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25×20.04+4×20.04-2004×20.03+20.04×20.04
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=5.32x5959+0.532x10x4+5.32x10x203.3+5.32x100x20.04
=5.32x5959+5.32x4+5.32x2003+5.32x2004
=5.32x(5959+4+2003+2004)
=5.32x9970=53040.4
= 53,2 x 595,9 + 53,2 x 0,04 + 53,2 x 203,3 + 53.2 x 200,4
= 53,2 x (595,9 + 0,04 + 203,3 + 200,4 )
= 53,2 x 999,64
= 53180,848
\(25\times323-22\times25-25\\ =25\times\left(323-22-1\right)\\ =25\times300\\ =7500\)
a) \(\dfrac{25}{37}\times\dfrac{18}{29}+\dfrac{18}{29}\times\dfrac{12}{37}\)
\(=\dfrac{18}{29}\times\left(\dfrac{25}{37}+\dfrac{12}{37}\right)\)
\(=\dfrac{18}{29}\times\dfrac{37}{37}\)
\(=\dfrac{18}{29}\times1\)
\(=\dfrac{18}{29}\)
b) \(\dfrac{31}{85}\times\dfrac{11}{19}+\dfrac{31}{85}\times\dfrac{12}{19}-\dfrac{42}{19}\times\dfrac{31}{85}\)
\(=\dfrac{31}{85}\times\left(\dfrac{11}{19}+\dfrac{12}{19}-\dfrac{42}{19}\right)\)
\(=\dfrac{31}{85}\times\dfrac{-19}{19}\)
\(=\dfrac{31}{85}\times-1\)
\(=-\dfrac{31}{85}\)
c) \(\dfrac{16}{53}:\dfrac{17}{9}-\dfrac{16}{53}:\dfrac{17}{8}\)
\(=\dfrac{16}{53}:\left(\dfrac{9}{17}-\dfrac{8}{17}\right)\)
\(=\dfrac{16}{53}:\dfrac{1}{17}\)
\(=\dfrac{16}{901}\)
c) \(\dfrac{1}{5}\times\dfrac{12}{31}\times\dfrac{4}{3}+\dfrac{19}{31}\times\dfrac{4}{15}\)
\(=\dfrac{4}{15}\times\dfrac{12}{31}+\dfrac{19}{31}\times\dfrac{4}{15}\)
\(=\dfrac{4}{15}\times\left(\dfrac{12}{31}+\dfrac{19}{31}\right)\)
\(=\dfrac{4}{15}\times\dfrac{31}{31}\)
\(=\dfrac{4}{15}\times1\)
\(=\dfrac{4}{15}\)
a: =18/29*(25/37+12/37)
=18/29
b: =31/85(11/19+12/19-42/19)
=-31/85
c; =16/53(9/17+8/17)=16/53
d: =4/15(12/31+19/31)=4/15
a = 2004 x (4+1+1+1+1)
=2004 x 8=16032
b = 1995 x (1+1+3)
= 1995 x 5 =9975
25 * 20,04 + 4 * 20,04 - 2004 * 20,33 + 2004 * 20,04
= 25 * 20,04 + 4 * 20,04 - 2033 * 20,04 + 2004 * 20,04
= ( 25 + 4 - 2033 + 2004 ) * 20,04
= 0 * 20,04
= 0
25 x 20,04 + 4 x 20,04 - 2004 x 20,33 + 2004 x 20,04
= 25 x 20,04 + 4 x 20,04 - 20,04 x 100 x 20,33 + 2004 x 20,04
= 25 x 20,04 + 4 x 20,04 - 20,04 x 2033 + 2004 x 20,04
= 20,04 x (25 + 4 - 2033 + 2004)
= 20,04 x 0
= 0
bạn đánh sai số 2003