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7 tháng 7 2015

đặt A=(3+1)(32+1)(34+1)(38+1)(316+1)(332+1)

=>2A=2.(3+1)(32+1)(34+1)(38+1)(316+1)(332+1)

=>2A=(3-1)(3+1)(32+1)(34+1)(38+1)(316+1)(332+1)

=(32-1)(32+1)(34+1)(38+1)(316+1)(332+1)

=(34-1)(34+1)(38+1)(316+1)(332+1)

=(38-1)(38+1)(316+1)(332+1)

=(316-1)(316+1)(332+1)

=(332-1)(332+1)

=364-1

=>2A=\(\frac{3^{64}-1}{2}\)

15 tháng 7 2018

bạn ơi: A=\(\frac{3^{64}-1}{2}\) chứ ko phải 2A=\(\frac{3^{64}-1}{2}\)

27 tháng 12 2016

A=\(\left(3-1\right)\left(3+1\right)\left(3^2+1\right)\left(3^4+1\right)\left(3^8+1\right)\left(3^{16}+1\right)\left(3^{16}+1\right)\)

\(=\left(3^2-1\right)\left(3^2+1\right)\left(3^4+1\right)\left(3^8+1\right)\left(3^{16}+1\right)\left(3^{32}+1\right)\)

\(=\left(3^4-1\right)\left(3^4+1\right)\left(3^8+1\right)\left(3^{16}+1\right)\left(3^{32}+1\right)\)

\(=\left(3^8-1\right)\left(3^8+1\right)\left(3^{16}+1\right)\left(3^{32}+1\right)=\left(3^{16}-1\right)\left(3^{16}+1\right)\left(3^{32}+1\right)\)

\(=\left(3^{32}-1\right)\left(3^{32}+1\right)=3^{64}-1\)

15 tháng 9 2019

\(A=\left(3+1\right)\left(3^2+1\right)\left(3^4+1\right)\left(3^8+1\right)\left(3^{16}+1\right)\)

\(\Leftrightarrow2A=\left(3-1\right)\left(3+1\right)\left(3^2+1\right)\left(3^4+1\right)\left(3^8+1\right)\left(3^{16}+1\right)\)

\(\Leftrightarrow2A=\left(3^2-1\right)\left(3^2+1\right)\left(3^4+1\right)\left(3^8+1\right)\left(3^{16}+1\right)\)

\(\Leftrightarrow2A=\left(3^4-1\right)\left(3^4+1\right)\left(3^8+1\right)\left(3^{16}+1\right)\)

\(\Leftrightarrow2A=\left(3^8-1\right)\left(3^8+1\right)\left(3^{16}+1\right)\)

\(\Leftrightarrow2A=\left(3^{16}-1\right)\left(3^{16}+1\right)\)

\(\Leftrightarrow2A=3^{32}-1\)

\(\Leftrightarrow A=3^{31}-\frac{1}{2}\)

4 tháng 10 2020

Đặt A = ( 3 + 1 )( 32 + 1 )( 34 + 1 )( 38 + 1 )( 316 + 1 )( 332 + 1 )

=> 2A = 2.( 3 + 1 )( 32 + 1 )( 34 + 1 )( 38 + 1 )( 316 + 1 )( 332 + 1 )

          = ( 3 - 1 )( 3 + 1 )( 32 + 1 )( 34 + 1 )( 38 + 1 )( 316 + 1 )( 332 + 1 )

          = ( 32 - 1 )( 32 + 1 )( 34 + 1 )( 38 + 1 )( 316 + 1 )( 332 + 1 )

          = ( 34 - 1 )( 34 + 1 )( 38 + 1 )( 316 + 1 )( 332 + 1 )

          = ( 38 - 1 )( 38 + 1 )( 316 + 1 )( 332 + 1 )

          = ( 316 - 1 )( 316 + 1 )( 332 + 1 )

          = ( 332 - 1 )( 332 + 1 )

          = 364 - 1

2A = 364 - 1 => A = \(\frac{3^{64}-1}{2}\)

17 tháng 9 2016

\(8\left(3^2+1\right)\left(3^4+1\right)\left(3^8+1\right)\left(3^{16}+1\right)\)

\(=\left(3^2-1\right)\left(3^2+1\right)\left(3^4+1\right)\left(3^8+1\right)\left(3^{16}+1\right)\)

\(=\left(3^4-1\right)\left(3^4+1\right)\left(3^8+1\right)\left(3^{16}+1\right)\)

\(=\left(3^8-1\right)\left(3^8+1\right)\left(3^{16}+1\right)\)

\(=\left(3^{16}-1\right)\left(3^{16}+1\right)\)

\(=3^{32}-1\)

27 tháng 7 2017

1,       (x-1)3-(x-1)(x2+x+1)

   =  x-3x21+3x1+1-(x3-13)

   = x-3x21+3x1+1-x3 +1

   = x3-x3-3x21+3x1+1+1

   =   -3x21+3x1+2

2,       (x+3)(x2-3x+9)-(3+x)

   = x3+33 -(9+3.32x+3.3.x+ x3)

  = x3+3-(9+ 27x+9x2+x3)

= x3+9 -9-27x-9x2-x3

  =x3​-x3+9 -9-27x-9x2

=-27x-9x2

c thay dấu làm tg tự như những con trên í 

Bài 2:

\(=\left(x-1\right)^3-3\left(x-1\right)^2\cdot\left(x+1\right)+3\left(x-1\right)\cdot\left(x+1\right)^2-\left(x+1\right)^3\)

\(=\left(x-1-x-1\right)^3=\left(-2\right)^3=-8\)

8 tháng 7 2019

3. ( 22 + 1 ).( 24 + 1 ).( 28 + 1 )......( 264 + 1 ) + 1

= ( 22 - 1 ).( 22 + 1 ).( 24 + 1 ).( 28 + 1 )....( 264 + 1 ) + 1

= ( 24 - 1 ).( 24 + 1 ).( 28 + 1 )......( 264 + 1 ) + 1

= ( 28 + 1 ).....( 264 + 1 )  + 1

= ( 264 - 1 ).( 264 + 1 ) + 1

=  2128 - 1 + 1

= 2128

8 tháng 7 2019

8.( 32 + 1 ).( 34 + 1 ).( 38 + 1 )....( 3128 + 1 ) + 1

= ( 32 - 1 ).( 32 + 1 ).( 34 + 1 ).( 38 + 1 )....( 3128 + 1 ) + 1

= ( 34 - 1 ).( 34 + 1 ).( 38 + 1 )....( 3128 + 1 ) + 1

= ( 38 - 1 ).( 38 + 1 )....( 3128 + 1 ) + 1

= ( 316 - 1 )......( 3128 + 1 ) + 1

= ( 3128 - 1 ).( 3128 + 1 ) + 1

=  3256 - 1 + 1

= 3256