tính
a,100-[116-(13-52)]
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\(\frac{30}{13}\)× \(\frac{52}{29}\)×\(\frac{116}{240}\)= \(\frac{3×10×13×4×29×4}{13×29×2×3×4×10}\)( gạch số giống nhau đi )=\(\frac{4}{2}\)= 2
a) A= 100 - 116 : 4
=100-29
=71
b) B= 100 - [ 116 - (13 - 5)2]
=100-[116-82]
=100-(116-64)
=100-52
=48
c) C= |- 65| + (- 42) + |65|
= 65+(-42)+65
= 88
Bài 1:
\(\dfrac{-13}{38}\) và \(\dfrac{29}{-88}\)
\(\dfrac{-13}{38}=\dfrac{-13.29}{38.29}=\dfrac{-377}{1102}\)
\(\dfrac{29}{-88}=\dfrac{-29}{88}=\dfrac{-29.13}{88.13}=\dfrac{-377}{1144}\)
Vì \(\dfrac{-377}{1102}< \dfrac{-377}{1144}\) nên \(\dfrac{-13}{38}< \dfrac{29}{-88}\)
\(\dfrac{-18}{31}\) và \(\dfrac{-1818}{3131}\)
\(\dfrac{-18}{31}\)
\(\dfrac{-1818}{3131}=\dfrac{-1818:101}{3131:101}=\dfrac{-18}{31}\)
Vì \(\dfrac{-18}{31}=\dfrac{-18}{31}\) nên \(\dfrac{-18}{31}=\dfrac{-1818}{3131}\)
Bài 2:
a) \(\dfrac{-1}{39}+\dfrac{-1}{52}=\dfrac{-4}{156}+\dfrac{-3}{156}=\dfrac{-4+-3}{156}=\dfrac{-7}{156}\)
b) \(\dfrac{-6}{9}+\dfrac{-12}{16}=\dfrac{-2}{3}+\dfrac{-3}{4}=\dfrac{-8}{12}+\dfrac{-9}{12}=\dfrac{-17}{12}\)
\(13\cdot16+13\cdot\left(-116\right)+17\cdot\left(-100\right)\)
\(=13\left(16+-116\right)+17\cdot\left(-100\right)\)
\(=13\cdot\left(-100\right)+17\cdot\left(-100\right)\)
\(=\left(-100\right)\cdot\left(13+17\right)=30\cdot\left(-100\right)=-3000\)
13.16+13.(-116)+17.(-100)
=13.(-116+16)+17.(-100)
=13.(-100)+17.(-100)
=(-100).(13+17)
=-100.30
=(-3000)
a. 10/13 + 9/16
=160/208+117/208
=277/208
7/90 + 123/270
=7/90+41/90
=48/90
=8/15
b. 19/21 - 5/12
=76/84-35/84
=41/84
90/100 - 25/40
=9/10-25/40
=36/40-25/40
=11/40
\(100-\left(116-\left(13-5^2\right)\right)=100-\left(116-\left(-12\right)\right)\)
\(=100-\left(116+12\right)=100-128=-28\)
100-[116-(13-52)]
=100-[116-(13-25)]
=100-(116-13+25)
=100-(103+25)
=100-128
=-28
\(100-\left[116-\left(13-5\right)^2\right]\)
\(=100-\left(116-8^2\right)\)
\(=100-\left(116-64\right)\)
\(=100-52\)
\(=48\)
a) 25 = 2.2.2.2.2 = 32
b) 33 = 3.3.3 = 27
c) 52 = 5.5 =25
d) 109 =10.10.10.10.10.10.10.10.10 = 1 000 000 000
a: =6^2-15*2
=36-30=6
b: =3*25+15*4-3
=72+60
=132
c: =25*2+5
=50+5
=55
d: =5+12=17
e: =7^2(15-5)=49*10=490
f: =4^3*125-125:25
=1000-5
=995
\(100-\)\(\left[116-\left(13-5^2\right)\right]\)
=\(100-\left[116-\left(13-25\right)\right]\)
=\(100-\left[116-\left(-12\right)\right]\)
=\(100-\left(116+12\right)\)
=\(100-128\)
=\(-28\)
= 100 - [116 - (-12)]
=100-128
= (-28)