Tính nhanh:
1.2 + 2.3 + 3.4 + 4.5 + ...+ 100.101
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A = 1.2 + 2.3 + 3.4 + 4.5 + ... + 99.100 + 100.101
3.A = 1.2.3 + 2.3.3 +3.4.3 + ... + 100.101.3
3A= 1.2.3 + 2.3.(4 - 1) + 3.4.(5 - 2) + ... + 100.101.(102 - 99)
3A = 1.2.3 + 2.3.4 - 1.2.3 + 2.3.4 -3.4.5 + ... +99.100.101 -100.101.102
3A = 99.100.101
A = 99.100.101 : 3
A = 33.100.101
Vậy A = 33. 100 .101 (Tự tính)
A = 1.2 + 2.3 + 3.4 + ... + 99.100 + 100.101
⇒ 3A = 1.2.3 + 2.3.3 + 3.4.3 + ... + 99.100.3 + 100.101.3
= 1.2.3 + 2.3.(4 - 1) + 3.4.(5 - 2) + ... + 99.100.(101 - 98) + 100.101.(102 - 99)
= 1.2.3 - 1.2.3 + 2.3.4 - 2.3.4 + 3.4.5 + ... - 98.99.100 + 99.100.101 - 99.100.101 + 100.101.102
= 100.101.102
= 1030200
⇒ A = 1030200 : 3
= 343400
Ta có 3A=1.2.3+2.3.4-1.2.3+3.4.5-2.3.4+4.5.6-3.4.5+....+100.101.102-99.100.101
\(\Rightarrow\)3A=100.101.102
\(\Rightarrow\)A=343400
B=1.2+1+2.3+1+3.4+1+...+100.101+100
\(\Rightarrow\)B=1.2+2.3+3.4+...+100.101+[1+2+3+..+100]
Mặt khác 1.2+2.3+3.4+4.5+...+100.101=A
\(\Rightarrow\)B=343400+101.100:2=348450
Ta có :
A = 1.2+2.3+3.4+4.5+...+100.101
B = 1.3+2.4+3.5+4.6+....+100.102
=> B - A = ( 1.2+2.3+3.4+4.5+...+100.101) - (1.3+2.4+3.5+4.6+...+100.102)
=> B - A = 1.2+2.3+3.4+4.5+...+100.101-1.3-2.4-3.5-4.6-....-100.102
=> B - A = 1.2+(2.3-1.3)+(3.4-2.4)+(4.5-3.5)+...+(100.101-99.101)-100.102
=> B - A = 2+3+4+5+...+101-10200
=> B - A = (2+101)+(3+100)+...+(51+52)-10200
=> B - A = 103+103+103+....+103-10200 ( 50 SỐ 103 )
=> B - A = 103.50-10200
=> B - A = 5150-10200
=> B - A = -5050
Cách làm đúng nhưng bạn lấy nhầm A-B thay vì B-A rồi, kết quả là 5050 mới đúng
Ta có : A = 1.2 + 2.3 + 3.4 + ...... + 100.101
=> 3A = 1.2.3 - 1.2.3 + 2.3.4 - 2.3.4 + ...... + 100.101.102
=> 3A = 100.101.102
=> A = 100.101.102/3
=> A = 343400
Đặt S= 1.2 + 2.3 + 3.4 + ...+ 99.100
3S = 1.2.3+2.3.3+3.4.3+...+98.99.3+99.100.3
3S= 1.2.3+2.3(4-1)+3.4(5-2)+...+98.99(100-97)+99.100(101-98)
3S= 1.2.3+2.3.4-1.2.3+3.4.5-2.3.4+...-97.98.99+99.100.101-98.99.100
3S = 99.100.101 3S = 3.33.100.101
S=33.100.101= 333300
Nhớ **** cho mjk với nhak!!!!!
Đặt S= 1.2 + 2.3 + 3.4 + ...+ 99.100
3S = 1.2.3+2.3.3+3.4.3+...+98.99.3+99.100.3
3S= 1.2.3+2.3(4-1)+3.4(5-2)+...+98.99(100-97)+99.100(101-98)
3S= 1.2.3+2.3.4-1.2.3+3.4.5-2.3.4+...-97.98.99+99.100.101-98.99.100
3S = 99.100.101 3S = 3.33.100.101
S=33.100.101= 333300
Nhớ **** cko mjk nhak!!
S = 1 + 2 + 2² + 2³ + 2⁴ + ... + 2¹⁰⁰
2S = 2 + 2² + 2³ + 2⁴ + ... + 2¹⁰¹
S = 2S - S
= (2 + 2² + 2³ + ... + 2¹⁰¹) - (1 + 2 + 2² + ... + 2¹⁰⁰)
= 2¹⁰¹ - 1
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S = 1.2 + 2.3 + 3.4 + ... + 99.100 + 100.101
3S = 1.2.3 + 2.3.(4 - 1) + 3.4.(5 - 2) + ... + 99.100.(101 - 98) + 100.101.(102 - 99)
= 1.2.3 - 1.2.3 + 2
3.4 - 2.3.4 + 3.4.5 - ... - 98.99.100 + 99.100.101 - 99.100.101 + 100.101.102
= 100.101.102
S = 100 . 101 . 102 : 3
= 343400
------------
Q = 1² + 2² + 3² + ... + 100² + 101²
= 101.102.(2.101 + 1) : 6
= 348551
1.Tính
A= (1-1/22).(1-1/32)...(1-1/1002)
B= -1/1.2-1/2.3-1/3.4-...-1/100.101
C= 1.2+2.3+3.4+...+100.101
Lời giải :
Đặt S=1.2+2.3+3.4+4.5+…+99.100+100.101
3S=1.2.3+2.3.3+3.4.3+4.5.3+…+99.100.3+100.101.3
=1.2(3−0)+2.3(4−1)+3.4(5−2)+4.5(6−3)+…+99.100(101−98)+100.101(102−99)
=0.1.2-1.2.3+1.2.3-2.3.4+...+99.100.101-100.101.102
=100.101.102
S=100.101.34=343400
1.Tính
a) Ta có:
A=(1-1/22).(1-1/32)...(1-1/1002)
=>A=3/22.8/32.....9999/1002
=>A=(1.3/2.2).(2.4/3.3).....(99.101/100.100)
=>A=(1.2.3.....99/2.3.4.....100).(3.4.5.....101/2.3.4.....100)
=>A=1/100.101/2
=>A=101/200
b) Ta có:
B=-1/1.2-1/2.3-1/3.4-...-1/100.101
=>B=-(1/1.2+1/2.3+1/3.4+...+1/100.101)
=>B=-(1-1/2+1/2-1/3+1/3-1/4+...+1/100-1/101)
=>B=-(1-1/101)
=>B=-100/101
c) Ta có:
C=1.2+2.3+3.4+...+100.101
=>3C=1.2.3+2.3.3+3.4.3+...+100.101.3
=>3C=1.2.3+2.3.(4-1)+3.4.(5-2)+...+100.101.(102-99)
=>3C=1.2.3-1.2.3+2.3.4-2.3.4+3.4.5-3.4.5+...+100.101.102
=>3C=100.101.102
=>3C=1030200
=>C=343400
Chúc bạn hok tốt nhé >:)!!!!!
Gọi biểu thức này là S , ta có
S =1.2 + 2.3 + 3.4 + 4.5 + ...+ 100.101
3S= 1. 2 .3 + 2. 3 .3 + 3 . 4 .3 + 4 .5 .3 + ...........+ 100 .101 .3
3S= 1.2 (3 - 0) + 2 . 3 .(4 - 1) + 3 . 4. (5 - 2 ) +.......+ 100 . 101 . (102 - 99)
3S = 1 . 2 . 3 - 0 . 1 .2 + 2 . 3 . 4 - 1 . 2 .3 + ................+ 100 . 101 .102 - 99 100 . 101
S = \(\frac{100.101.102}{3}=\frac{100.101.34}{1}\)
S = 343400