Question

[ahri]

tìm x

c)[3(x+\(\dfrac{1}{2}\))+5(0,6-x)].50%=-x:6\(\dfrac{1}{5}\)

Answer 1

[Lê Gia Bảo]

\(\Rightarrow\)\(\left[3x+\dfrac{3}{2}+3-5x\right].\dfrac{1}{2}=-x:\dfrac{31}{5}\)

\(\Rightarrow\)\(\left[-2x+\dfrac{9}{2}\right].\dfrac{1}{2}=-x.\dfrac{5}{31}\)

\(\Rightarrow\)\(\dfrac{-2x}{2}+\dfrac{9}{4}=-x.\dfrac{5}{31}\)

\(\Rightarrow\)\(-x+\dfrac{9}{4}=-x.\dfrac{5}{31}\)

\(\Rightarrow\dfrac{9}{4}=\dfrac{-x5}{31}+x\)

\(\Rightarrow\dfrac{9}{4}=\dfrac{-x5+31x}{31}\)

\(\Rightarrow\dfrac{9}{4}=\dfrac{x\left(-5+31\right)}{31}\)

\(\Rightarrow\dfrac{9}{4}=\dfrac{x.26}{31}\)

\(\Rightarrow\dfrac{9}{4}.31=x.26\)\(\Rightarrow\dfrac{279}{4}=x.26\)

\(\Rightarrow x=\dfrac{279}{4}:26=\dfrac{279}{4}.\dfrac{1}{26}\)

\(\Rightarrow x=\dfrac{279}{104}\)

Vậy x=\(\dfrac{279}{104}\)