Cho hình hộp ABCD.A'B'C'D'. Chứng minh rằng :
a) \(\overrightarrow{AB}+\overrightarrow{B'C'}+\overrightarrow{DD'}=\overrightarrow{AC'}\)
b) \(\overrightarrow{BD}-\overrightarrow{D'D}-\overrightarrow{B'D'}=\overrightarrow{BB'}\)
c) \(\overrightarrow{AC}+\overrightarrow{BA'}+\overrightarrow{BD}+\overrightarrow{C'D}=\overrightarrow{0}\)
