-52 + 2/3 x X= -46
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\(-52+\frac{2}{3}x=-46\)
\(\frac{2}{3}x=-46-\left(-52\right)\)
\(\frac{2}{3}x=6\)
\(x=6:\frac{2}{3}\)
\(x=9\)
\(\frac{2}{3}\)X=-46-(-52)
\(\frac{2}{3}\)X=6
X=6chia \(\frac{2}{3}\)
X=9
a) 25 + 5 x 5 = 25 + 25
= 50
b) 160 – 48 : 4 = 160 - 12
= 148
c) 732 + 46 : 2 = 732 + 23
= 755
d) 974 – 52 x 3 = 974 – 156
= 818
Giải phương trình:
a) x+1 /9 + x+2 /8 = x+3 /7 + x+4 /6
b) x+43 /57 + x+46 /54 = x+49 /51 + x+52 /48
a) \(\frac{x+1}{9}+\frac{x+2}{8}=\frac{x+3}{7}+\frac{x+4}{6}\)
\(\Rightarrow\left(\frac{x+1}{9}+1\right)+\left(\frac{x+2}{8}+2\right)=\left(\frac{x+3}{7}+1\right)+\left(\frac{x+4}{6}+1\right)\)
\(\Rightarrow\frac{x+10}{9}+\frac{x+10}{8}-\frac{x+10}{7}-\frac{x+10}{6}=0\)
\(\Rightarrow\left(x+10\right)\left(\frac{1}{9}+\frac{1}{8}-\frac{1}{7}-\frac{1}{6}\right)=0\)
Mà \(\frac{1}{9}+\frac{1}{8}-\frac{1}{7}-\frac{1}{6}\ne0\)
\(\Rightarrow x+10=0\)
\(\Rightarrow x=-10\)
Vậy x = -10
b) \(\frac{x+43}{57}+\frac{x+46}{54}=\frac{x+49}{51}+\frac{x+52}{48}\)
\(\Rightarrow\left(\frac{x+43}{57}+1\right)+\left(\frac{x+46}{54}+1\right)=\left(\frac{x+49}{51}+1\right)+\left(\frac{x+52}{48}+1\right)\)
\(\Rightarrow\frac{x+100}{57}+\frac{x+100}{54}=\frac{x+100}{51}+\frac{x+100}{48}\)
\(\Rightarrow\frac{x+100}{57}+\frac{x+100}{54}-\frac{x+100}{51}-\frac{x+100}{48}=0\)
\(\Rightarrow\left(x+100\right)\left(\frac{1}{57}+\frac{1}{54}-\frac{1}{51}-\frac{1}{48}\right)=0\)
Mà \(\frac{1}{57}+\frac{1}{54}-\frac{1}{51}-\frac{1}{48}\ne0\)
\(\Rightarrow x+100=0\)
\(\Rightarrow x=-100\)
Vậy x = -100
a.\(\frac{x+1}{9}+\frac{x+2}{8}=\frac{x+3}{7}+\frac{x+4}{6}\)
=>\(\frac{x+1}{9}+1+\frac{x+2}{8}+1=\frac{x+3}{7}+1+\frac{x+4}{6}+1\)
<=> \(\frac{x+1+9}{9}+\frac{x+2+8}{8}=\frac{x+3+7}{7}+\frac{x+4+6}{6}\)
<=>\(\frac{x+10}{9}+\frac{x+10}{8}=\frac{x+10}{7}+\frac{x+10}{6}\)
<=> \(\frac{x+10}{9}+\frac{x+10}{8}-\frac{x+10}{7}-\frac{x+10}{6}=0\)
<=> \(\left(x+10\right)\left(\frac{1}{9}+\frac{1}{8}-\frac{1}{7}-\frac{1}{6}\right)=0\)
<=> x+10=0
<=> x=-10
Vậy tập nghiệm của phương trình trên là S=\(\left\{-10\right\}\)
b. \(\frac{x+43}{57}+\frac{x+46}{54}=\frac{x+49}{51}+\frac{x+52}{48}\)
=> \(\frac{x+43}{57}+1+\frac{x+46}{54}+1=\frac{x+49}{51}+1+\frac{x+52}{48}+1\)<=>\(\frac{x+43+57}{57}+\frac{x+46+54}{54}=\frac{x+49+51}{51}+\frac{x+52+48}{48}\)
<=>\(\frac{x+100}{57}+\frac{x+100}{54}=\frac{x+100}{51}+\frac{x+100}{48}\)
<=>\(\frac{x+100}{57}+\frac{x+100}{54}-\frac{x+100}{51}-\frac{x+100}{48}=0\)
<=>(x+100)\(\left(\frac{1}{57}+\frac{1}{54}-\frac{1}{51}-\frac{1}{48}\right)\)=0
<=>x+100=0
<=>x= -100
Vậy tập nghiệm của phương trình trên là S=\(\left\{-100\right\}\)
\(\frac{x}{27}-\frac{2}{9}=\frac{6}{18}\)
\(\frac{x}{27}=\frac{6}{18}-\frac{2}{9}\)
\(\frac{x}{27}=\frac{3}{9}-\frac{2}{9}\)
\(\frac{x}{27}=\frac{1}{9}\)
\(\frac{x}{27}=\frac{3}{27}\)
\(x=3\)
Ấy nhầm, làm lại nha:
\(\frac{x}{27}-\frac{2}{9}=\frac{6}{18}\)
\(\frac{x}{27}=\frac{6}{18}+\frac{2}{9}\)
\(\frac{x}{27}=\frac{3}{9}+\frac{2}{9}\)
\(\frac{x}{27}=\frac{5}{9}\)
\(\frac{x}{27}=\frac{15}{27}\)
\(x=15\)
\(-52+\frac{2}{3}x=-46\)
\(\frac{2}{3}x=-46+52\)
\(\frac{2}{3}x=6\)
\(x=6:\frac{2}{3}\)
\(x=9\)
1) 1996 + 3992 + 5988 + 7984
= 1996 x 1 + 1996 x 2 + 1996 x 3 + 1996 x 4
= 1996 x ( 1 + 2 + 3 + 4)
= 1996 x 10 = 19960
2) 2 x 3 x 4 x 8 x 50 x 25 x 125
= 3 x (2 x 50) x (4 x 25) x (8 x 125)
= 3 x 100 x 100 x 1000
= 30.000.000
3(45 x 46 + 47 x 48) x (51 x 52 - 49 x 48) x (45 x 128 - 90 x 64)
x (1995 x 1996 + 1997 x 1998)
Ta thÊy : 45 x 128 - 90 x 64
= 45 x 2 x 64 - 90 x 64
= 90 x 64 - 90 x 64
= 0
1) 1996 + 3992 + 5988 + 7984
= 1996 x 1 + 1996 x 2 + 1996 x 3 + 1996 x 4
= 1996 x ( 1 + 2 + 3 + 4)
= 1996 x 10 = 19960
2) 2 x 3 x 4 x 8 x 50 x 25 x 125
= 3 x (2 x 50) x (4 x 25) x (8 x 125)
= 3 x 100 x 100 x 1000
= 30.000.000
3(45 x 46 + 47 x 48) x (51 x 52 - 49 x 48) x (45 x 128 - 90 x 64)
x (1995 x 1996 + 1997 x 1998)
Ta thÊy : 45 x 128 - 90 x 64
= 45 x 2 x 64 - 90 x 64
= 90 x 64 - 90 x 64
= 0
L I K E NHÁ BẠN^^
-52 + \(\frac{2}{3}\)x X = -46
\(\frac{2}{3}\)X = \(-46+52\)
\(\frac{2}{3}x=6\)
\(x=6:\frac{2}{3}=9\)
2 / 3 x X = -46 -- 52
2/3 xX = 6
X = 6 : 2/3
X = 9