\(\frac{x}{5}=\frac{4,2}{8,4}\)

\(\frac{x}{5}=\frac{1}{2}\)

\(\Leftrightarrow\)\(2x=5\)

\(\Leftrightarrow\)\(x=\frac{5}{2}\)

x= 25,5

hok tốt

ư ư ư ư ư ư ư ư thôi bỏ

Từ \(2x=3y\)\(\Rightarrow\)\(\frac{x}{3}=\frac{y}{2}=\frac{x}{3}.\frac{1}{7}=\frac{y}{2}.\frac{1}{7}\)\(\Rightarrow\)\(\frac{x}{21}=\frac{y}{14}\)( 1 )

Từ \(5y=7z\)\(\Rightarrow\)\(\frac{y}{7}=\frac{z}{5}=\frac{y}{7}.\frac{1}{2}=\frac{z}{5}.\frac{1}{2}\)\(\Rightarrow\)\(\frac{y}{12}=\frac{z}{10}\)( 2 )

Từ ( 1 ) và ( 2 ) suy ra : \(\frac{x}{21}=\frac{y}{14}=\frac{z}{10}\)

Đặt \(\frac{x}{21}=\frac{y}{14}=\frac{z}{10}=k\)\(\Rightarrow\hept{\begin{cases}x=21k\\y=14k\\z=10k\end{cases}}\)

Thay vào ta được :

\(2.21k-3.14k+4.10k=350\)

\(42k-42k+40k=350\)

\(40k=350\)

\(k=\frac{35}{4}\)

\(\Rightarrow\hept{\begin{cases}x=21.\frac{35}{4}\\y=14.\frac{35}{4}\\z=10.\frac{35}{4}\end{cases}}\)\(\Rightarrow\hept{\begin{cases}x=\frac{735}{4}\\y=\frac{245}{2}\\z=\frac{175}{2}\end{cases}}\)

Ta có :

( x + 0,8 )² = 0,25

\(\Rightarrow\left(x+\frac{4}{5}\right)^2=\frac{1}{4}\)

\(\Rightarrow\orbr{\begin{cases}\left(x+\frac{4}{5}\right)^2=\left(\frac{1}{2}\right)^2\\\left(x+\frac{4}{5}\right)^2=\left(\frac{-1}{2}\right)^2\end{cases}}\)

\(\Rightarrow\orbr{\begin{cases}x+\frac{4}{5}=\frac{1}{2}\\x+\frac{4}{5}=\frac{-1}{2}\end{cases}}\)

\(\Rightarrow\orbr{\begin{cases}x=\frac{-3}{10}\\x=\frac{-13}{10}\end{cases}}\)

\(\left(x+0,8\right)^2=0,25\)

\(\left(x+0,8\right)^2=\frac{1}{4}\)

\(\left(x+0,8\right)^2=\left(\frac{1}{2}\right)^2\)hoặc \(\left(-\frac{1}{2}\right)^2\)

\(x+0,8=\pm\frac{1}{2}\)

\(\Rightarrow\orbr{\begin{cases}x+0,8=\frac{1}{2}\\x+0,8=-\frac{1}{2}\end{cases}}\)\(\Rightarrow\orbr{\begin{cases}x=\frac{1}{2}-0,8\\x=-\frac{1}{2}-0,8\end{cases}}\)\(\Rightarrow\orbr{\begin{cases}x=-\frac{3}{10}\\x=-\frac{13}{10}\end{cases}}\)

\(\frac{1}{1.2}+\frac{1}{3.4}+...+\frac{1}{49.50}=1-\frac{1}{2}+\frac{1}{3}-\frac{1}{4}+...+\frac{1}{49}-\frac{1}{50}\)

\(=\left(1+\frac{1}{2}+\frac{1}{3}+\frac{1}{4}+...+\frac{1}{49}+\frac{1}{50}\right)-2\left(\frac{1}{2}+\frac{1}{4}+...+\frac{1}{50}\right)\)

\(=\left(1+\frac{1}{2}+\frac{1}{3}+\frac{1}{4}+...+\frac{1}{49}+\frac{1}{50}\right)-\left(1+\frac{1}{2}+...+\frac{1}{25}\right)\)

\(=\frac{1}{26}+\frac{1}{27}+\frac{1}{28}+...+\frac{1}{50}\)

Lại có \(\frac{30}{26}+\frac{31}{27}+...+\frac{54}{50}-25\)

\(=\left(\frac{30}{26}-1\right)+\left(\frac{31}{27}-1\right)+...+\left(\frac{54}{50}-1\right)\)

\(=\frac{4}{26}+\frac{4}{27}+...+\frac{4}{50}=4\left(\frac{1}{26}+\frac{1}{27}+...+\frac{1}{50}\right)\)

Khi đó M = \(\left(\frac{1}{26}+\frac{1}{27}+...+\frac{1}{49}+\frac{1}{50}\right):\left[4\left(\frac{1}{26}+\frac{1}{27}+...+\frac{1}{50}\right)\right]=\frac{1}{4}\)

\(\frac{2^7-9^3}{6^5-8^2}=\frac{2^7-\left(3^2\right)^3}{\left(2.3\right)^5-\left(2^3\right)^2}\)

\(=\frac{2^7-3^6}{2^5.3^5-2^6}=\frac{2^7-3^6}{2^5.\left(3^5-2\right)}\)

\(=\frac{128-729}{32.241}=\frac{-601}{7712}\)