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(3x-1)2-(2x-1)(2x+1)
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TA
18 tháng 6 2021
`-3x(2x+1)+(2x-1)(3x+2)`
`=-6x^2-3x+6x^2+4x-3x-2`
`=(6x^2-6x^2)+(4x-3x-3x)-2`
`=-2x-2`
13 tháng 8 2021
Ta có: \(-3x\left(2x+1\right)+\left(2x-1\right)\left(3x+2\right)\)
\(=-6x^2-3x+6x^2+4x-3x-2\)
\(=-2x-2\)
ND
1
MT
9 tháng 7 2015
(2x+1)*(2x-1)-(3x+1)2-(3x-2)*(5-2x)
=4x2-1-(9x2+6x+1)-(15x-6x2-10+4x)
=4x2-1-9x2-6x-1-15x+6x2+10-4x
=x2-25x+8
5 tháng 8 2021
\(A=2x^2\left(3x+4\right)\left(3x-4\right)-\dfrac{9}{2}\left(2x^2+1\right)\left(2x^2-1\right)\)
\(=2x^2\left(9x^2-16\right)-\dfrac{9}{2}\left(4x^4-1\right)\)
\(18x^4-32x^2-18x^4+\dfrac{9}{2}\\ =-32x^2+\dfrac{9}{2}\)
5 tháng 8 2021
Ta có: \(A=2x^2\left(3x+4\right)\left(3x-4\right)-\dfrac{9}{2}\left(2x^2+1\right)\left(2x^2-1\right)\)
\(=2x^2\left(9x^2-16\right)-\dfrac{9}{2}\left(4x^4-1\right)\)
\(=18x^4-36x^2-18x^4+\dfrac{9}{2}\)
\(=-36x^2+\dfrac{9}{2}\)
PT
1
CM
14 tháng 12 2017
(2x + 1)2 + (3x – 1)2 + 2(2x + 1)(3x – 1)
= (2x + 1)2 + 2.(2x + 1)(3x – 1) + (3x – 1)2
= [(2x + 1) + (3x – 1)]2
= (2x + 1 + 3x – 1)2
= (5x)2
= 25x2
NT
1
PN
3 tháng 11 2015
\(\left(3x+1\right)^2+2\left(3x+1\right)\left(2x-1\right)+\left(2x-1\right)^2=\left(3x+1+2x-1\right)^2=25x^2\)
27 tháng 12 2020
a) Ta có: \(\dfrac{2x^2-2x}{x-1}\)
\(=\dfrac{2x\left(x-1\right)}{x-1}\)
=2x
b) Ta có: \(\dfrac{x^2+2x+1}{3x^2+3x}\)
\(=\dfrac{\left(x+1\right)^2}{3x\left(x+1\right)}\)
\(=\dfrac{x+1}{3x}\)
c) Ta có: \(\dfrac{x}{3x-3}+\dfrac{1}{x^2-1}\)
\(=\dfrac{x}{3\left(x-1\right)}+\dfrac{1}{\left(x-1\right)\left(x+1\right)}\)
\(=\dfrac{x+1+3}{3\left(x-1\right)\left(x+1\right)}\)
\(=\dfrac{x+4}{3x^2-3}\)
4 tháng 7 2016
\(\left(2x+1\right)^2+\left(3x-1\right)^2+2\left(2x+1\right)\left(3x-1\right)\)
\(=\left(2x+1\right)^2+2\left(2x+1\right)\left(3x-1\right)+\left(3x-1\right)^2\)
\(=\left[\left(2x+1\right)+\left(3x-1\right)\right]^2\)
25 tháng 7 2021
Ta có: \(2x\left(3x-1\right)-\left(2x+1\right)\left(x-3\right)\)
\(=6x^2-2x-\left(2x^2-6x+x-3\right)\)
\(=6x^2-2x-2x^2+5x+3\)
\(=4x^2+3x+3\)
Ta có: \(3\left(x^2-2x\right)-\left(4x+2\right)\left(x-1\right)\)
\(=3x^2-6x-\left(4x^2-4x+2x-2\right)\)
\(=3x^2-6x-4x^2+2x+2\)
\(=-x^2-4x+2\)
25 tháng 7 2021
\(2x\left(3x-1\right)-\left(2x+1\right)\left(x-3\right)=6x^2-2x-2x^2+5x+3=4x^2+3x+3\)
\(3\left(x^2-2x\right)-\left(4x+2\right)\left(x-1\right)=3x^2-6x-4x^2+2x-2=-x^2-4x-2\)
1 tháng 8 2021
A = \(\left(3x-1\right)^2+2\left(3x-1\right)\left(2x+1\right)+\left(2x+1\right)^2\)
A = \(\left(3x-1+2x+1\right)^2\)
HN
1 tháng 8 2021
A)
<=>(3x)^2−2×3x+1+2(3x−1)(2x+1)+(2x+1)^2
<=>(3x)^2−2×3x+1+(6x−2)(2x+1)+(2x+1)^2
<=>(3x)^2−2×3x+1+12x^2+6x−4x−2+(2x+1)^2
<=>(3x)^2−2×3x+1+12x^2+6x−4x−2+(2x)^2+2×2x+1
<=>32x^2−2×3x+1+12x^2+6x−4x−2+(2x)^2+2×2x+1
<=>9x^2−2×3x+1+12x^2+6x−4x−2+(2x)^2+2×2x+1
<=>9x^2−2×3x+1+12x^2+6x−4x−2+2^2x^2+2×2x+1
<=>9x^2−2×3x+1+12x^2+6x−4x−2+4x^2+2×2x+1
<=>9x^2−6x+1+12x^2+6x−4x−2+4x^2+2×2x+1
<=>9x^2−6x+1+12x^2+6x−4x−2+4x^2+4x+1
<=>(9x^2+12x^2+4x^2)+(−6x+6x−4x+4x)+(1−2+1)
<=> 25x^2
B)
<=>2x(4x^2−6x+9)+3(4x^2−6x+9)+8(1−x)(1+x+x^2)
<=>8x^3−12x^2+18x+3(4x^2−6x+9)+8(1−x)(1+x+x^2)
<=>8x^3−12x^2+18x+12x^2−18x+27+8(1−x)(1+x+x^2)
<=>8x^3−12x^2+18x+12x^2−18x+27+(8−8x)(1+x+x^2)
<=>8x^3−12x^2+18x+12x^2−18x+27+8(1+x+x^2)−8x(1+x+x^2)
<=>8x^3−12x^2+18x+12x^2−18x+27+8+8x+8x^2−8x(1+x+x^2)
<=>8x^3−12x^2+18x+12x^2−18x+27+8+8x+8x^2−(8x+8x2+8x^3)
<=>8x^3−12x^2+18x+12x^2−18x+27+8+8x+8x^2−8x−8x^2−8x^3
<=>(8x^3−8x^3)+(−12x^2+12x^2+8x^2−8x^2)+(18x−18x+8x−8x)+(27+8)
<=> 35
( 3x - 1 )2 - ( 2x - 1 )( 2x + 1 ) = 9x2 - 6x + 1 - ( 4x2 - 1 )
= 9x2 - 6x + 1 - 4x2 + 1 = 5x2 - 6x + 2