Tính
a> -0,32 + 4,15 - 2
b > 24 - 0,47 - 2,5
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a) (3+xy2)2
=32+2.3.xy2+(xy2)2
=9+6xy2+x2y4
Vậy ...
b) (10−2m2n)2
=102−2.10.2m2n+(2m2n)2
=100−40m2n+4m4n2
Vậy ...
c) (a−b2)(a+b2)
=a2−(b2)2
=a2−b4
Vậy ...
\(\begin{array}{l}a)\frac{{ - 6}}{{18}} + \frac{{18}}{{27}}\\ = \frac{{ - 1}}{3} + \frac{2}{3}\\ = \frac{1}{3}\\b)2,5 - ( - \frac{6}{9})\\ = \frac{{25}}{{10}} + \frac{6}{9}\\ = \frac{5}{2} + \frac{2}{3}\\ = \frac{{15}}{6} + \frac{4}{6}\\ = \frac{{19}}{6}\\c) - 0,32.( - 0,875)\\ = \frac{{ - 32}}{{100}}.( - \frac{{875}}{{1000}})\\ = \frac{{ - 8}}{{25}}.(\frac{{ - 7}}{8})\\ = \frac{8}{{25}}.\frac{7}{8}\\ = \frac{7}{{25}}\\d)( - 5):2\frac{1}{5}\\ = ( - 5):\frac{{11}}{5}\\ = ( - 5).\frac{5}{{11}}\\ = \frac{{ - 25}}{{11}}\end{array}\)
a:\(\dfrac{1}{4}+\dfrac{1}{5}+\dfrac{1}{2}=\dfrac{5}{20}+\dfrac{4}{20}+\dfrac{10}{20}=\dfrac{19}{20}\)
b:\(\dfrac{3}{7}+\dfrac{5}{8}+\dfrac{1}{4}=\dfrac{24}{56}+\dfrac{35}{56}+\dfrac{14}{56}=\dfrac{73}{56}\)
a,1,38
b,21.03
\(a,-0,32+4,15-2=0.83\)
\(b,24-0,47-2,5=21,03\)