X/6 - 3/7 = 17/42
Trả lời đúng và nhanh thì mik tick cho ✨
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a) 14-(7-x+3)=5-{4-(5- |3| ) }
14-(10-x) = 5-{4-(5-3) }
x +14-10=5-(4-2)
x+4 = 5-2
x+4 =3
x =3-4
x =-1 Vậy x= -1
-7 + [ - (-3) + |6| - (544 + |-6 |) ] = 5 - ( 7 - x + 4)
-7+{ 3+6-(544+6) } =5-(11-x)
-7+(9-600) =x+5-11
-7+-591 =x+(-6)
-598 = x+ (-6)
x =-598 - (-6)
x = -592
Vậy x= -592
tick mình nha
1+2+3+4+5+6+7+8+9+10+11+12+13+14+15+16+17+18+19+20
= (1+19)+(2+18)+(3+17)+(4+16)+(5+15)+(6+14)+(7+13)+(8+12)+(9+11)+(10+20)
= 20 + 20 + 20 + 20 + 20 + 20 + 20 + 20 + 20 +30
= 20x9 +30
=180+30
=210
tk cho mik nhé
a, 2/3 - 2/9 + 7/9 = 6/9 - 2/9 + 7/9 = 10/9
b, 7/6 + 3/5 : 6 = 7/6 + 3/5 x 1/6 = 7/6 + 1/10 = 70/60 + 6/10 = 76/10 = 38/5
c, x : 6/25 = 18
x = 18 x 6/25
x = 36/25
d, ( 2/5 + 4/7) : x = 17/5
29/35 : x = 17/5
x = 29/35 : 17/5
x = 29/119
\(a.\dfrac{2}{3}-\dfrac{2}{9}+\dfrac{7}{9}=\dfrac{6}{9}-\dfrac{2}{9}+\dfrac{7}{9}=\dfrac{4}{9}+\dfrac{7}{9}=\dfrac{11}{9}\\ b.\dfrac{7}{6}+\dfrac{3}{5}:6=\dfrac{7}{6}+\dfrac{3}{5}\times\dfrac{1}{6}=\dfrac{7}{6}+\dfrac{1}{10}=\dfrac{70}{60}+\dfrac{6}{60}=\dfrac{76}{60}=\dfrac{19}{15}\\ c.x:\dfrac{6}{25}=18\\ x=18\times\dfrac{6}{25}\\ x=\dfrac{108}{25}\\ d.\left(\dfrac{2}{5}+\dfrac{4}{7}\right):x=\dfrac{17}{5}\\ \dfrac{34}{35}:x=\dfrac{7}{5}\\ x=\dfrac{34}{35}:\dfrac{7}{5}\\ x=\dfrac{34}{49}\)
a) 7 - ( 18 + x ) = - 15
18 + x = 7+ 15
18 + x = 22
x = 22 - 18
x = 4
vậy x= 4
Trl:
a) \(7-\left(18+x\right)=-15\)
\(\Rightarrow\left(18+x\right)=7-\left(-15\right)\)
\(\Rightarrow\left(18+x\right)=7+15\)
\(\Rightarrow\left(18+x\right)=22\)
\(\Rightarrow x=22-18\)
\(\Rightarrow x=4\)
b) \(\left(x-17\right)-\left(-3\right)=0\)
\(\Rightarrow\left(x-17\right)+3=0\)
\(\Rightarrow\left(x-17\right)=0-3\)
\(\Rightarrow\left(x-17\right)=-3\)
\(\Rightarrow x=-3+17\)
\(\Rightarrow x=14\)
5x+6⋮x+2
=>5(x+2)-4⋮x+2
Mà x+2⋮x+2 =>5(x+2)⋮x+2
=>4⋮x+2
=>x+2∈Ư(4)={-4;-2;-1;1;2;4}
=>x∈{-6;-4;-3;-1;0;2}
Vì x+2 ⋮ x+2; 5 ∈ N
=> 5(x+2) ⋮ x+2
=> 5x +10 ⋮ x+2
Mà 5x + 6 ⋮ x+2
=> (5x+10)-(5x+6) ⋮ x+2
=> 4 ⋮ x+2
=> x+2 thuộc tập ước của 4
Mà ước của 4 = {1;-1;2;-2;4;-4}
=> x+2 ∈ {1;-1;2;-2;4;-4}
=> x ∈ {-1;-3;0;-4;2;-6}
Vậy x ∈ {-1;-3;0;-4;2;-6}
\(\frac{x}{6}-\frac{3}{7}=\frac{17}{42}\)
\(\frac{x}{6}=\frac{17}{42}+\frac{3}{7}\)
\(\frac{x}{6}=\frac{5}{6}\)
\(\Rightarrow x=5\)
\(\frac{x}{6}-\frac{3}{7}=\frac{17}{42}\)
\(\frac{x}{6}=\frac{17}{42}+\frac{3}{7}\)
\(\frac{x}{6}=\frac{17}{42}+\frac{18}{42}\)
\(\frac{x}{6}=\frac{35}{42}\)
\(\frac{x}{6}=\frac{5}{6}\)
\(\Rightarrow x=5\)