Question

[Nguyen Hai Bang]

Tìm x trong các tỉ lệ thức:

a,-0,52 : x= -9,36 : 16,38

b,\(\frac{x}{-15}\)=\(\frac{-60}{x}\)

c, \(\frac{-2}{x}\)=\(\frac{-x}{8}\)

d, 3,8 : 2x =\(\frac{1}{4}\):  2\(\frac{2}{3}\)

e, 0,25x : 3 =\(\frac{5}{6}\):  0,125

Answer 1

[nguyen van huy]

\(a,-0,52:x=-9,36:16,38\)

\(\Leftrightarrow\frac{-13}{25}:x=\frac{-4}{7}\)

\(\Leftrightarrow x=\frac{-13}{25}:\frac{-4}{7}\)

\(\Leftrightarrow x=\frac{91}{100}\)

\(b,\frac{x}{-15}=\frac{-60}{x}\)

\(\Leftrightarrow x^2=900\)

\(\Leftrightarrow x^2=\left(30,-30\right)^2\)

\(\Leftrightarrow\orbr{\begin{cases}x=30\\x=-30\end{cases}}\)

\(c,\frac{-2}{x}=\frac{-x}{8}\)

\(\Leftrightarrow-\left(x^2\right)=-16\)

\(\Leftrightarrow x^2=16\)

\(\Leftrightarrow x^2=\left(4,-4\right)^2\)

\(\Leftrightarrow\orbr{\begin{cases}x=-4\\x=4\end{cases}}\)

\(d.3,8\div2x=\frac{1}{4}:2\frac{2}{3}\)

\(\Leftrightarrow3,8\div2x=\frac{3}{32}\)

\(\Leftrightarrow2x=3,8\div\frac{3}{32}\)

\(\Leftrightarrow2x=\frac{608}{15}\)

\(\Leftrightarrow x=\frac{608}{15}\div2\)

\(\Leftrightarrow x=\frac{304}{15}\)

\(e.0,25x\div3=\frac{5}{6}:0,125\)

\(\Leftrightarrow0,25x\div3=\frac{20}{3}\)

\(\Leftrightarrow0,25x=\frac{20}{3}.3\)

\(\Leftrightarrow\frac{1}{4}x=20\)

\(\Leftrightarrow x=20:\frac{1}{4}\)

\(\Leftrightarrow x=80\)