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Cách 1:
Xét số bị trừ, ta có:
(2/3 + 3/4 + 4/5 + ... + 2016/2017) x (1/2 + 2/3 + 3/4 + ... + 2015/2016)
= (2/3 + 3/4 + 4/5 + ... + 2015/2016 + 2016/2017) x (1/2 + 2/3 + 3/4 + ... + 2015/2016)
= (2/3 + 3/4 + 4/5 + ... + 2015/2016) x (1/2 + 2/3 + 3/4 + ... + 2015/2016) + 2016/2017 x (1/2 + 2/3 + 3/4 + ... + 2015/2016)
Xét số trừ, ta có:
(1/2 + 2/3 + 3/4 + ... + 2016/2017) x (2/3 + 3/4 + 4/5 + ... + 2015/2016)
= (1/2 + 2/3 + 3/4 + ... + 2015/2016 + 2016/2017) x (2/3 + 3/4 + 4/5 + ... + 2015/2016)
= (1/2 + 2/3 + 3/4 + ... + 2015/2016) x (2/3 + 3/4 + 4/5 + ... + 2015/2016) + 2016/2017 x (2/3 +3/4 + 4/5 + ... + 2015/2016) =
Ta thấy số bị trừ và số trừ có số hạng giống nhau là:
(2/3 +3/4 + 4/5 + ... + 2015/2016) x (1/2 + 2/3 + 3/4 + ... + 2015/2016)
Nên phép trừ trên có thể viết lại:
2016/2017 x (1/2 + 2/3 + 3/4 + ... + 2015/2016) - 2016/2017 x (2/3 + 3/4 + 4/5 + ... + 2015/2016)
= 2016/2017 x [(1/2 + 2/3 + 3/4 + ... + 2015/2016) - (2/3 +3/4 + 4/5 + ... + 2015/2016)]
= 2016/2017 x 1/2
= 1008/2017
Cách 2:
a. \(\left(\dfrac{1}{3}+\dfrac{2}{3}\right)+\dfrac{3}{4}=1+\dfrac{3}{4}=\dfrac{7}{4}\)
b. \(\dfrac{3}{4}+\dfrac{3}{5}+\dfrac{2}{8}+\dfrac{4}{10}=\left(\dfrac{3}{4}+\dfrac{2}{8}\right)+\left(\dfrac{3}{5}+\dfrac{4}{10}\right)=1+1=2\)
a ) `1/3 + 3/4 + 2/3 + 1/4 `
`= (1/3 + 2/3 )+ (3/4 + 1/4)`
`= 1 + 1 `
`= 2
b 3/4 + 3/5 + 2 phần 8 + 4/10`
`= (3/4 + 2/8 ) + ( 3/5 + 4/10 ) `
`= 1 + 1 `
`= 2`
A = 4\(\dfrac{1}{3}\) + 3\(\dfrac{3}{4}\) + 2 - \(\dfrac{2}{5}\) + 8 - \(\dfrac{3}{5}\) + 7 - \(\dfrac{1}{4}\) + 6 - \(\dfrac{2}{3}\)
A = \(\dfrac{13}{3}\) + \(\dfrac{15}{4}\) + ( 2 + 8 + 6 + 7) - ( \(\dfrac{2}{5}\) + \(\dfrac{3}{5}\)) - \(\dfrac{1}{4}\) - \(\dfrac{2}{3}\)
A = \(\dfrac{13}{3}\) + \(\dfrac{15}{4}\) + 23 - 1 - \(\dfrac{1}{4}\) - \(\dfrac{2}{3}\)
A = ( \(\dfrac{13}{3}\) - \(\dfrac{2}{3}\)) + 22 +( \(\dfrac{15}{4}\) - \(\dfrac{1}{4}\) )
A = \(\dfrac{11}{3}\) + 22 + \(\dfrac{14}{4}\)
A = \(\dfrac{11}{3}\) + 22 + \(\dfrac{7}{2}\)
A = \(\dfrac{22}{6}\) + \(\dfrac{132}{6}\) + \(\dfrac{21}{6}\)
A = \(\dfrac{175}{6}\)
a) Cách 1 : (3/4 + 1/2) x 5/7
= 5/4 x 5/7
= 25/28
Cách 2 : (3/4 + 1/2) x 5/7
= 3/4 x 5/7 + 1/2 x 5/7
= 15/28 + 5/14
= 25/28
b) Cách 1 : 5/7 x 13/21 + 2/7 x 13/21
= 65/147 + 26/147
= 13/21
Cách 2 : 5/7 x 13/21 + 2/7 x 13/21
= (5/7 + 2/7) x 13/21
= 1 x 13/21
= 13/21
câu c tự làm
a)
`1/3+3/4+2/3+1/4`
`=1/3+2/3+3/4+1/4`
`=1+1`
`=2`
b)
`3/4+3/5+2/8+4/10`
`=3/4+2/8+3/5+4/10`
`=6/8+2/8+6/10+4/10`
`=1+1`
`=2`
c)
`1/10+2/10+3/10+4/10+5/10+6/10+7/10+8/10+9/10`
`=1/10+9/10+2/10+8/10+3/10+7/10+6/10+4/10+5/10`
`=1+1+1+1+5/10`
`=4+5/10`
`=40/10+5/10`
`=45/10=9/2`
a: =1/3+2/3+3/4+1/4
=1+1
=2
b: =3/4+1/4+3/5+2/5
=1+1
=2
c: =(1+2+3+4+5+6+7+8+9)/10
=45/10
=9/2
A = \(\dfrac{1}{2}\)+ \(\dfrac{1}{3}\)+ \(\dfrac{1}{4}\)+ \(\dfrac{1}{2}\)+ \(\dfrac{2}{3}\)+ \(\dfrac{3}{4}\)
A = ( \(\dfrac{1}{2}\)+ \(\dfrac{1}{2}\)) + ( \(\dfrac{1}{4}\)+\(\dfrac{3}{4}\)) +( \(\dfrac{1}{3}\)+ \(\dfrac{2}{3}\))
A = 1 + 1 + 1
A = 3
B = ( \(\dfrac{3}{4}\) + \(\dfrac{5}{7}\)+ \(\dfrac{16}{64}\)+ \(\dfrac{2}{7}\)) - 2
B = ( \(\dfrac{3}{4}\)+ \(\dfrac{1}{4}\)) + ( \(\dfrac{5}{7}\)+ \(\dfrac{2}{7}\)) - 2
B = 1 + 1 - 2
B = 2 - 2
B = 0
(2/3+3/4)+1/4
= 17/12+1/4
=5/3
(2/3+3/4)+1/4
= 17/12+1/4
=5/3