Tìm x biết 4x+720/x = 1/2
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\(\left(x+\frac{2}{3}\right)\left(\frac{5}{4}-2x\right)>0\)
th1 :
\(\hept{\begin{cases}x+\frac{2}{3}>0\\\frac{5}{4}-2x>0\end{cases}\Rightarrow\hept{\begin{cases}x>-\frac{2}{3}\\-2x>-\frac{5}{4}\end{cases}\Rightarrow}\hept{\begin{cases}x>-\frac{2}{3}\\x>\frac{5}{8}\end{cases}\Rightarrow}x>\frac{5}{8}}\)
th2 :
\(\hept{\begin{cases}x+\frac{2}{3}< 0\\\frac{5}{4}-2x< 0\end{cases}\Rightarrow\hept{\begin{cases}x< -\frac{2}{3}\\-2x< -\frac{5}{4}\end{cases}\Rightarrow}\hept{\begin{cases}x< -\frac{2}{3}\\x< \frac{5}{8}\end{cases}\Rightarrow}x< -\frac{2}{3}}\)
vậy_
720 : [41 - (2x - 5)] = 8 . 5
=> 720 : [41 - (2x - 5)] = 40
=> 41 - (2x - 5) = 720 : 40
=> 41 - (2x - 5) = 18
=> 2x - 5 = 41 - 18
=> 2x - 5 = 23
=> 2x = 23 + 5
=> 2x = 28
=> x = 28 : 2
=> x = 14
Vậy x = 14
1 + 2 + 3 + 4 + ... + (x - 1) + x = 78
có x số hạng
=> (x + 1) . x : 2 = 78
=> (x + 1) . x = 78 . 2
=> (x + 1) . x = 156
=> (x + 1) . x = 13 . 12
=> x = 12
Vậy x = 12
90/17
1111111111111111111111111111111111111111111111111111111111111111111111111111111
\(\frac{4x+720}{70\times x}=\frac{1}{2}\Rightarrow2\left(4x+720\right)=70x\)
<=>8x+1440=70x
=>8x-70x=0-1440
=>-62x=-1440
=>x=\(\frac{720}{31}\)
Giải:
a) \(70.\dfrac{4x+720}{x}=\dfrac{1}{2}\)
\(\Leftrightarrow\dfrac{280x+50400}{x}=\dfrac{1}{2}\)
\(\Leftrightarrow2\left(280x+50400\right)=x\)
\(\Leftrightarrow560x+100800=x\)
\(\Leftrightarrow560x-x=-100800\)
\(\Leftrightarrow549x=-100800\)
\(\Leftrightarrow x=-\dfrac{11200}{61}\)
Vậy ...
b) \(x^2+5x< 0\)
\(\Leftrightarrow x\left(x+5\right)< 0\)
\(\Leftrightarrow\left[{}\begin{matrix}\left\{{}\begin{matrix}x< 0\\x+5>0\end{matrix}\right.\\\left\{{}\begin{matrix}x>0\\x+5< 0\end{matrix}\right.\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}\left\{{}\begin{matrix}x< 0\\x>-5\end{matrix}\right.\\\left\{{}\begin{matrix}x>0\\x< -5\end{matrix}\right.\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}0>x>-5\\x\in\varnothing\end{matrix}\right.\)
Vậy ...
a, 128 – 3(x+4) = 23
b, 12 x - 4 3 . 8 3 = 4 . 8 4
c, [(4x+28).3+55]:5 = 35
d, 720:[41 – (2x – 5)] = 2 3 . 5
Đk : x khác 0
=> 35/2x + 720/x = 1/2
=> 35+1440/2x = 1/2
=> 1475/2x = 1/2
=> 1475 = 1/2 . 2x = x
Vậy x = 1475
k mk nha
\(\Leftrightarrow8x+1440=x\)
=>7x=-1440
hay x=-1440/7