bạn ơi x173/24 là sao mk ko hiểu

mik ghi thiếu

(43/8+x-173/24):50/3=2

giờ mới đúng

2⁴.5-2⁴.3
=2⁴.(5-3)
=2⁴.2
=2^{5
học tốt nhoa}
 

\(2^4\cdot5-2^4\cdot3\) 

=\(2^4\cdot\left(5-3\right)\) 

=\(16\cdot2\)

= \(32\)

\(=3^2.22-3^3.19\)

\(=3^2.22-3^2.57\)

\(=3^2\left(22-57\right)\)

\(=3^2.-35\)

\(=-9.35=-315.\)

a/    Fe → FeCl₂ → Fe(OH)₂ → FeSO₄ → Fe(NO₃)₂ → Fe₂(SO₄)₃ → Fe(OH)₃ → Fe₂O₃ → Fe → FeCl₃

1. Fe + 2HCl → FeCl₂ + H₂

2. FeCl₂ + Ba(OH)₂ → Fe(OH)₂ + BaCl₂ 

3. Fe(OH)₂ + H₂SO₄ → FeSO₄ + 2H₂O

4. FeSO₄ + Ba(NO₃)₂ → Fe(NO₃)₂ + BaSO₄

5. 6Fe(NO₃)₂ + 9H₂SO₄ → 3Fe₂(SO₄)₃ + 4H₂O + 10HNO₃ + NO

6. Fe₂(SO₄)₃ + 6NaOH → 2Fe(OH)₃ + 3Na₂SO₄

7. 2Fe(OH)₃ → (nhiệt độ) Fe₂O₃ + 3H₂O

8. Fe₂O₃ + 3CO → (nhiệt độ) 2Fe + 3CO₂

9. Fe + Cl₂ → (nhiệt độ) FeCl₃

b/    Al → Al₂O₃  →  AlCl₃ → Al(OH)₃ → Al₂O₃  → Al → NaAlO₂

1. 4Al + 3O₂ → (nhiệt độ) 2Al₂O₃

2. Al₂O₃ + 6HCl → 2AlCl₃ + 3H₂O

3. 2AlCl₃ + 3Ca(OH)₂ → 2Al(OH)₃ + 3CaCl₂

4. 2Al(OH)₃ → (nhiệt độ) Al₂O₃ + 3H₂O

5. 2Al₂O₃ → (nhiệt độ) 4Al + 3O₂

6. 2Al + 2H₂O + 2NaOH → 2NaAlO₂ + 3H₂

(x+5)³-x³-125

=x³+5³-x³-5³

=0

1. \(\left(x+5\right)^3-x^3-125\)

\(=x^3+15x^2+75x+125-x^3-125\)

\(=15x^2+75x\)

2. \(x^3+6x^2+12x+8=0\)

\(\Leftrightarrow x^3+2x^2+4x^2+8x+4x+8=0\)

\(\Leftrightarrow x^2\left(x+2\right)+4x\left(x+2\right)+4\left(x+2\right)=0\)

\(\Leftrightarrow\left(x^2+4x+4\right)\left(x+2\right)=0\)

\(\Leftrightarrow\left(x+2\right)^2\left(x+2\right)=0\)

\(\Leftrightarrow\left(x+2\right)^3=0\)

\(\Leftrightarrow x+2=0\Leftrightarrow x=-2\)

\(\frac{5}{6}x+\frac{1}{2}-\frac{1}{3}x=0,75x-\frac{7}{8}\)  

\(\frac{5}{6}x-\frac{1}{3}x-0,75x=-\frac{7}{8}-\frac{1}{2}\) 

\(\frac{5}{6}x-\frac{1}{3}x-\frac{3}{4}x=-\frac{11}{8}\) 

\(\frac{1}{2}x-\frac{3}{4}x=-\frac{11}{8}\)  

\(-\frac{1}{4}x=-\frac{11}{8}\)  

\(x=-\frac{11}{8}:-\frac{1}{4}\)  

\(x=\frac{11}{2}\)