Tìm x
a, (x + 5)3 . 2 = 432
b, x3 + 52 . 32 = 252
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a, 2 3 x + 5 2 x = 2 5 2 + 2 3 - 33
8x+25x = 33
33x = 33
x = 1
b, 260 : x + 4 = 5 2 3 + 5 - 3 3 2 + 2 2
260:(x+4) = 5.13–3.13
x+4 = 260:26
x+4 = 10
x = 6
c, 720 : [ 41 - 2 x - 5 ] = 2 3 . 5
41–(2x–5) = 720:40
2x–5 = 41–18
2x = 28
x = 14
d, 3 2 - 2 x - 12 + 35 = 5 2 + 279 : 3 2
7(x–12)+35 = 56
7(x–12) = 21
x–12 = 3
x = 15
\(5x+2x\cdot\left(2^3\cdot5-3^2\cdot4\right)+5^2=4^3\)
\(\Rightarrow5x+2x\cdot\left(8\cdot5-9\cdot4\right)+25=64\)
\(\Rightarrow5x+2x\cdot\left(40-36\right)=64-25\)
\(\Rightarrow5x+2x\cdot4=39\)
\(\Rightarrow5x+8x=39\)
\(\Rightarrow x\cdot\left(5+8\right)=39\)
\(\Rightarrow13x=39\)
\(\Rightarrow x=\dfrac{39}{13}\)
\(\Rightarrow x=3\)
Vậy: ...
T a c ó 4 3 x - 5 2 - 9 9 x 2 - 25 2 = 0 4 3 x - 5 2 - 9 3 x 2 - 5 2 2 = 0 4 3 x - 5 2 - 9 3 x - 5 3 x + 5 2 = 0 4 3 x - 5 2 - 9 3 x - 5 2 3 x + 5 2 = 0 3 x - 5 2 4 - 3 3 x + 5 2 = 0 3 x - 5 2 4 - 3 3 x + 5 2 = 0 3 x - 5 2 2 2 - 9 x + 15 2 = 0 3 x - 5 2 2 + 9 x + 15 2 – 9 x – 15 = 0 3 x - 5 2 9 x + 17 - 9 x – 13 = 0
Đáp án cần chọn là: C
a) 2(x-51)=2.23+20 b)32(x+4)-52=5.52
2(x-51)=2.8+20 9(x+4)-25=125
2(x-51)=36 9(x+4)=125+25
x-51=36:2 9(x+4)=150
x-51=18 x+4= 150:9
x=18+51 x+4=50/9
x=69 x=14/9
Vậy:x=69 Vậy:x=14/9
Mik sai thì thôi nha!!!!
a) 2(x-51)=2.23+20 b)32(x+4)-52=5.52
2(x-51)=2.8+20 9(x+4)-25=125
2(x-51)=36 9(x+4)=125+25
x-51=36:2 9(x+4)=150
x-51=18 x+4= 150:9
x=18+51 x+4=50/9
x=69 x=4/9
Vậy:x=69 Vậy:x=4/9
4 2 . 25 2 + 32. 125 2 3 . 5 2 = 2 4 .5 4 + 2 5 .5 3 2 3 .5 2 = 2 4 .5 3 5 + 2 2 3 .5 2 = 2.5.7 = 70
a: x-56:4=16
nên x-14=16
hay x=30
b: \(101+\left(36-4x\right)=105\)
\(\Leftrightarrow36-4x=4\)
hay x=8
Vì a: x-56:4=16
=>x-14=16
Hay:x=30
Vì b: 101+(36−4x)=105101+(36−4x)=105
⇔36−4x=4⇔36−4x=4
Hay:x=8
Vậy x={30:8}
Nếu sai thì thui nhá,đừng chửi mình!
\(a,\Leftrightarrow\left(x-5\right)\left(2x+3\right)=0\\ \Leftrightarrow\left[{}\begin{matrix}x=5\\x=-\dfrac{3}{2}\end{matrix}\right.\\ b,\Leftrightarrow\left(x-4\right)\left(x+4\right)=0\\ \Leftrightarrow\left[{}\begin{matrix}x=4\\x=-4\end{matrix}\right.\)
\(a,\left(x-8\right)\left(x^3+8\right)=0\\ \Leftrightarrow\left[{}\begin{matrix}x-8=0\\x^3+8=0\end{matrix}\right.\\ \Leftrightarrow\left[{}\begin{matrix}x=8\\x^3=-8\end{matrix}\right.\\ \Leftrightarrow\left[{}\begin{matrix}x=8\\x=-2\end{matrix}\right.\)
\(b,\left(4x-3\right)-\left(x+5\right)=3\left(10-x\right)\\ \Leftrightarrow4x-3-x-5=30-3x\\ \Leftrightarrow3x-8-30+3x=0\\ \Leftrightarrow6x-38=0\\ \Leftrightarrow x=\dfrac{19}{3}\)
TK
`a.(x-8)(x+8)=0`
`⇔³{x−8=0x³+8=2 `
`⇔³³{x=8x³=−2³ `
`⇔{x=8x=−2`
Vậy ` x = 8;-2`
`b. ( 4 x − 3 ) − ( x + 5 ) = 3 . ( 10 − x )`
`⇔ 4 x − 3 − x − 5 = 30 − 3 x`
`⇔ 3 x − 8 = 30 − 3 x`
`⇔ 3 x + 3 x = 30 + 8`
`⇔ 6 x = 38`
`⇔ x = 19/ 3`
Vậy ` x = 19/ 3`
(x + 5)3 . 2 = 432
(x + 5)3 = 432 : 2
(x + 5)3 = 216
x + 5 = \(\sqrt[3]{216}\)
x + 5 = 6
x = 6 - 5
x = 1
***
x3 + 52 . 32 = 252
x3 + 25 . 9 = 252
x3 + 225 = 252
x3 = 252 - 225
x3 = 27
x3 = \(\sqrt[3]{27}\)
x = 3
a) (x + 5)3.2 = 432
=> (x + 5)3 = 432 : 2
=> (x + 5)3 = 216 = 63
=> x + 5 = 6
=> x = 6 - 5
=> x = 1
b) x3 + 52.32 = 252
=> x3 + 25.9 = 252
=> x3 + 225 = 252
=> x3 = 252 - 225
=> x3 = 27 = 33
=> x = 3