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a: =7/8:(2/9-18+1/36)-5/12
=-7/142-5/12=-397/852
b: =3/7(4/9+5/9:6/12)=2/3
c: =5^8(16/31-47/31)+1/3=-5^8+1/3
d: =7/2(3/8+5/8:4/15)=609/64
A) 7/38 x 9/11 +7/38 x 4/11 -7/38 x 2/11
=7/38.(9/11+4/11-2/11)
=7/38
B) 5/31 x 21/25 + 5/31 x -7/10 - 5/31 x 9/20
=5/31.(21/25-7/10-9/20)
=5/31.(-31/100)
=-1/20
a) (x-5)3 = ( x - 5)2
=>\(\left\{{}\begin{matrix}x-5=0\\x-5=1\end{matrix}\right.\) =>\(\left\{{}\begin{matrix}x=5\\x=6\end{matrix}\right.\)
vậy x=5 hoặc x=6
b) 22x+1 - 1 = 31
=> 22x+1=31+1
=> 22x+1=32
=> 22x+1=25
=> 2x+1=5
=> 2x=6
=> x=3
vậy x=3
c) (x - 5)4 - 3 = 78
=> (x-5)4=81
=> (x-5)4=34
=> x-5=3
=> x=8
vậy x=8
Bài 3:
a: =>|x+7|=12-12=0
=>x+7=0
hay x=-7
b: =>|x-3|=4
=>x-3=4 hoặc x-3=-4
=>x=7 hoặc x=-1
c: =>x-5<=0
hay x<=5
Bài 3:
a: =>|x+7|=0
=>x+7=0
hay x=-7
b: =>|x-3|=4
=>x-3=4 hoặc x-3=-4
=>x=7 hoặc x=-1
c: =>x-5<=0
hay x<=5
tìm tất cả các số tự nhiên n thỏa mãn 5n+14 chia hết cho n+2
\(n\in N\Rightarrow n+2\in N\)
\(5n+14⋮n+2\Rightarrow5n+10+4⋮n+2\Rightarrow5\left(n+2\right)+4⋮n+2\)
Mà \(5\left(n+2\right)⋮n+2\Rightarrow4⋮n+2\Rightarrow n+2\inƯ\left(4\right)=\left\{1;2;4\right\}\Rightarrow n\in\left\{-1;0;2\right\}\)
Mà \(n\in N\Rightarrow n\in\left\{0;2\right\}\)
a, (10/3:x).(-5/4)=-10/3
10/3:x=-10/3:(-5/4)
10/3:x=8/3
x=10/3:8/3
x=5/4
b,(-6/5+x):(-18/5)=-1/4
-6/5+x=-1/4.(-18/5)
-6/5+x=9/10
x=9/10-(-6/5)=9/10+6/5
x=21/10
c,-22/15.x+1/3=-2/5
-22/15.x=-2/5-1/3=-11/15
x=-11/15:(-22/15)
x=11/21
d,(0,25-30%x).1/3=-31/6+1/4=-59/12
1/4-3/10x=-59/12:1/3=-59/4
3/10x=1/4-(-59/4)=1/4+59/4=15
x=15:3/10
x=50
e,(0,5x-3/7):1/2=8/7
1/2x=8/7.1/2=4/7
x=4/7:1/2
x=8/7
c) {[(20 - 2.3).5] - 2.5} : 2 + (4.5)²
= {(20 - 6).5] - 10} : 2 + 20²
= (14.5 - 10) : 2 + 400
= (70 - 10) : 2 + 400
= 60 : 2 + 400
= 30 + 400
= 430
d) (1² + 2² + 3² + ... + 100²) . (2⁴ - 4²)
= (1² + 2² + 3² + ... + 100²) . (16 - 16)
= (1² + 2² + 3² + ... + 100²) . 0
= 0
Bài 2
a) -2x < 5
2x > 5
x > 5/2
b) [31 - (x + 5)].11 = 121
31 - (x + 5) = 121 : 11
31 - (x + 5) = 11
x + 5 = 31 - 11
x + 5 = 20
x = 20 - 5
x = 15
c) (x + 1)³ = 27
(x + 1)³ = 3³
x + 1 = 3
x = 3 - 1
x = 2
\(5^{x-1}+5^x+5^{x+1}=31\)
=>\(5^x\cdot\dfrac{1}{5}+5^x+5^x\cdot5=31\)
=>\(5^x\left(\dfrac{1}{5}+1+5\right)=31\)
=>\(5^x\cdot\dfrac{31}{5}=31\)
=>\(5^x=31:\dfrac{31}{5}=5\)
=>x=1