Question

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Answer 1

[Nguyễn Huy Tú]

1, \(\sqrt{12}+5\sqrt{3}-\sqrt{48}=2\sqrt{3}+5\sqrt{3}-4\sqrt{3}=3\sqrt{3}\)

2, \(5\sqrt{5}+\sqrt{20}-3\sqrt{45}=5\sqrt{5}+2\sqrt{5}-6\sqrt{5}=\sqrt{5}\)

còn đâu bạn tự làm, tương tự 

7, \(\sqrt{11+6\sqrt{2}}+\sqrt{11-6\sqrt{2}}=\sqrt{9+2.3\sqrt{2}+2}+\sqrt{9-2.3\sqrt{2}+2}\)

\(=\sqrt{\left(3+\sqrt{2}\right)^2}+\sqrt{\left(3-\sqrt{2}\right)^2}=3+\sqrt{2}+3-\sqrt{2}=6\)

8, \(\sqrt{4+2\sqrt{3}}+\sqrt{4-2\sqrt{3}}=\sqrt{\left(\sqrt{3}+1\right)^2}+\sqrt{\left(\sqrt{3}-1\right)^2}\)

\(=\sqrt{3}+1+\sqrt{3}-1=2\sqrt{3}\)

9, \(\sqrt{8-2\sqrt{7}}-\sqrt{11-4\sqrt{7}}=\sqrt{\left(\sqrt{7}-1\right)^2}-\sqrt{7-4\sqrt{7}+4}\)

\(=\sqrt{7}-1-\sqrt{\left(\sqrt{7}-2\right)^2}=\sqrt{7}-1-\sqrt{7}+2=1\)