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/x+2/=0\(\Rightarrow x+2=0\Rightarrow x=0-2=-2\)
/x-3/=7-(-2)=9\(\Rightarrow x=9+3=12ho\text{ặc}x=-9+3=-6\)
(7-x)-(25+7)=-25\(\Rightarrow\left(7-x\right)-32=-25\Rightarrow7-x=-25+32=7\Rightarrow x=0\)
/x-3/=/5/+/-7/=5+7=12\(\Rightarrow x=15ho\text{ặc}x=-9\)
/x-5/=/-7/=7\(\Rightarrow x=12ho\text{ặc}x=-2\)
4-(7-x)=x-(13-4)\(\Rightarrow x-3=x-9\Rightarrow x-x=-9+3\Rightarrow0=-6\)(vô lí)
Vậy không có x thoả mãn 4-(7-x)=x-(13-4)
|x+2|=0
Vì |0|=0,suy ra x+2=0
x=0-2
x=-2
Vậy x = -2
|x-3|=7-(-2)
|x-3|=7+2
|x-3|=9
Vì |9|=|-9|=9,suy ra x-3 thuộc{9;-9}
*x-3=9
x =9+3
x =12
*x-3=-9
x=-9+3
x=-6
Vậy x thuộc {12;-6}
a, \(\left|x+3\right|=15\)
TH1 : \(x+3=15\Leftrightarrow x=12\)
TH2 : \(x+3=-15\Leftrightarrow x=-18\)
b, \(\left|x-7\right|+13=15\Leftrightarrow\left|x-7\right|=2\)
TH1 : \(x-7=2\Leftrightarrow x=9\)
TH2 : \(x-7=-2\Leftrightarrow x=5\)
c, \(\left|x-3\right|-16=-4\Leftrightarrow\left|x-3\right|=12\)
TH1 : \(x-3=12\Leftrightarrow x=15\)
TH2 : \(x-3=-12\Leftrightarrow x=-9\)
d, \(26-\left|x+9\right|=-13\Leftrightarrow\left|x+9\right|=39\)
TH1 : \(x+9=39\Leftrightarrow x=30\)
TH2 : \(x+9=-39\Leftrightarrow x=-48\)
a) Ta có: \(x-12=\left(-9\right)-15\)
\(\Rightarrow x-12=-24\)
\(\Rightarrow x=-12\)
b) \(2-x=17-\left(-5\right)\)
\(\Rightarrow2-x=22\)
\(\Rightarrow x=2-22\)
\(\Rightarrow x=-20\)
c) \(11-\left(15+11\right)=x-\left(25-9\right)\)
\(\Rightarrow-15=x-16\)
\(\Rightarrow x=1\)
d) \(x-\left(17-x\right)=x-7\)
\(\Rightarrow x-17+x=x-7\)
\(\Rightarrow x+x-x=-7+17\)
\(\Rightarrow x=10\)
e) \(9-25=\left(7-x\right)-\left(25+7\right)\)
\(\Rightarrow9-25=7-x-25-7\)
\(\Rightarrow-16=-25-x\)
\(\Rightarrow x=-9\)
g) \(x-13=21-x\)
\(\Rightarrow x+x=21+13\)
\(\Rightarrow2x=34\)
\(\Rightarrow x=17\)
a, x - 12 = ( -9 ) - 15
x - 12 = -24
x = -24 + 12
x = -12
b, 2 - x = 17 - ( -5 )
2 - x = 22
x = 2 - 22
x = -20
c, 11 - ( 15 + 11 ) = x - ( 25 - 9 )
11 - 26 = x - 16
-15 = x - 16
x = -15 + 16
x = 1
d, x - ( 17 - x ) = x - 7
x - 17 + x = x - 7
x + x - 17 = x - 7
x + x - x = -7 + 17
x = 10
e.9 - 25 = ( 7- x ) - ( 25 + 7 )
-16 = ( 7 - x ) -32
7 - x = -32 + 16
7 - x = 16
x = 7 - 16
x= -9
g, x - 13 = 21 - x
x + x = 21 + 13
2x = 44
x = 44 : 2
x=22
`(x + 7) - 25 = 13`
`=> x +7 = 13 + 25`
`=> x+ 7 = 38`
`=> x = 38 - 7`
`=> x = 31`
Vậy `x=31`
\(\left(x+7\right)-25=13\)
\(x+7=13+25\)
\(x+7=38\)
\(x=38-7\)
\(x=31\)
vậy x = 31