Question

[Lê Thế Dũng]

so sánh:

\(C=1.3.5.7...99\)  và\(\frac{51}{2}.\frac{52}{2}.\frac{53}{2}....\frac{100}{2}\)

Answer 1

[Nhók Bướq Bỉnh]

C=1.3.5.7...99
=>2.4.6...100.C=1.2.3...100
=>C = (1.2.3....100) / (2.4.6...100)= (1.2.3...50).(51.52...100) / [(2.1)(2.2).(2.3)...(2.50)]
C=(1.2.3...50).(51.52...100) /[2^50.(1.2.3...50)] =(51.52...100)/2^50 =51/2.52/2.53/2...100/2 =D
VAy C=D