\(\frac{4-\frac{1}{23}-\frac{56}{39}-\frac{25}{47}}{\frac{5}{69}+\frac{5}{117}+\frac{5}{141}}\)
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\(\frac{4-\frac{3}{69}-\frac{168}{117}-\frac{75}{141}}{\frac{5}{69}+\frac{5}{117}+\frac{5}{141}}\)
=\(\frac{\frac{66}{69}-\frac{66}{117}-\frac{66}{141}}{\frac{5}{69}+\frac{5}{117}+\frac{5}{141}}\)
=\(\frac{66\left(\frac{1}{69}+\frac{1}{117}+\frac{1}{141}\right)}{5\left(\frac{1}{69}+\frac{1}{117}+\frac{1}{141}\right)}\)
=\(\frac{66}{5}\)
@@ dùng máy tính mà tính
Anh làm mẫu 1 phần
\(\frac{\frac{2}{2017}+\frac{2}{2018}}{\frac{5}{2017}+\frac{5}{2018}}=\frac{2.\left(\frac{1}{2017}+\frac{1}{2018}\right)}{5.\left(\frac{1}{2017}+\frac{1}{2018}\right)}=\frac{2}{5}\)
Đặt: \(\frac{1}{117}=a,\frac{1}{119}=b\)
Khi đó: \(A=3ab-4a.5.118b-5ab+\frac{8}{39}\)
\(=-2362ab+\frac{8}{39}\)
\(=-2362.\frac{1}{117}.\frac{1}{119}=\frac{38}{1071}\)
Bài 1:
a) \(\left(\frac{9}{25}-2.18\right):\left(3\frac{4}{5}+0,2\right)\)
\(=\left(\frac{9}{25}-36\right):\left(\frac{19}{5}+\frac{1}{5}\right)\)
\(=\left(\frac{9}{25}-\frac{900}{25}\right):4\)
\(=-\frac{891}{25}.\frac{1}{4}\)
\(=-\frac{891}{100}\)
b) \(\frac{3}{8}.19\frac{1}{3}-\frac{3}{8}.33\frac{1}{3}\)
\(=\frac{3}{8}.\frac{58}{3}-\frac{3}{8}.\frac{100}{3}\)
\(=\frac{3}{8}\left(\frac{58}{3}-\frac{100}{3}\right)\)
\(=\frac{3}{8}\left(-\frac{42}{3}\right)\)
\(=\frac{3}{8}.\left(-14\right)\)
\(=-\frac{21}{4}\)
c) \(1\frac{4}{23}+\frac{5}{21}-\frac{4}{23}+0,5+\frac{16}{21}\)
\(=\frac{27}{23}+\frac{5}{21}-\frac{4}{23}+\frac{1}{2}+\frac{16}{21}\)
\(=\frac{27}{23}+\frac{5}{21}+\left(-\frac{4}{23}\right)+\frac{1}{2}+\frac{16}{21}\)
\(=\left[\frac{27}{23}+\left(-\frac{4}{23}\right)\right]+\left(\frac{5}{21}+\frac{16}{21}\right)+\frac{1}{2}\)
\(=1+1=2\)
d) \(\frac{21}{47}+\frac{9}{45}+\frac{26}{47}+\frac{4}{5}\)
\(=\frac{21}{47}+\frac{9}{45}+\frac{26}{47}+\frac{36}{45}\)
\(=\left(\frac{21}{47}+\frac{26}{47}\right)+\left(\frac{9}{45}+\frac{36}{45}\right)\)
\(=1+1=2\)