Bài 1: Tìm x biết:
a,7/x = x.28 b, 40+x/77-x = 6/7
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Lời giải:
a. $\frac{7}{x}=\frac{x}{28}$
$\Rightarrow x^2=7.28=196=14^2=(-14)^2$
$\Rightarrow x=\pm 14$
b.
$\frac{x+10}{x+17}=\frac{3}{4}$
$\Rightarrow 4(x+10)=3(x+17)$
$\Rightarrow 4x+40=3x+51$
$\Rightarrow x=11$
c.
$\frac{40+x}{77-x}=\frac{6}{7}$
$\Rightarrow 7(40+x)=6(77-x)$
$\Rightarrow 280+7x=462-6x$
$\Rightarrow 13x=182$
$\Rightarrow x=182:13=14$
Lời giải:
a. $\frac{7}{x}=\frac{x}{28}$
$\Rightarrow x^2=7.28=196=14^2=(-14)^2$
$\Rightarrow x=\pm 14$
b.
$\frac{x+10}{x+17}=\frac{3}{4}$
$\Rightarrow 4(x+10)=3(x+17)$
$\Rightarrow 4x+40=3x+51$
$\Rightarrow x=11$
c.
$\frac{40+x}{77-x}=\frac{6}{7}$
$\Rightarrow 7(40+x)=6(77-x)$
$\Rightarrow 280+7x=462-6x$
$\Rightarrow 13x=182$
$\Rightarrow x=182:13=14$
1a) \(\frac{x-3}{x+7}=\frac{-5}{-6}\)
=> \(\frac{x-3}{x+7}=\frac{5}{6}\)
=> (x - 3).6 = 5.(x + 7)
=> 6x - 18 = 5x + 35
=> 6x - 5x = 35 + 18
=> x = 53
b) \(\frac{x-7}{x+3}=\frac{4}{3}\)
=> (x - 7). 3 = (x + 3). 4
=> 3x - 21 = 4x + 12
=> 3x - 4x = 12 + 21
=> -x = 33
=> x = -33
c) \(\frac{x-10}{6}=-\frac{5}{18}\)
=> (x - 10) . 18 = -5 . 6
=> 18x - 180 = -30
=> 18x = -30 + 180
=> 18x = 150
=> x = 150 : 18 = 25/3
d) \(\frac{x-2}{4}=\frac{25}{x-2}\)
=> (x - 2)(x - 2) = 25 . 4
=> (x - 2)2 = 100
=> (x - 2)2 = 102
=> \(\orbr{\begin{cases}x-2=10\\x-2=-10\end{cases}}\)
=> \(\orbr{\begin{cases}x=12\\x=-8\end{cases}}\)
e) \(\frac{7}{x}=\frac{x}{28}\)
=> 7 . 28 = x . x
=> 196 = x2
=> x2 = 142
=> \(\orbr{\begin{cases}x=14\\x=-14\end{cases}}\)
f) \(\frac{40+x}{77-x}=\frac{6}{7}\)
=> (40 + x) . 7 = (77 - x).6
=> 280 + 7x = 462 - 6x
=> 280 - 462 = -6x + 7x
=> -182 = x
=> x = -182
Bài 1:
a) x + \(\frac{1}{9}\) - \(\frac{3}{5}\) = \(\frac{3}{6}\) b) \(\frac{3}{4}\) - x + \(\frac{6}{11}\) = \(\frac{5}{6}\)
x + \(\frac{1}{9}\) = \(\frac{3}{6}\) + \(\frac{3}{5}\) \(\frac{3}{4}\) - x = \(\frac{5}{6}\) - \(\frac{6}{11}\)
x + \(\frac{1}{9}\) = \(\frac{11}{10}\) \(\frac{3}{4}\) - x = \(\frac{19}{66}\)
x = \(\frac{11}{10}\) - \(\frac{1}{9}\) x = \(\frac{19}{66}\) + \(\frac{3}{4}\)
x = \(\frac{89}{90}\) x = \(\frac{137}{132}\)
Bài 2
a) x : 13/16 = 5/8 b)x - 14/28 = 6/9 + 8/25
x = 5/8 * 13/16 x - 14/28 = 74/75
x = 65/128 x = 74/75 + 14/28
x = 223/150
Bài 3
a)62/7 * x = 29/9 : 3/56 b)1/5 : x = 1/5 + 1/7
62/7 * x = 1624/27 1/5 : x = 12/35
x = 1624/27 : 62/7 x = 12/35 * 1/5
x = 5684/637 x = 12/175
a) Ta có : ( x + 1 ).( 3 - x ) > 0
Th1 : \(\hept{\begin{cases}x+1>0\\3-x>0\end{cases}\Rightarrow\hept{\begin{cases}x>-1\\x>3\end{cases}\Rightarrow}x>3}\)
Th2 : \(\hept{\begin{cases}x+1< 0\\3-x< 0\end{cases}\Rightarrow\hept{\begin{cases}x< -1\\x< 3\end{cases}\Rightarrow}x< -1}\)
Bài 1 :
a) = 98765
b) = 300657
c) 610000
Bài 2:
a) X + 77 = 1800
X = 1800 - 77
X = 1723
b) 8950 : x = 5
x = 8950 : 5
x = 1790
c) x = 8765 : 5
x = 1753
a,98765 b,300657 c,610000 Bài 2 : a, 17923 b, 1790 c, 1753
a: 7/x=x/28
nên x2=196
=>x=14 hoặc x=-14
b: \(\dfrac{40+x}{77-x}=\dfrac{6}{7}\)
=>7x+280=462-6x
=>13x=182
hay x=14