15 x 2 + 15 x 3 - 15 + 15 x 5
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\(1,\frac{2}{3}+\frac{4}{9}+\frac{1}{5}+\frac{2}{15}+\frac{3}{2}-\frac{17}{18}\)
\(< =>\frac{4}{9}+\frac{3}{2}+\left(\frac{2}{3}+\frac{1}{5}+\frac{2}{15}\right)-\frac{17}{18}\)
\(< =>\frac{8}{18}+\frac{27}{18}+\left(\frac{10}{15}+\frac{3}{15}+\frac{2}{15}\right)-\frac{17}{18}\)
\(< =>\frac{35}{18}+1-\frac{17}{18}\)
\(< =>\frac{53}{18}-\frac{17}{18}\)
\(< =>2\)
\(2,\frac{13}{28}\cdot\frac{5}{12}-\frac{5}{28}\cdot\frac{1}{12}\)
\(< =>\left(\frac{13}{28}-\frac{5}{28}\right)\cdot\left(\frac{5}{12}-\frac{1}{12}\right)\)
\(< =>\frac{2}{7}\cdot\frac{1}{3}\)
\(< =>\frac{2}{21}\)
\(3,\frac{19}{4}\cdot\frac{15}{23}-\frac{15}{4}\cdot\frac{7}{23}+\frac{15}{4}\cdot\frac{11}{23}\)
\(< =>\frac{285}{92}-\frac{105}{92}+\frac{165}{92}\)
\(< =>\frac{15}{4}\)
\(a,\left(3416+6584\right)+1025=11025\\ b,15\times\left(2+3+5\right)=150\)
\(a,3416+1025+6584\\ =\left(3416+6584\right)+1025\\ =10000+1025\\ =11025\\ b,15\times2+15\times3+15\times5\\ =15\times\left(2+3+5\right)\\ =15\times10\\ =150\)
a,3416+1025+6584=(3416+6584)+1025=10000+1025=11025b,15×2+15×3+15×5=15×(2+3+5)=15×10=150
\(x+\dfrac{2}{3}=\dfrac{15}{6}\times\dfrac{9}{5}\)
\(x+\dfrac{2}{3}=\dfrac{5}{3}\times\dfrac{9}{5}\)
\(x+\dfrac{2}{3}=\dfrac{9}{3}\)
\(x=\dfrac{9}{3}-\dfrac{2}{3}\)
\(x=\dfrac{7}{3}\)
______________
\(\dfrac{15}{2}-x=\dfrac{7}{4}+\dfrac{5}{2}\)
\(\dfrac{15}{2}-x=\dfrac{7}{4}+\dfrac{10}{4}\)
\(\dfrac{15}{2}-x=\dfrac{17}{4}\)
\(x=\dfrac{15}{2}-\dfrac{17}{4}\)
\(x=\dfrac{30}{4}-\dfrac{17}{4}\)
\(x=\dfrac{13}{4}\)
a)
Ta có : ( 1 + 2 + 3 + ... + 99)
Số số hạng là: ( 99 - 1 ) : 1 + 1 = 100
Tổng là: ( 99 + 1 ) x 100 : 2 = 5000
=> 5000 x ( 13 - 12 - 1 ) x 15
=> 5000 x 10 x 15
=> 50000 x 15
=> 750000
Ko muốn vt nx :))
\(a,3\left(x-5\right)-4\left(x-3\right)=-12\)
\(\Leftrightarrow3x-15-4x+12=-12\)
\(\Leftrightarrow-x=-9\)
\(\Leftrightarrow x=9\)
Vậy x=9
15 x 2 + 15 x 3 - 15 + 15 x 5=30+45+75-15=135
15 x 2 + 15 x 3 - 15 + 15 x 5
= 15 x 2 + 15 x 3 - 15 x 1 + 15 x 5
= 15 x (2 + 3 - 1 + 5)
= 15 x 9
= 135