\(\frac{1}{10}+\frac{9}{10}+\frac{10}{10}+9+\frac{160}{2}\)
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\(\frac{-9}{10}.\frac{5}{14}+\frac{1}{10}.\frac{-9}{2}+\frac{1}{7}.\frac{-9}{10}\)
\(=\frac{-9}{10}.\frac{5}{14}+\frac{-9}{10}.\frac{1}{2}+\frac{1}{7}.\frac{-9}{10}\)
\(=\frac{-9}{10}.\left(\frac{5}{14}+\frac{1}{2}+\frac{1}{7}\right)=\frac{-9}{10}.1=\frac{-9}{10}\)
\(\frac{-9}{10}.\frac{5}{14}+\frac{1}{10}.\left(\frac{-9}{2}\right)+\frac{1}{7}.\frac{-9}{10}\)
\(=\frac{-9}{10}.\frac{5}{14}+\frac{1}{7}.\frac{-9}{10}+\frac{1}{10}.\left(\frac{-9}{2}\right)\)
\(=\frac{-9}{10}.\left(\frac{5}{14}+\frac{1}{7}\right)+\frac{1}{10}.\left(\frac{-9}{2}\right)\)
\(=\frac{-9}{10}.\frac{1}{2}+\frac{1}{10}.\left(\frac{-9}{2}\right)\)
\(=\left(\frac{-9}{10}+\frac{1}{2}\right)^2\)
\(=\left(\frac{-9}{10}+\frac{5}{10}\right)^2\)
\(=\left(\frac{-2}{5}\right)^2\)
\(=\frac{4}{25}\)
\(=\frac{1+2+3+4+5+6+7+8+9}{10}\)
\(=\frac{45}{10}=\frac{9}{2}\)
a,
\(=\frac{1+2+3+4+5+6+7+8+9}{10}=\frac{45}{10}=\frac{9}{2}\)
b,\(=9\times\left(\frac{26\times10101}{27\times10101}+\frac{8\times11111}{9\times11111}\right)=9\times\left(\frac{26}{27}+\frac{8}{9}\right)=9\times\frac{50}{27}=\frac{50}{3}\)
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\(\frac{1}{10}+\frac{9}{10}+\frac{10}{10}+9+\frac{160}{2}\)
\(=\frac{10}{10}+\frac{10}{10}+9+\frac{160}{2}\)
\(=1+1+9+80\)
\(=91\)
Ta có \(\frac{1}{10}+\frac{9}{10}+\frac{10}{10}+9+\frac{160}{2}=\left(\frac{1}{10}+\frac{9}{10}\right)+\left(\frac{10}{10}+9\right)+\frac{160}{2}\)
\(=1+10+80\)
\(=91\)
Vậy giá trị biểu thức là 91