tìm x
{28.15-34.12}x:6+8=24
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8.3x+3.2x-6x=24
=>6x-8.3x-(3.2x-24)=0
=>3x(2x-8)-3(2x-8)=0
=>(2x-8)(3x-3)=0
=>\(\orbr{\begin{cases}2^x-8=0\\3^x-3=0\end{cases}\Rightarrow\orbr{\begin{cases}2^x=8\\3^x=3\end{cases}\Rightarrow}\orbr{\begin{cases}2^x=2^3\\3^x=3^1\end{cases}\Rightarrow}\orbr{\begin{cases}x=3\\x=1\end{cases}}}\)
Vậy x=3 hoặc x=1
x - 24 = 54
=> x = 54 + 24
=> x = 78
Vậy x = 78
8 - x = 6
=> x = 8 - 6
=> x = 2
Vậy x = 2
24 + x = 94
=> x = 94 - 24
=> x = 70
Vậy x = 70
77 + x = 90
=> x = 90 - 77
=> x = 13
Vậy x = 13
Bài làm
***x-24=54
x=54+24
x=78
***8-x=6
X=8-6
x=2
***24+x=94
x=94-24
x=70
***77+x=90
x=90-77
x=13
a, \(\frac{3}{8}=\frac{6}{x}\Rightarrow3x=6.8\Rightarrow3x=48\Rightarrow x=\frac{48}{3}=16\)
b, \(\frac{1}{8}=\frac{x}{27}\Rightarrow8x=27\Rightarrow x=\frac{27}{8}\)
c, \(\frac{4}{x}=\frac{6}{8}\Rightarrow6x=4.8\Rightarrow6x=32\Rightarrow x=\frac{32}{6}=\frac{16}{3}\)
d, \(\frac{x}{6}=\frac{5}{24}\Rightarrow24x=30\Rightarrow x=\frac{30}{24}=\frac{5}{4}\)
a: \(\dfrac{-4}{8}=\dfrac{x}{-10}=\dfrac{-7}{y}=\dfrac{z}{-24}\)
=>\(\dfrac{x}{-10}=\dfrac{-7}{y}=\dfrac{z}{-24}=\dfrac{-1}{2}\)
=>\(\left\{{}\begin{matrix}x=\left(-10\right)\cdot\dfrac{\left(-1\right)}{2}=5\\y=\dfrac{-7\cdot2}{-1}=14\\z=\dfrac{-24\cdot\left(-1\right)}{2}=\dfrac{24}{2}=12\end{matrix}\right.\)
b: \(\dfrac{-3}{6}=\dfrac{x}{-2}=\dfrac{-18}{y}=\dfrac{-z}{24}\)
=>\(\dfrac{x}{-2}=\dfrac{-18}{y}=\dfrac{z}{-24}=\dfrac{-1}{2}\)
=>\(\dfrac{x}{2}=\dfrac{18}{y}=\dfrac{z}{24}=\dfrac{1}{2}\)
=>\(x=2\cdot\dfrac{1}{2}=1;y=18\cdot\dfrac{2}{1}=36;z=\dfrac{24}{2}=12\)
\(a,\Rightarrow\dfrac{1}{2}x=-2\Rightarrow x=-4\\ b,3x=5y\Rightarrow\dfrac{x}{5}=\dfrac{y}{3}=\dfrac{x+y}{5+3}=\dfrac{24}{8}=3\\ \Rightarrow\left\{{}\begin{matrix}x=15\\y=9\end{matrix}\right.\)
\(\left(28.15-34.12\right)x:6+8=24\)
\(12x:6+8=24\)
\(12x:6=32\)
\(12x=192\)
\(x=16\)