Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.
1/13.58.4+32.26.2+52.10
=52.58+52.32+52.10
=52(58+32+10)=52.100=5200
2/15.37.4+120.21+21.5.12
=60.37+120.21+60.21
=60(37+2.21+21)=60.100=6000
Bài 1:
a) \(\frac{16}{15}.\frac{\left(-5\right)}{14}.\frac{54}{24}.\frac{56}{21}\)
\(=\frac{4.2.2}{5.3}.\frac{\left(-5\right)}{2.7}.\frac{3.3}{4}.\frac{8}{3}\)
\(=\frac{4.2.2.\left(-5\right).3.3.8}{5.3.2.7.4.3}\)
\(=\frac{-16}{7}\)
b) \(\frac{7}{3}.\frac{\left(-5\right)}{2}.\frac{15}{21}.\frac{4}{\left(-5\right)}\)
\(=\frac{7}{3}.\frac{\left(-5\right)}{2}.\frac{5}{7}.\frac{2.2}{\left(-5\right)}\)
\(=\frac{7.\left(-5\right).5.2.2}{3.2.7.\left(-5\right)}\)
\(=\frac{10}{3}\)
Bài 2:
a) \(\frac{21}{24}.\frac{11}{9}.\frac{5}{7}=\frac{7}{8}.\frac{11}{9}.\frac{5}{7}=\frac{11.5}{8.9}=\frac{55}{72}\)
b) \(\frac{5}{23}.\frac{17}{26}+\frac{5}{23}.\frac{9}{26}\)
\(=\frac{5}{23}.\left(\frac{17}{26}+\frac{9}{26}\right)=\frac{5}{23}.1=\frac{5}{23}\)
c) \(\left(\frac{3}{29}-\frac{1}{5}\right).\frac{29}{3}=\frac{3}{29}.\frac{29}{3}-\frac{1}{5}.\frac{29}{3}\)
\(=1-1\frac{14}{15}=\frac{14}{15}\)
Bài 3:
a) x/5 = 2/5
=> x =2
b) -4/x = 20/14 = 10/7
=> -4/x = 10/7
=> x.10 = (-4).7
x.10 = - 28
x= -28 :10
x= -2,8
c) 4/7 = 12/x = 12/ 21
=> 12/x = 12/21
=> x = 21
d) 3/7 = x / 21 = 9/21
=> x/21 = 9/21
=> x= 9
\(x\left(x-2\right)=0\)
\(\Rightarrow\orbr{\begin{cases}x=0\\x-2=0\end{cases}}\)
\(\Rightarrow\orbr{\begin{cases}x=0\\x=2\end{cases}}\)
`5`
`a, -7/21 +(1+1/3)`
`=-7/21 + ( 3/3 + 1/3)`
`=-7/21+ 4/3`
`=-7/21+ 28/21`
`= 21/21`
`=1`
`b, 2/15 + ( 5/9 + (-6)/9)`
`= 2/15 + (-1/9)`
`= 1/45`
`c, (9-1/5+3/12) +(-3/4)`
`= ( 45/5-1/5 + 3/12)+(-3/4)`
`= ( 44/5 + 3/12)+(-3/4)`
`= 9,05 +(-0,75)`
`=8,3`
`6`
`x+7/8 =13/12`
`=>x= 13/12 -7/8`
`=>x=5/24`
`-------`
`-(-6)/12 -x=9/48`
`=> 6/12 -x=9/48`
`=>x= 6/12-9/48`
`=>x=5/16`
`---------`
`x+4/6 =5/25 -(-7)/15`
`=>x+4/6 =1/5 + 7/15`
`=> x+ 4/6=10/15`
`=>x=10/15 -4/6`
`=>x=0`
`----------`
`x+4/5 = 6/20 -(-7)/3`
`=>x+4/5 = 6/20 +7/3`
`=>x+4/5 = 79/30`
`=>x=79/30 -4/5`
`=>x= 79/30-24/30`
`=>x= 55/30`
`=>x= 11/6`
\(5)\)
\(A=\dfrac{-7}{21}+\left(1+\dfrac{1}{3}\right)\)
\(A=\dfrac{-7}{21}+\dfrac{4}{3}\)
\(A=\dfrac{-7}{21}+\dfrac{28}{21}\)
\(A=1\)
\(--------------\)
\(B=\dfrac{2}{15}+\left(\dfrac{5}{9}+\dfrac{-6}{9}\right)\)
\(B=\dfrac{2}{15}+\dfrac{-1}{9}\)
\(B=\dfrac{18}{135}+\dfrac{-15}{135}\)
\(B=\dfrac{1}{45}\)
\(------------\)
\(C=9-\dfrac{1}{5}+\dfrac{3}{12}+\dfrac{-3}{4}\)
\(C=\dfrac{44}{5}+\dfrac{3}{12}+\dfrac{-3}{4}\)
\(C=\dfrac{528}{60}+\dfrac{15}{60}+\dfrac{-3}{4}\)
\(C=\dfrac{181}{20}+\dfrac{-3}{4}\)
\(C=\dfrac{181}{20}+\dfrac{-15}{20}\)
\(C=\dfrac{83}{10}\)
\(6)\)
\(a)\) \(x+\dfrac{7}{8}=\dfrac{13}{12}\)
\(x=\dfrac{13}{12}-\dfrac{7}{8}\)
\(x=\dfrac{104}{96}-\dfrac{84}{96}\)
\(x=\dfrac{5}{24}\)
\(b)\) \(\dfrac{-6}{12}-x=\dfrac{9}{48}\)
\(\dfrac{-1}{2}-x=\dfrac{3}{16}\)
\(x=\dfrac{-1}{2}-\dfrac{3}{16}\)
\(x=\dfrac{-8}{16}-\dfrac{3}{16}\)
\(x=\dfrac{-11}{16}\)
\(c)\) \(x+\dfrac{4}{6}=\dfrac{5}{25}-\left(-\dfrac{7}{15}\right)\)
\(x+\dfrac{4}{6}=\dfrac{5}{25}+\dfrac{7}{15}\)
\(x+\dfrac{4}{6}=\dfrac{75}{375}+\dfrac{105}{375}\)
\(x+\dfrac{4}{6}=\dfrac{12}{25}\)
\(x=\dfrac{12}{25}-\dfrac{4}{6}\)
\(x=\dfrac{72}{150}-\dfrac{100}{150}\)
\(x=\dfrac{-14}{75}\)
\(d)\) \(x+\dfrac{4}{5}=\dfrac{6}{20}-\left(-\dfrac{7}{3}\right)\)
\(x+\dfrac{4}{5}=\dfrac{6}{20}+\dfrac{7}{3}\)
\(x+\dfrac{4}{5}=\dfrac{18}{60}+\dfrac{140}{60}\)
\(x+\dfrac{4}{5}=\dfrac{79}{30}\)
\(x=\dfrac{79}{30}-\dfrac{4}{5}\)
\(x=\dfrac{79}{30}-\dfrac{24}{30}\)
\(x=\dfrac{11}{6}\)
Trl :
15 x 37 x 4 + 120 x 2 + 21 x 5 x 12
= 15 x 4 x 37 + 60 x 2 x 2 + 21 x 5 x 12
= 60 x 37 + 60 x 4 + 21 x 60
= 60 x ( 37 + 4 + 21 )
= 60 x 62
= 60 x 62
= 3720
Hok tốt ~
Hơi nhiều đấy
e) (x + 12)(x - 3) = 0
=> x + 12 = 0 hay x - 3 = 0
=> x = -12 I => x = 3
Vậy x = -12 hay x = 3
g) (-x + 5)(3 - x) = 0
=> -x + 5 = 0 hay 3 - x = 0
=> -x = -5 I => x = 3
=> x = 5
Vậy x = 5 hay x = 3
h) (x - 1)(x - 2) - (-x - 3) = 0
=> (x - 1)(x - 2) + x + 3 = 0
Từ đây sẽ là cách giải lớp 7 (ko biết có áp dụng vào được ko do chương trình lớp 6 ko có phần này)
=> (x2 - 2x - x + 2) + x + 3 = 0
=> x2 - 3x + x + 2 + 3 = 0
Từ đây sẽ là cách giải lớp 8 (ko biết có áp dụng vào được ko do chương trình lớp 6 ko có phần này)
=> x2 - 2x + 1 + 5 = 0
=> (x - 1)(x - 1) + 5 = 0
=> (x - 1)2 + 5 = 0 (vô lí)
Vậy x = O
Bài 3: Tính hợp lý:
a) (15 + 37) + (52 - 37 - 17)
= 15 + 37 + 52 - 37 - 17
= (37 - 37) + (52 - 17 + 15)
= 0 + 50
= 50
b) Cách 1:
(38 - 42 + 14) - (23 - 21 + 10)
= 38 - 42 + 14 - 23 + 21 - 10
= (38 + 14 + 21) - (42 + 23 + 10)
= 73 - 75
= -2
Cách 2:
(38 - 42 + 14) - (23 - 21 + 10)
= 38 - 42 + 14 - 23 + 21 - 10
= (-23 + 21) + (38 - 42) + (14 - 10)
= -2 - 4 + 4
= -2 + 0
= -2
c) -(21 - 32) - (-12 + 32)
= -21 + 32 + 12 - 32
= (-21 + 12) + (32 - 32)
= -9 + 0
= -9
d) -(12 + 21 - 23) - (23 - 21 + 10)
= -12 - 21 + 23 - 23 + 21 - 10
= (-12 - 10) + (-21 + 21) + (23 - 23)
= -22 + 0 + 0
= -22
e) (57 - 752) - (605 - 53)
= 57 - 752 - 605 + 53
= (57 + 53) - (752 + 605)
= 110 - 1357
= -1247
g) (55 + 45 + 15) - (15 - 55 + 45)
= 55 + 45 + 15 - 15 + 55 - 45
= (55 + 55) + (45 - 45) + (15 - 15)
= 110 + 0 + 0
= 110
1. a, => -12x+60+21-7x = 5
=> 81 - 19x = 5
=> 19x = 81 - 5 = 76
=> x = 76 : 19 = 4
Tk mk nha
`15\times37\times4+120\times21+21\times5\times12`
`= (15\times4)\times37+60\times2\times21+21\times(5\times12)`
`= 60\times37+60\times42+21\times60`
`= 60\times(37+42+21)`
`= 60\times100`
`= 6000`
$15 \times 37 \times 4 + 120 \times 21 + 21 \times 5 \times 12$
$ = 15 \times 37 \times 4+ 60 \times 2 \times 21 + 21 \times 5 \times 12$
$ = 60 \times 37 + 60 \times 42 + 21 \times 60$
$ = 60 \times (37 + 42 + 21)$
$ = 60 \times 100$
$ = 6000$