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a ) \(\frac{3}{4}\)+ \(\frac{1}{6}\) = \(\frac{18}{24}\)+ \(\frac{4}{24}\)= \(\frac{22}{24}\)
b ) \(\frac{11}{12}\)- \(\frac{3}{4}\)= \(\frac{11}{12}\)- \(\frac{9}{12}\)= \(\frac{2}{12}\)
c ) \(\frac{11}{12}\)- \(\frac{1}{6}\) = \(\frac{11}{12}\)- \(\frac{2}{12}\) = \(\frac{9}{12}\)
d ) \(\frac{1}{6}\)+ \(\frac{3}{4}\)= \(\frac{4}{24}\)+ \(\frac{18}{24}\) = \(\frac{22}{24}\)
Xin lỗi mình không rút gọn nha !
\(\frac{5}{12}+\frac{3}{4}+\frac{1}{3}\)
\(=\frac{5}{12}+\frac{9}{12}+\frac{4}{12}\)
\(=\frac{5+9+4}{12}\)
\(=\frac{18}{12}=\frac{9}{4}\)
\(\frac{1}{4}+\frac{3}{7}+\frac{11}{14}\)
\(=\frac{7}{28}+\frac{12}{28}+\frac{22}{28}\)
\(=\frac{7+12+22}{28}\)
\(=\frac{41}{28}\)
\(\frac{5}{12}\)+\(\frac{3}{4}\)+\(\frac{1}{3}\)=\(\frac{5}{12}\)+\(\frac{9}{12}\)+\(\frac{4}{12}\)=\(\frac{18}{12}\)=\(\frac{3}{2}\)
\(\frac{1}{4}\)+\(\frac{3}{7}\)+\(\frac{11}{14}\)=\(\frac{7+12+22}{28}\)=\(\frac{41}{28}\)
\(A=\frac{3}{7}+\frac{4}{9}+\frac{4}{7}+\frac{7}{11}\)
\(A=1+\frac{4}{9}+\frac{7}{11}\)
\(A==\frac{76}{33}\)
\(B=\frac{1}{8}+\frac{1}{12}+\frac{3}{8}+\frac{5}{12}\)
\(B=\frac{1}{2}+\frac{1}{2}\)
\(B=\frac{1}{4}\)
\(\frac{3}{4}+\frac{1}{6}=\frac{9+2}{12}=\frac{11}{12}\)
\(\frac{11}{12}-\frac{3}{4}=\frac{11-9}{12}=\frac{2}{12}=\frac{1}{6}\)
\(\frac{11}{12}-\frac{1}{6}=\frac{11-2}{12}=\frac{9}{12}=\frac{3}{4}\)
\(\frac{1}{6}+\frac{3}{4}=\frac{2+9}{12}=\frac{11}{12}\)
BÀI 1:
a) \(\frac{4}{5}+\frac{3}{8}+\frac{1}{4}\)
\(=\frac{32}{40}+\frac{15}{40}+\frac{10}{40}\)
\(=\frac{32+15+10}{40}\)\(=\frac{57}{40}\)
b) \(\frac{5}{9}+\frac{2}{3}+\frac{1}{2}\)
\(=\frac{10}{18}+\frac{12}{18}+\frac{9}{18}\)
\(=\frac{10+12+9}{18}=\frac{31}{18}\)
a] 4/12 ; 5/12 ; 11/2 ; 1/4
b] 1 ; 9/12; 12/5 ; 11/3
c] 8/21; 6/11;8/7
d] 2/3 ;2/7 15/2
a]1/3 5/12 11/2 1/4
b]1 3/4 12/5 33/9
c]8/21 6/11 8/7
d]2/3 2/7 15/2
Ta có : 21/11 - 9/19 - 3/19 - 12/38 + 24/22
= (21/11 + 24/22 - (9/19 + 3/19 + 12/38)
= 66/22 + 0
= 3
\(3:\dfrac{3}{4}-\dfrac{77}{12}:11\)
\(=3\times\dfrac{4}{3}-\dfrac{7}{12}=4-\dfrac{7}{12}=\dfrac{48}{12}-\dfrac{7}{12}=\dfrac{41}{12}\)