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\(7^{2x}+7^{2x+2}=2450\)
\(7^{2x}.1+7^{2x}.7^2=2450\)
\(7^{2x}.\left(1+7^2\right)=2450\)
\(7^{2x}.\left(1+49\right)=2450\)
\(7^{2x}.50=2450\)
\(7^{2x}=2450:50\)
\(7^{2x}=49\)
\(7^{2x}=7^2\)
\(\Rightarrow2x=2\)
\(x=2:2\)
\(x=1\)
Vậy \(x=1\)
\(7^{2x}+7^{2x+2}=2450\)
\(\Leftrightarrow7^{2x}+7^{2x}.7^2=2450\)
\(\Leftrightarrow7^{2x}.\left(1+7^2\right)=2450\)
\(\Leftrightarrow7^{2x}.50=2450\)
\(\Leftrightarrow7^{2x}=2450:50\Leftrightarrow7^{2x}=49\)
\(\Leftrightarrow7^{2x}=7^2\Leftrightarrow2x=2\)
\(\Leftrightarrow x=1\)
\(7^{2x}+7^{2x+2}=2450\)
\(\Rightarrow7^{2x}\left(1+7^2\right)=2450\)
\(\Rightarrow7^{2x}\cdot50=2450\)
\(\Rightarrow7^{2x}=49=7^2\)
\(\Rightarrow2x=2\Rightarrow x=1\)
\(\dfrac{x-2}{x-1}=\dfrac{x+4}{x+7}\)
Áp dụng tính chất dãy tỉ số bằng nhau ta có:
\(\dfrac{x-2}{x-1}=\dfrac{x+4}{x+7}=\dfrac{x-2-x-4}{x-1-x-7}=\dfrac{-6}{-8}=\dfrac{3}{4}\)
\(\Leftrightarrow\dfrac{x-2}{x-1}=\dfrac{3}{4}\)
\(\Leftrightarrow4x-8=3x-3\)
\(\Leftrightarrow4x=3x+5\)
\(x=5\)
Theo đề , ta có :\(\dfrac{x-2}{x-1}=\dfrac{x+4}{x+7}\)
Theo tính chất của dãy tỉ sô bằng nhau, ta được:
\(\dfrac{x-2}{x-1}=\dfrac{x+4}{x+7}=\dfrac{x-2-x-4}{x-1-x-7}=\dfrac{-6}{-8}=\dfrac{3}{4}\)
\(\Leftrightarrow\dfrac{x-2}{x-1}=\dfrac{3}{4}\Rightarrow4x-8=3x-3\)
\(\Rightarrow4x-3x=8-3\)
\(\Rightarrow1x=5\Rightarrow x=5\)
\(7^{2x}+7^{2x+2}=2450\)
\(7^{2x}\left(1+7^2\right)=2450\)
\(7^{2x}=2450\div50\)
\(7^{2x}=49\)
\(\Rightarrow2x=2\)
\(\Leftrightarrow x=1\)
\(7^{2x}+7^{2x+2}=2450\)
\(\Leftrightarrow7^{2x}+7^{2x}.7^2=2450\)
\(\Leftrightarrow7^{2x}\left(1+7^2\right)=2450\)
\(\Leftrightarrow49^x\left(1+49\right)=2450\)
\(\Leftrightarrow49^x.50=2450\)
\(\Leftrightarrow49^x=2450:50\)
\(\Leftrightarrow49^x=49\)
\(\Rightarrow x=1\)
vậy x=1
a) 2x+2x+3=144
2x . 1 + 2x . 23 = 144
2x . ( 1 + 23 ) = 144
2x . 9 = 144
2x = 144 : 9
2x = 16
2x = 24
=> x = 4
b) 72x + 72x+2 = 2450
72x . 1 + 72x . 72= 2450
72x . ( 1 + 72 ) = 2450
72x . 50 = 2450
72x = 2450 : 50
72x = 49
72x = 72
=> 2x = 2
=> x = 1
Ta có : 2x + 2x + 3 = 144
=> 2x (1 + 23) = 144
=> 2x . 9 = 144
=> 2x = 144 : 9
=> 2x = 16
=> 2x = 24
=> x = 4
72x + 72x+2 = 2450
1.72x + 72x.72 = 2450
72x.(1+72) = 2450
72x.(1+49) = 2450
72x.50 = 2450
72x = 2450 : 50
72x = 49
72x = 72
2x = 2
x = ... (Tự tính)
Vậy x = ...
\(7^{2x}+7^{2x+2}=2450\)
\(1\times7^{2x}+7^{2x}\times7^2=2450\)
\(7^{2x}\left(1+7^2\right)=2450\)
\(\frac{7^{2x}\left(1+7^2\right)}{1+7^2}=\frac{2450}{1+7^2}\)
\(7^{2x}=\frac{2450}{1+49}\)
\(7^{2x}=\frac{2450}{50}\)
\(7^{2x}=49\)
\(7^{2x}=7^2\)
\(2x=2\)
\(x=2\div2\)
\(x=1\)
Học tốt nha.
\(7^{2x}+7^{2x+2}=2450\)
\(7^{2x}+7^{2x}.7^2=2450\)
\(7^{2x}+7^{2x}.49=2450\)
\(7^{2x}\left(1+49\right)=2450\)
\(7^{2x}.50=2450\)
\(7^{2x}=2450:50\)
\(7^{2x}=49\)
\(7^{2x}=7^2\)
\(2x=2\)
=> \(x=1\)
Vậy \(x=1\)
7x.1+7x.72=2450
7x(1+49)=2450
7x.50=2450
7x=2450:50
7x=49=72
=>x=2.
Đây nhé
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