2x2=16
3x3=21
4x4=4
vậy:1x1=?
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S5=5x5-(4x4-(3x3-(2x2-1x1)))
S2011=2001x2001-(2000x2000-(1999x1999-(....)))
a) 1+1x1−1x1+1x1−1x =(1+1x):(1−1x)=x+1x:x−1x=x+1x.xx−1=x+1x−1=(1+1x):(1−1x)=x+1x:x−1x=x+1x.xx−1=x+1x−1
b) 1−2x+11−x2−2x2−11−2x+11−x2−2x2−1 =(1−2x+1):(1−x2−2x2−1)=(1−2x+1):(1−x2−2x2−1)
=x+1−2x+1:x2−1−(x2−2)x2−1=x+1−2x+1:x2−1−(x2−2)x2−1
=x−1x+1:x2−1−x2+2x2−1=x−1x+1:1(x−1)(x+1)=x−1x+1:x2−1−x2+2x2−1=x−1x+1:1(x−1)(x+1)
=x−1x+1.(x−1)(x+1)1=(x−1)2=x−1x+1.(x−1)(x+1)1=(x−1)2.
a) 1+1x1−1x1+1x1−1x =(1+1x):(1−1x)=x+1x:x−1x=x+1x.xx−1=x+1x−1=(1+1x):(1−1x)=x+1x:x−1x=x+1x.xx−1=x+1x−1 b) 1−2x+11−x2−2x2−11−2x+11−x2−2x2−1 =(1−2x+1):(1−x2−2x2−1)=(1−2x+1):(1−x2−2x2−1) =x+1−2x+1:x2−1−(x2−2)x2−1=x+1−2x+1:x2−1−(x2−2)x2−1 =x−1x+1:x2−1−x2+2x2−1=x−1x+1:1(x−1)(x+1)=x−1x+1:x2−1−x2+2x2−1=x−1x+1:1(x−1)(x+1) =x−1x+1.(x−1)(x+1)1=(x−1)2=x−1x+1.(x−1)(x+1)1=(x−1)2.
= 1.1! + (3 - 1).2! + (4 - 1).3! + ...+ (16 - 1).15!
= 1! + 3.2! - 2! + 4.3! - 3! + ...+16.15! - 15!
= 1! + 3! - 2! + 4! - 3! + ...+16! - 15!
= 1! + (3! + 4! + ...+ 16!) - (2! + 3! + ...+ 15!)
= 1 + 16! - 2! = ....
Ta có: 1x1!+2x2!+......+15x15!
= 1.1! + (3 - 1).2! + (4 - 1).3! + ...+ (16 - 1).15!
= 1! + 3.2! - 2! + 4.3! - 3! + ...+16.15! - 15!
= 1! + 3! - 2! + 4! - 3! + ...+16! - 15!
= 1! + (3! + 4! + ...+ 16!) - (2! + 3! + ...+ 15!)
= 1 + 16! - 2!
Vậy ...............
hok tốt
1x1=13