+5+9-x-x-2=0\)
\(\Leftrightarrow12-x=0\)
\(\Leftrightarrow x=12-0\)
\(\Leftrightarrow x=12\)
Vậy x=12
b) \(x+5+9-x=x+2\)
\(\Leftrightarrow x+5+9-x-\left(x+2\right)=0\)
\(\Leftrightarrow x+5+9-x-x-2=0\)
\(\Leftrightarrow12-x=0\)
\(\Leftrightarrow x=12-0\)
\(\Leftrightarrow x=12\)
Vậy x=12
c) \(x+5+x-9=x+2\)
\(\Leftrightarrow x+5+x-9-\left(x+2\right)=0\)
\(\Leftrightarrow x+5+x-9-x-2=0\)
\(\Leftrightarrow x-6=0\)
\(\Leftrightarrow x=6+0\)
\(\Leftrightarrow x=6\)
Vậy x=6
1. x + 2x = -36
=> 3x = -36
=> x = -36 : 3
=> x = -12
2. (2x + 3) \(⋮\)(x - 2)
=> (2x - 2) + 5 \(⋮\)(x - 2)
=> 2(x - 2) + 5 \(⋮\)(x - 2)
=> 5 \(⋮\)(x - 2)
=> x - 2 \(\in\)Ư(5) = {-5;-1;1;5}
=> x \(\in\){-3;1;3;7}
3. Khi đó a . (-b) = -132
4. -2(3x + 2) = 12 + 22 + 32
=> -2(3x + 2) = 1 + 4 + 9
=> -2(3x + 2) = 14
=> 3x + 2 = 14 : (-2)
=> 3x+ 2 = -7
=> 3x = -7 - 2
=> 3x = -9
=> x = -9 : 3
=> x = -3
1/ \(x+2x=-36\)
\(\Rightarrow3x=-36\)
\(\Rightarrow x=-\frac{36}{3}\)
\(\Rightarrow x=-12\)
2/ \(\left(2x+3\right)⋮\left(x-2\right)\)
\(\Leftrightarrow\left(2x-4\right)+7⋮\left(x-2\right)\)
\(\Leftrightarrow2\left(x-2\right)+7⋮\left(x-2\right)\)
\(\Rightarrow7⋮\left(x-2\right)\)
\(\Rightarrow\left(x-2\right)\inƯ\left(7\right)\)
\(\Rightarrow x\inƯ\left(7-2\right)\)
\(\Rightarrow x\inƯ\left(5\right)\)
\(\Rightarrow x\in\left\{-5,1,5\right\}\)
Vậy x nhỏ nhất để \(\left(2x-3\right)⋮\left(x-2\right)\) là -5
3/ Vì \(a\cdot b=32\)
\(\Rightarrow-a\cdot b=-\left(a\cdot b\right)=-32\)
4/ \(-2\left(3x+2\right)=1^2+2^2+3^2\)
\(\Leftrightarrow-6x-4=1+4+9\)
\(\Leftrightarrow-6x=14+4\)
\(\Leftrightarrow-6x=18\)
\(\Leftrightarrow x=\frac{18}{-6}\)
\(\Rightarrow x=3\)
Ta có: -210=(-1)+(-2)+(-3)+...+(-x+1)+(-x)
-210=-[1+2+3+...+(x-1)+x)]
-210=\(-\left[\frac{x\left(x+1\right)}{2}\right]\)
hay 210=\(\left[\frac{x\left(x+1\right)}{2}\right]\)
=> x(x+1)=210.2=420
=> 20.21=420 => x=20
-210 = (-1) + (-2) + (-3) + ... + (-x + 1) + (-x)
=> -210 = -(1 + 2 + 3 + ... + x - 1 + x)
=> 210 = 1 + 2 + 3 + ... + x - 1 + x
=> 210 = (x + 1) . x : 2
=> 420 = (x + 1) . x
=> (20 + 1) . 20 = (x + 1) . x
=> x = 20
Số số hạng là :
-x - (-1) = -x + 1 (số)
Tổng là :
[-x + (-1)].(-x + 1):2 = (-x - 1).(-x + 1):2 = -210
=> (-x - 1).(-x + 1) = -420
=> (-x)2 - 12 = -420
=> (-x)2 = -419
=> x không tồn tại vì (-x)2 > (=) 0
a) \(-\left(x+2\right)-\left(x+3\right)=x\)
\(\Leftrightarrow-\left(x+2\right)-\left(x+3\right)-x=0\)
\(\Leftrightarrow-x-2-x-3-x=0\)
\(\Leftrightarrow-3x-5=0\)
\(\Leftrightarrow-3x=5\)
\(\Leftrightarrow x=\dfrac{-5}{3}\)
Vậy \(x=\dfrac{-5}{3}\)
b) \(-\left(x+2\right)+x+3=x\)
\(\Leftrightarrow-\left(x+2\right)+x+3-x=0\)
\(\Leftrightarrow-x-2+x+3-x=0\)
\(\Leftrightarrow-x+1=0\)
\(\Leftrightarrow-x=-1\)
\(\Leftrightarrow x=1\)
Vậy \(x=1\)
c) \(x+2+x+3=x\)
\(\Leftrightarrow x+2+x+3-x=0\)
\(\Leftrightarrow x+5=0\)
\(\Leftrightarrow x=-5\)
Vậy \(x=-5\)
THANKS
LOVE ...