Question

[Trần Khánh Huyền]

giải giúp em bài ni vs ạ, em cảm tạ

Answer 1

[Nguyễn Lê Phước Thịnh]

a: \(\dfrac{x^3-3x^2}{x-3}=\dfrac{x^2\left(x-3\right)}{x-3}=x^2\)

b: \(\dfrac{2x^2+2x-4}{x+2}=\dfrac{2\left(x^2+x-2\right)}{x+2}=2\left(x-1\right)=2x-2\)

c: \(\dfrac{x^3+x^2-12}{x-2}=\dfrac{x^3-2x^2+3x^2-6x+6x-12}{x-2}=x^2+3x+6\)

d: \(\dfrac{-3x^3-9x+5x^2+15}{5-3x}=\dfrac{3x^3-5x^2+9x-15}{3x-5}\)

\(=\dfrac{x^2\left(3x-5\right)+3\left(3x-5\right)}{3x-5}=x^2+3\)