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21 tháng 11 2024

a)   =x^2+3x+x+3

      =x*(x+3)+1*(x+3)

      =(x+1)*(x+3)

b)   =4x^2-2x+6x-3

      =2x*(2x-1)+3*(2x-1)

      =(2x-1)*(2x+3)

c)   =x^2-4x+3x-12

      =x*(x-4)+3*(x-4)

      =(x-4)*(x+3)

 

12 tháng 8 2015

a) x^4 - x^3 - x + 1 

= x^3 ( x - 1 ) - ( x- 1 )

= ( x^3 - 1 )(x - 1)

= ( x- 1 )^2 (x^2 + x +  1 )

 

12 tháng 8 2015

a)x4-x3-x+1

=x3(x-1)-(x-1)

=(x-1)(x3-1)

=(x-1)(x-1)(x2+x+1)

=(x-1)2(x2+x+1)

b)5x2-4x+20xy-8y

(sai đề)

 

29 tháng 9 2019

Xin lỗi mk viết câu hơi sát một chút ak.

1 tháng 10 2016

a)

\(x^5+x^3-x^2-1\)

\(=x^3\left(x^2+1\right)-\left(x^2+1\right)\)

\(=\left(x^2+1\right)\left(x^3-1\right)\)

\(=\left(x^2+1\right)\left(x-1\right)\left(x^2+x+1\right)\)

b)

\(x^2-3x^3-x+3\)

\(=x\left(x-1\right)-3\left(x^3-1\right)\)

\(=x\left(x-1\right)-3\left(x-1\right)\left(x^2+x+1\right)\)

\(=\left(x-1\right)\left(x-3x^2-3x-3\right)\)

\(=\left(x-1\right)\left(-3x^2-2x-3\right)\)

c)

\(x^2-6x+8\)

\(=x^2-2.x.3+9-1\)

\(=\left(x-3\right)^2-1\)

\(=\left(x-3-1\right)\left(x-3+1\right)\)

\(=\left(x-4\right)\left(x-2\right)\)

d)

\(4x^4-4x^2y^2-8y^4\)

\(=\left(2x^2\right)^2-2.\left(2x^2\right)y^2+y^2-9y^4\)

\(=\left(2x^2-y\right)^2-\left(3y^2\right)^2\)

\(=\left(2x^2-y-3y^2\right)\left(2x^2-y+3y^2\right)\)

1 tháng 10 2016

a,nhóm x*5 với x*3,x*2 và 1:   (x*5+ x*3) - (x*2+1) =x*3.(x*2+1)-(x*2+1) =.....,  câu b nhóm x*2 và -3x*3,x và 3,    câu c bang (x-3)*2-1 =..., câu d đat 4 ra.

1 tháng 10 2016

a) \(x^5+x^3-x^2-1=x^3\left(x^2+1\right)-\left(x^2+1\right)=\left(x^3-1\right)\left(x^2+1\right)\)

b) \(x^2-3x^3-x+3=x\left(x-1\right)-3\left(x^3-1\right)=x\left(x-1\right)-3\left(x-1\right)\left(x^2+x+1\right)=\left(x-1\right)\left[\left(x-3\right)-\left(x^2+x+1\right)\right]=\left(x-1\right)\left(-x^2-4\right)\)c) \(x^2-6x+8=x^2-6x+9-1=\left(x-3\right)^2-1=\left(x-2\right)\left(x-4\right)\)

d) \(4x^4+4x^2y^2-8y^4=4x^4+4x^2y^2+y^4-9y^4=\left(2x^2+y^2\right)^2-9y^4=\left(2x^2+4y^2\right)\left(2x^2-2y^2\right)=2\left(x^2+2y^2\right)2\left(x^2-y^2\right)=4\left(x^2+2y^2\right)\left(x+y\right)\left(x-y\right)\)

30 tháng 10 2016

\(A=\left(x^2+x\right)^2-14\left(x^2+x\right)+24\)

Đặt \(x^2+x=t\), ta có:

\(A=t^2-14t+24\)

\(=t^2-2t-12t+24\)

\(=t\left(t-2\right)-12\left(t-2\right)\)

\(=\left(t-2\right)\left(t-12\right)\)

\(=\left(x^2+x-2\right)\left(x^2+x-12\right)\)

\(B=\left(x^2+x\right)^2+4x^2+4x-12\)

\(=\left(x^2+x\right)^2+4\left(x^2+x\right)-12\)

Đặt \(x^2+x=t\), ta có:

\(B=t^2+4t-12\)

\(=t^2+6t-2t-12\)

\(=t\left(t+6\right)-2\left(t+6\right)\)

\(=\left(t+6\right)\left(t-2\right)\)

\(=\left(x^2+x+6\right)\left(x^2+x-2\right)\)

\(C=\left(x+1\right)\left(x+2\right)\left(x+3\right)\left(x+4\right)+1\)

\(=\left(x^2+5x+4\right)\left(x^2+5x+6\right)+1\)

Đặt \(x^2+5x+4=t\), ta có:

\(C=t\left(t+2\right)+1\)

\(=t^2+2t+1\)

\(=\left(t+1\right)^2\)

\(=\left(x^2+5x+4+1\right)^2\)

\(=\left(x^2+5x+5\right)^2\)

\(D=\left(x+1\right)\left(x+3\right)\left(x+5\right)\left(x+7\right)+15\)

\(=\left(x^2+8x+7\right)\left(x^2+8x+15\right)+15\)

Đặt \(x^2+8x+7=t\), ta có:

\(D=t\left(t+8\right)+15\)

\(=t^2+8t+15\)

\(=t^2+3t+5t+15\)

\(=t\left(t+3\right)+5\left(t+3\right)\)

\(=\left(t+3\right)\left(t+5\right)\)

\(=\left(x^2+8x+7+3\right)\left(x^2+8x+7+5\right)\)

\(=\left(x^2+8x+10\right)\left(x^2+8x+12\right)\)

\(F=\left(x^2+x+1\right)\left(x^2+x+2\right)-12\)

Đặt \(x^2+x+1=t\), ta có:

\(F=t\left(t+1\right)-12\)

\(=t^2+t-12\)

\(=t^2+4t-3t-12\)

\(=t\left(t+4\right)-3\left(t+4\right)\)

\(=\left(t+4\right)\left(t-3\right)\)

\(=\left(x^2+x+1+4\right)\left(x^2+x+1-3\right)\)

\(=\left(x^2+x+5\right)\left(x^2+x-2\right)\)

\(E=x^4+2x^3+5x^2+4x-12\)

\(=x^4-x^3+3x^3-3x^2+8x^2-8x+12x-12\)

\(=x^3\left(x-1\right)+3x^2\left(x-1\right)+8x\left(x-1\right)+12\left(x-1\right)\)

\(=\left(x-1\right)\left(x^3+3x^2+8x+12\right)\)

\(=\left(x-1\right)\left(x^3+2x^2+x^2+2x+6x+12\right)\)

\(=\left(x-1\right)\left[x^2\left(x+2\right)+x\left(x+2\right)+6\left(x+2\right)\right]\)

\(=\left(x-1\right)\left(x+2\right)\left(x^2+x+6\right)\)

 

30 tháng 10 2016

siêng phết

16 tháng 7 2018

a)  \(x^3-x^2-5x+125\)

\(=\left(x+5\right)\left(x^2-5x+25\right)-x\left(x+5\right)\)

\(=\left(x+5\right)\left(x^2-6x+25\right)\)

b)  \(5x^2-5xy-3x+3y\)

\(=5x\left(x-y\right)-3\left(x-y\right)\)

\(=\left(x-y\right)\left(5x-3\right)\)

c)  \(x^2-2x-4y^2+1\)

\(=\left(x-1\right)^2-4y^2\)

\(=\left(x-2y-1\right)\left(x+2y-1\right)\)

16 tháng 10 2018

\(1,4x^4+4x^2y^2-8y^4\)

\(=4\left(x^4+x^2y^2-y^4-y^4\right)\)

\(=4\left[\left(x^4-y^4\right)+\left(x^2y^2-y^4\right)\right]\)

\(=4\left[\left(x^2+y^2\right)\left(x^2-y^2\right)+y^2\left(x^2-y^2\right)\right]\)

\(=4\left(x^2-y^2\right)\left(x^2+y^2+y^2\right)\)

\(=4\left(x-y\right)\left(x+y\right)\left(x^2+2y^2\right)\)

16 tháng 10 2018

\(2,12x^2y-18xy^2-30y^3\)

\(=6y\left(2x^2-3xy-5y^2\right)\)

\(=6y\left[\left(2x^2+2xy\right)-\left(5xy+5y^2\right)\right]\)

\(=6y\left[2x\left(x+y\right)-5y\left(x+y\right)\right]\)

\(=6y\left(x+y\right)\left(2x-5y\right)\)

15 tháng 10 2017

\(\text{a) }x^5+x^3-x^2-1\\ \\=\left(x^5-x^2\right)+\left(x^3-1\right)\\ \\=x^2\left(x^3-1\right)+\left(x^3-1\right)\\ \\=\left(x^2+1\right)\left(x^3-1\right)\\ \\=\left(x^2+1\right)\left(x-1\right)\left(x^2+x+1\right)\\ \)

\(\text{b) }x^2-x-12\\ \\=x^2-4x+3x-12\\ \\ =\left(x^2-4x\right)+\left(3x-12\right)\\ =x\left(x-4\right)+3\left(x-4\right)\\ \\=\left(x-4\right)\left(x+3\right)\\ \)

15 tháng 10 2017

a) x5 + x3 - x2 - 1 = ( x5 + x3 ) - ( x2 + 1)

= x3 . ( x2 + 1 ) - ( x2 + 1 )

= ( x2 + 1 ) . ( x3 - 1 )

= ( x2 + 1 ) . ( x - 1 ) . ( x2 + x + 1 )

b) x2 - x - 12 = x2 - 4x + 3x - 12

= x . ( x - 4 ) + 3 . ( x - 4 )

= ( x - 4 ) . ( x + 3 )

c) 4x4 + 4x2y2 - 8y4 = 4x4 - 4x2y2 + 8x2y2 - 8y4

= 4x2 . ( x2 - y2 ) + 8y2 . ( x2 - y2 )

= ( x2 - y2 ) . ( 4x2 + 8y2 )

= 4 . ( x - y ) . ( x + y ) . ( x2 + 2y2 )

10 tháng 7 2019

\(A=\left(6x-3y\right)+\left(4x^2-4xy+y^2\right)\) 

  \(=3\left(2x-y\right)+\left(2x-y\right)^2\) 

  \(=\left(3+2x-y\right)\left(2x-y\right)\)

\(B=9x^2-\left(y^2-4y+4\right)\) 

   \(=9x^2-\left(y-2\right)^2\) 

   \(=\left(3x+y-2\right)\left(3x-y+2\right)\)

10 tháng 7 2019

A = ( 6x - 3y ) + (4x2 - 4xy + y2 )

A = 3.( 2x - y) + [ ( 2x )2 - 2.2.x.y + y2 ]

A = 3.( 2x - y ) + ( 2x - y )2

A = ( 2x - y ).(3 + 2x - y )

B = 9x2 - ( y2 - 4y + 4 )

B = ( 3x )2 - ( y - 2 )2

B = ( 3x - y + 2 ).( 3x + y - 2 )

C = - 25x2 + y2 - 6y + 9

C =   ( y2 - 2.3.y + 3) - ( 5x )2

C = ( y - 3 )2 - ( 5x )2

C = (y - 3 - 5x ).( y - 3 +5x )

D = x2 - 4x - y2 -- 8y  - 12

D = ( x2 - 4x + 4 ) - 4 - y2 - 8y -12

D = ( x - 2.2x + 22 ) - ( y2 + 2.4.y + 42 )

D = ( x - 2 )2 - ( y + 4 )2

D = ( x - 2 + y + 4 ).( x - 2 - y - 4 )

D = ( x + y + 2 ).( x - y - 6 )