1. C

2. D

3. A

4. B

5. A

1. C

2. D

3. A

4. B

5. A

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Đề cho 200 ml dung dịch gì bạn nhỉ?

In the world there are many big cities but the one I like the most is Tokyo, in Japan. This city is the capital of Japan. Not only that, but Tokyo is also an administrative center of Japan and the world. Tokyo is considered a culinary paradise, where you will enjoy dishes from popular to high-end dishes. One of them is Sushi - a famous traditional dish of Japan that the whole world knows is also produced from this city, especially exploring Ebisu with grilled meat, vegetables, hot pot, sashimi … At the same time, many dishes in the train station area are very convenient for passengers at the station as well as nearby. Explore the many other dishes in the basement or head to Honoji to find food from the menu on the wall. In addition to the domestic food, in Tokyo you can enjoy other dishes from other countries such as America, France, Germany ... In addition to eating, Tokyo is also a place to shop with cheap and affordable items to types of high-class products with famous brands in the world. In addition, in Tokyo there is a Japanese crab symbol, which is the Tokyo Tower. The most popular in japan is the blossom tree '' sakura'',....

Program HOC24;

var i,n: integer;

t: longint;

begin

write('Nhap n '); readln(n);

t:=1;

for i:=1 to n do t:=t*2;

write('2^,n,' = ',t);

readln

end.

program Tinh_2_mu_n;
var
n, i: integer;
ket_qua: longint;
begin
write('Nhap vao so nguyen n: '); readln(n);
ket_qua := 1;
for i := 1 to n do
ket_qua := ket_qua * 2;writeln('2^', n, '=',ket_qua); readin;
end.  

a, \(Mg+2HCl\rightarrow MgCl_2+H_2\)

b, \(n_{Mg}=\dfrac{2,4}{24}=0,1\left(mol\right)\)

Theo PT: \(n_{HCl}=2n_{Mg}=0,2\left(mol\right)\)

\(\Rightarrow m_{ddHCl}=\dfrac{0,2.36,5}{20\%}=36,5\left(g\right)\)

c, \(n_{MgCl_2}=n_{H_2}=n_{Mg}=0,1\left(mol\right)\)

Ta có: m _{dd sau pư} = 2,4 + 36,5 - 0,1.2 = 38,7 (g)

\(\Rightarrow C\%_{MgCl_2}=\dfrac{0,1.95}{38,7}.100\%\approx24,55\%\)

cái gí tu

\(a,PTHH:Mg+2HCl\rightarrow MgCl_2+H_2\\b,n_{Mg}=\dfrac{2,4}{24}=0,1\left(mol\right)\Rightarrow n_{MgCl_2}=n_{H_2}=n_{Mg}=0,1\left(mol\right);n_{HCl}=2.0,1=0,2\left(mol\right)\\ b,m_{ddHCl}=\dfrac{0,2.36,5.100}{20}=36,5\left(g\right)\\ c,m_{ddsau}=2,4+36,5-0,1.2=38,7\left(g\right)\\ C\%_{ddMgCl_2}=\dfrac{0,1.95}{38,7}.100\approx24,548\%\)