3/7+2/21-3/14
5/4-5/12+3/8
7/12x8/21:2/3
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\(\frac{1.3.5+2.6.10+4.12.20+7.21.35}{1.5.7+2.10.14+4.20.28+7.35.49}\)
\(=\frac{1.3.5\left(1+2+4+7\right)}{1.5.7\left(1+2+7+7\right)}=\frac{1.3.5}{1.5.7}=\frac{15}{35}=\frac{3}{7}\)
\(\frac{1\cdot3\cdot5+2\cdot6\cdot10+4\cdot12\cdot20+7\cdot21\cdot35}{1\cdot5\cdot7+2\cdot10\cdot14+4\cdot20\cdot28+7\cdot35\cdot49}\)
\(=\)\(\frac{1\cdot3\cdot5\cdot\left(1+2+4+7\right)}{1\cdot5\cdot7\cdot\left(1+2+7+7\right)}\)
\(=\frac{1\cdot3\cdot5}{1\cdot5\cdot7}\)\(=\frac{15}{35}=\frac{3}{7}\)
bn vội quá viết nhầm lun kìa
hj hj chúc bn làm bài tốt nha
\(=\dfrac{3}{2}-\dfrac{2}{21}-\dfrac{7}{12}+\left[\dfrac{15}{21}-\dfrac{1}{3}+\dfrac{5}{4}-\dfrac{2}{7}-\dfrac{1}{3}\right]\)
=11/12-2/21+5/7-2/3+5/4-2/7
=11/12-2/3+5/4-2/21+3/7
=11/12-8/12+15/12-2/21+9/21
=18/12+7/21
=3/2+1/3
=9/6+2/6=11/6
\(B=\dfrac{3}{2}-\dfrac{2}{21}-\left\{\dfrac{7}{12}-\left[\dfrac{15}{21}-\left(\dfrac{1}{3}-\dfrac{5}{4}\right)-\left(\dfrac{2}{7}+\dfrac{1}{3}\right)\right]\right\}\)
\(B=\dfrac{3}{2}-\dfrac{2}{21}-\left\{\dfrac{7}{12}-\left[\dfrac{15}{21}-\left(-\dfrac{11}{12}\right)-\dfrac{13}{21}\right]\right\}\)
\(B=\dfrac{3}{2}-\dfrac{2}{21}-\left\{\dfrac{7}{12}-\dfrac{85}{84}\right\}\)
\(B=\dfrac{3}{2}-\dfrac{2}{21}-\left(-\dfrac{3}{7}\right)\)
\(B=\dfrac{11}{6}\)
\(a,MSC:45\\ \dfrac{4}{9}=\dfrac{20}{45};\dfrac{3}{5}=\dfrac{27}{45}\\ b,MSC:21\\ \dfrac{1}{7}=\dfrac{3}{21};\dfrac{2}{21}\left(giữ.nguyên\right)\\ c,MSC:24\\ \dfrac{5}{6}=\dfrac{20}{24};\dfrac{7}{8}=\dfrac{21}{24}\\ d,MSC:200\\ \dfrac{87}{40}=\dfrac{435}{200};\dfrac{153}{200}\left(giữ.nguyên\right)\\ e,MSC:24\\ \dfrac{9}{8}=\dfrac{27}{24};\dfrac{5}{3}=\dfrac{40}{24};\dfrac{1}{2}=\dfrac{12}{24}\)
A ) 4 /9 và 3/5 = 20/45 và 27/45
b ) 1/7 và 2/21 = 3/21 và 2/21
c ) 5/6 và 7/8 = 40/48 và 42/48
d ) 87/40 và 153/200 = 435/200 và 153/200
e) 9/8 ; 5/3 và 1/2 = 37/24 ; 40/24 và 12/24
1, Ta có :
\(x+\frac{3}{5}=\frac{4}{7}\div\frac{8}{21}\)
\(x+\frac{3}{5}=\frac{4}{7}\times\frac{21}{8}\)
\(x+\frac{3}{5}=\frac{3}{2}\)
\(x=\frac{3}{2}-\frac{3}{5}\)
\(x=\frac{15}{10}-\frac{6}{10}\)
\(x=\frac{9}{10}\)
Vậy x = \(\frac{9}{10}\)
2, Ta có :
\(\frac{2}{3}+\frac{3}{4}\div x=-\frac{1}{6}\)
\(\frac{3}{4}\div x=-\frac{1}{6}-\frac{2}{3}\)
\(\frac{3}{4}\div x=-\frac{1}{6}-\frac{4}{6}\)
\(\frac{3}{4}\div x=-\frac{5}{6}\)
\(x=\frac{3}{4}\div\left(-\frac{5}{6}\right)\)
\(x=\frac{3}{4}\times\left(-\frac{6}{5}\right)\)
\(x=-\frac{9}{10}\)
Vậy x = \(-\frac{9}{10}\)
Ta có : (x + 3) + (x + 5) + (x + 7) + ..... + (x + 21) = 335
=> x + x + x + x + (3 + 5 + 7 + ..... + 21) = 335
=> 10x + 120 = 335
=> 10x = 335 - 120
=> 10x = 215
=> x = 21,5
ta có : (x + 3) + (x + 5) + (x + 7) + ..... + (x + 21) = 335
<=> x + x + x + x + (3 + 5 + 7 + ..... + 21) = 335
<=> 10x + 120 = 335
=> 10x = 335 - 120
=> 10x = 215
vậy x = 21,5
a. (21 - 1) x (21 - 2) x (21 - 3) x ... x (21 - 21)
= 20 x 19 x 18 x ... x 0
= 0
b. 3 x 27 x 8 + 4 x 35 x 6 + 2 x 38 x 12
= (3 x 8) x 27 + (4 x 6) x 35 + (2 x 12) x 38
= 24 x 27 + 24 x 35 + 24 x 38
= 24 x (27 + 35 + 38)
= 24 x100
= 2400
c. A = (1001 + 1002 + 1003 +... + 2009) x (360 x 87 - 360 x 32 - 360 x 55)
= (1001 + 1002 + 1003 + ... + 2009) x [360 x (87 - 32 - 55)]
= (1001 + 1002 + 1003 + ... + 2009) x (360 x 0)
= (1001 + 1002 + 1003 + ... + 2009) x 0
= 0
tính nhanh à bn
\(\frac{3}{7}+\frac{2}{21}-\frac{3}{14}\)
\(=\frac{11}{21}-\frac{3}{14}=\frac{13}{42}\)
\(\frac{5}{4}-\frac{5}{12}+\frac{3}{8}\)
\(=\frac{5}{6}+\frac{3}{8}=\frac{29}{24}\)
\(\frac{7}{12}.\frac{8}{21}:\frac{2}{3}\)
\(=\frac{2}{9}:\frac{2}{3}=\frac{1}{3}\)