Giúp mk với!!!!!!!!!!!!!!!
\(\left|-x-\frac{2}{5}\right|+\frac{1}{2}=3,5\) Tìm x nha
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\(3\left(x-\frac{1}{2}\right)-5\left(x+\frac{3}{5}\right)=-x+\frac{1}{5}\)
\(3x-\frac{3}{2}-5x-3=-x+\frac{1}{5}\)
\(3x-5x+x=\frac{1}{5}+3+\frac{3}{2}\)
\(-x=\frac{47}{10}\)
\(x=\frac{-47}{10}\)
\(\frac{2.\left(x-5\right)}{-9}=\frac{6}{\left(x-5\right)^2}.\left(-1\right)\)
\(\frac{2.\left(x-5\right)}{-9}=\frac{-6}{\left(x-5\right)^2}\)
\(2.\left(x-5\right).\left(x-5\right)^2=\left(-9\right).\left(-6\right)\)(nhân chéo)
\(2.\left(x-5\right).\left(x-5\right)^2=54\)
\(\left(x-5\right).\left(x-5\right)^2=54:2=27\)
\(\Rightarrow27⋮x-5\)
\(x-5\inƯ\left(27\right)\)
\(x-5\in\left\{-27;-9;-3;-1;1;3;9;27\right\}\)
\(x\in\left\{-22;-4;2;4;6;8;14;32\right\}\)
a) \(\left|x+\frac{1}{2}\right|=\left|2x+3\right|\)
\(\Rightarrow\left[\begin{array}{nghiempt}x+\frac{1}{2}=2x+3\\x+\frac{1}{2}=-\left(2x+3\right)\end{array}\right.\)\(\Rightarrow\left[\begin{array}{nghiempt}2x-x=\frac{1}{2}-3\\x+\frac{1}{2}=-2x-3\end{array}\right.\)
\(\Rightarrow\left[\begin{array}{nghiempt}x=\frac{-5}{2}\\x+2x=-3-\frac{1}{2}\end{array}\right.\)\(\Rightarrow\left[\begin{array}{nghiempt}x=\frac{-5}{2}\\3x=\frac{-7}{2}\end{array}\right.\)\(\Rightarrow\left[\begin{array}{nghiempt}x=\frac{-5}{2}\\x=\frac{-7}{6}\end{array}\right.\)
Vậy \(x\in\left\{\frac{-5}{2};\frac{-7}{6}\right\}\)
\(\left|x+\frac{1}{2}\right|=\left|2x+3\right|\)
\(Ta\) \(có\): \(x+\frac{1}{2}=2x+3\)
\(x+\frac{1}{2}=x+x+3\\\)
\(x+\frac{1}{2}=x+\left(x+3\right)\)
\(\Rightarrow\frac{1}{2}=x+3\)
\(\Rightarrow x=\frac{1}{2}-3\)
\(\Rightarrow x=-\frac{5}{2}\)
Vậy \(x=-\frac{5}{2}\)
b, \(\left|x+\frac{1}{5}\right|+\left|x+\frac{2}{5}\right|+\left|x+1\frac{2}{5}\right|=4x\)
\(Ta\) \(có\)
\(x+\frac{1}{5}+x+\frac{2}{5}+x+1\frac{2}{5}\)\(=4x\)
\(3x+\left(\frac{1}{5}+\frac{2}{5}+1\frac{2}{5}\right)=4x\)
\(3x+2=4x\)
\(3x+2=3x+x\)
\(\Rightarrow x=2\)
Vậy \(x=2\)
a)\(\frac{x+1}{5}+\frac{x+3}{4}=\frac{x+5}{3}+\frac{x+7}{2}\)
\(\Leftrightarrow\frac{12\left(x+1\right)}{60}+\frac{15\left(x+3\right)}{60}=\frac{20\left(x+5\right)}{60}+\frac{30\left(x+7\right)}{60}\)
\(\Leftrightarrow12x+12+15x+45=20x+100+30x+210\)
\(\Leftrightarrow27x+57=50x+310\)
\(\Leftrightarrow27x+57-50x-310=0\)
\(\Leftrightarrow-23x-253=0\)
\(\Leftrightarrow x=-\frac{253}{23}\)
b)Tự làm
\(\frac{1}{3}\) + \(\frac{5}{6}\): \(\left(x-2\frac{1}{5}\right)\)= \(\frac{3}{4}\)
<=> \(\frac{5}{6}\):\(\left(x-2\frac{1}{5}\right)\)= \(\frac{3}{4}\)- \(\frac{1}{3}\)
<=> \(\frac{5}{6}\) : \(\left(x-2\frac{1}{5}\right)\) = \(\frac{5}{12}\)
<=> \(\left(x-2\frac{1}{5}\right)\) = \(\frac{5}{6}\) : \(\frac{5}{12}\)
,<=> \(\left(x-2\frac{1}{5}\right)\)= 2
<=. x = 2 + \(\frac{11}{5}\)
<=> x = \(\frac{21}{5}\)
a)\(\Leftrightarrow3x^2-3x^2+6x=36\Leftrightarrow6x=36\Leftrightarrow x=6\)
\(\left|-x-\frac{2}{5}\right|+\frac{1}{2}=3,5\)
\(\left|-x-\frac{2}{5}\right|=3,5-0,5\)
\(\left|-x-\frac{2}{5}\right|=3\)
\(\Rightarrow\orbr{\begin{cases}-x-\frac{2}{5}=3\\-x-\frac{2}{5}=-3\end{cases}\Leftrightarrow\orbr{\begin{cases}-x=\frac{17}{5}\\-x=-\frac{13}{5}\end{cases}\Leftrightarrow}\orbr{\begin{cases}x=-\frac{17}{5}\\x=\frac{13}{5}\end{cases}}}\)
Vậy \(x=-\frac{17}{5}\)hoặc \(x=\frac{13}{5}\)
Mày không biết trả lời mình mẫu giáo mà
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