(2x-39).7+3=80
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a) x = 2.
b) x = 7.
c) x= 12.
d) x= 45.
e) x = 18.
f) x = 10.
a)210-5x=200
5x=210-200
5x=10
x=10:2
x=5
B)210-5(x-10)=200
5(x-10)=210-200
5(x-10)=10
x-10=10:5=2
x=2+10=12
c)450:[41-(2x-5)]=3 mũ 2 .5
450:[41+5-2x]=45
41+5-2x=450:45
41+5-2x=10
2x=36
x=18
D)210:x-10=20
210:x=20+10
210:x=30
x=210:30
x=7
E)(5x-39).7+3=80
(5x-39).7=77
5x-39=11
5x=50
x=10
F(2x+1):7=2 mũ 2 nhân 3 mũ 2
(2x+1):7=36
2x+1=252
2x=251
x=251/2
\((5x-39)\cdot7+3=80\\\Rightarrow (5x-39)\cdot7=80-3\\\Rightarrow (5x-39)\cdot7=77\\\Rightarrow 5x-39=77:7\\\Rightarrow 5x-39=11\\\Rightarrow5x=11+39\\\Rightarrow5x=50\\\Rightarrow x=50:5=10\\Vậy:x=10\)
(5x - 39).7 + 3 = 80
(5x - 39).7 = 80 - 3
(5x - 39).7 = 77
5x - 39 = 77 : 7
5x - 39 = 11
5x = 11 + 39
5x = 50
x = 50 : 5
x = 10
Làm chi tiêt hơn ạ.
(5x - 39 ) . 7 + 3 = 80
( 5x - 39 ) .7 = 80 - 3
( 5x - 39 ) . 7 = 77
5x - 39 = 77:7
5x - 39 = 11
5x = 39 + 11
5x = 50
x = 50 : 5
x = 10
Vậy x = 10
\(=\left(\dfrac{1}{8}+\dfrac{2}{5}-\dfrac{3}{40}\right):\left[\dfrac{80}{7}+\dfrac{17}{2}\cdot\dfrac{-877}{84}\right]\)
\(=\dfrac{5+16-3}{40}\cdot\dfrac{168}{-4489}=\dfrac{9}{20}\cdot\dfrac{-168}{4489}=\dfrac{-378}{22445}\)
(2x-39).7+3=80
(2x-39).7=80-3
(2x-39).7=77
2x-39=77:7
2x-39=11
2x=11+39
2x=50
x=50:2
x=25
(2x-39).7+3=80
(2x-39).7 =80-3
(2x-39).7 =77
2x-39 =77:7
2x-39 =11
2x =11+39
2x =50
x =50:2
x =25
Vậy x = 25.