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Ta có: \(Ư\left(250\right)\in\left\{1;2;5;10;25;50;125;250\right\}\)
Nếu bạn học số âm rồi thì:
\(Ư\left(250\right)\in\left\{\pm1;\pm2;\pm5;\pm10;\pm25;\pm50;\pm125;\pm250\right\}\)
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Bài toán 1 : Viết các tập hợp sau.
a)Ư:(6,9,12) d) B(23) ; B(10) ; B(8)
b)Ư(7) ; Ư(18) ; Ư(10) e) B(3) ; B(12) ; B(9)
c)Ư(15) ; Ư(16) ; Ư(250 g) B(18) ; B(20) ; B(14)
\(a)\)
\(Ư (6) = \) \(\left\{1;2;3;6\right\}\)
\(Ư\left(9\right)=\left\{1;3;9\right\}\)
\(Ư\left(12\right)=\left\{1;2;3;4;6;12\right\}\)
\(b)\)
\(Ư\left(7\right)=\left\{1;7\right\}\)
\(Ư\left(18\right)=\left\{1;2;3;6;9;18\right\}\)
\(Ư\left(10\right)=\left\{1;2;5;10\right\}\)
\(c)\)
\(Ư\left(15\right)=\left\{1;3;5;15\right\}\)
\(Ư\left(16\right)=\left\{1;2;4;8;16\right\}\)
\(Ư\left(250\right)=\left\{1;2;5;10;25;50;125;250\right\}\)
\(d)\)
\(B\left(23\right)=\left\{0;23;46;69;...\right\}\)
\(B\left(10\right)=\left\{0;10;20;30;...\right\}\)
\(B\left(8\right)=\left\{0;8;16;24;...\right\}\)
\(e)\)
\(B\left(3\right)=\left\{0;3;6;9;...\right\}\)
\(B\left(12\right)=\left\{0;12;24;36;...\right\}\)
\(B\left(9\right)=\left\{0;9;18;27;...\right\}\)
\(g)\)
\(B\left(18\right)=\left\{0;18;36;54;...\right\}\)
\(B\left(20\right)=\left\{0;20;40;60;...\right\}\)
\(B\left(14\right)=\left\{0;14;28;42;...\right\}\)
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\(Ư_{\left(15\right)}=\left\{\pm1;\pm3;\pm5;\pm15\right\}\)
\(B_{\left(15\right)}=\left\{0;\pm15;\pm30;\pm45;....\right\}\)
1/
\(Ư_{\left(5\right)}=\left\{\pm1;\pm5\right\}\)
\(B_{\left(5\right)}=\left\{0;\pm5;\pm10;,...\right\}\)
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a) U(-5) = {-5;-1;1;5}
U(-27) = {-27;-9;-3;-1;1;3;9;27}
U(35) = {-35;-7;-5;-1;1;5;7;35}
b) 8 bội của - 9 là: 0;9;18;-18 ; -9 ; -72 ; -63 ; 36
8 bội của 15 là: 0;15;30;45;-75;75 ; -15 ; -30
8 bội của 17 là: 0;17;34;-17;-34; 51 ; -51 ; 68
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1 / Ta có : Ư ( 250 ) = { 1 ; 2 ; 5 ; 10 ; ... ; 250 }
2 / Ta có : B ( 11 ) = { 0 ; 11 ; 22 ; 33 ; ... }
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c1 : Ư(6) = {1;2;3;6}
Ư(12) = {1;2;3;4;6;12}
Ư(42) = {1;2;3;6;7;14;21;42}
ƯC(6;12;42) ={1;2;3;6}
c2 : phân tích các số thành thừa số nguyên tố
6 = 2 x 3
15 = 3 x 5
42 = 2 x 3 x 7
---> ưcln ( 6,15,42 ) = 2 x 3 = 6
ưc ( 6 , 15 , 42 ) = ư ( 6 ) = { 1 ; 2 ; 3 ; 6 }
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\(250=5^3\cdot2\)
=>\(Ư\left(250\right)=\left\{1;-1;2;-2;5;-5;10;-10;25;-25;50;-50;125;-125;250;-250\right\}\)
\(Ư\left(250\right)\)\(=\left\{1;2;5;10;25;50;125;250\right\}\)