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\(\left(3x-4x\right)\cdot6=3^3\cdot3^3+2^3+3^2-12^2\)
\(\Leftrightarrow18x-288=3^6+2^3+3^2-12^2\)
\(\Leftrightarrow18x-288=729+8+\left(3-12\right)\cdot\left(3+12\right)\)
\(\Leftrightarrow18x-288=729+8+\left(-9\right)\cdot15\)
\(\Leftrightarrow18x-288=729+8-135\)
\(\Leftrightarrow18x-288=602\)
\(\Leftrightarrow18x=602+288\)
\(\Leftrightarrow18x=890\)
\(\Rightarrow x=\dfrac{445}{9}\)
Vậy \(x=\dfrac{445}{9}\)
(3x-48).6=33.33+23+32-122
(3x-48).6=36+8+9-144
(3x-48).6=729+-127
(3x-48).6= 602
3x-48=\(\dfrac{602}{6}\)
3x=\(\dfrac{602}{6}\)+48
3x=\(\dfrac{445}{3}\Leftrightarrow x=\dfrac{445}{9}\)
a, 3.(x-9)+15=12+243:32
3x-27+15=12+243:9
3x-12=12+27
3x=12+12+27
3x=51
x=17
b, (3x-48).6=33.22+32.23-122
18x-288=32.3.22+32.22.2-(3.2.2)2
18x-288=32.3.22+32.22.2-32.22.22
18x-288= 32.22.(3+2-22)
18x-288= 9.4.(3+2-4)
18x-288=36.1
18x-288=36
18x=36+288
18x=324
x=18
\(\left(19x+2.5^2\right):14=\left(13-8\right)^2-4^2\)
<=> \(\left(19x+50\right):14=25-16\)
<=> \(\left(19x+50\right):14=9\)
<=> \(19x+50=126\)
<=> \(19x=76\)
<=> \(x=4\)
câu B làm j có \(x\)để tìm
\(390-\left(x-7\right)=169:13\)
<=> \(390-x+7=13\)
<=> \(390-x=6\)
<=> \(x=384\)
\(x-6:2-\left(48:24\right):2:6-3=0\)
<=> \(x-3-2:2:6=3\)
<=> \(x-3-\frac{1}{6}=3\)
<=> \(x=\frac{37}{6}\)
\(x+5.2-\left(32+16.3:6-15\right)=0\)
<=> \(x+10-25=0\)
<=> \(x=15\)
1
3\(^5\).5\(^3\)-20.{300-[546-2\(^3\).(7\(^8\):7\(^6\)+7\(^0\))]}
= 243.125-20.{300-[546-8.(49+1)
= 243.125-20.[300-(546-8.50)
= 243.125-20.[300-(546-400)
= 243.125-20.(300-146)
= 243.125-20.154
= 30375-3080
= 27295
\(=10-\left[\left(91-48\right).5+\left(8.10+8\right)\right]:28\)
\(=10-\left[43.5+88\right]:28\)
\(=10-\left[215+88\right]:28\)
\(=10-303:28\)
\(=10-10,821\)
\(=0,179\)
Ko chắc
\(a.\left(5+2\right).x=36-1\)
\(7.x=35\)
\(x=5\)
\(b.\left(5+1\right).x=75+3\)
\(6.x=78\)
\(x=13\)
\(c.\left(6+1\right).x=5^2+3\)
\(7.x=25+3\)
\(7.x=28\)
\(x=4\)
\(d.\left(7-1\right).x=5^2+3.4-1\)
\(6.x=25+12-1\)
\(6.x=36\)
\(x=6\)
a. 1440 : [ 120 - (3x + 9 ) ] = 120
120 - (3x + 9) = 1440 : 120 = 12
3x + 9 = 120 - 12 = 108
3x = 108 - 9 = 99
x = 99 : 3 = 33
b. 120 + [ ( 999 - 9x ) : 60 ] . 24 = 480
[ ( 999 - 9x ) : 60 ] . 24 = 480 - 120 = 360
( 999 - 9x ) : 60 = 360 : 24 = 15
( 999 - 9x ) = 15 . 60 = 900
9x = 999 - 900 = 99
x = 99 : 9 = 11
(3x - 48). 6 = 36 + 4 -135
(3x - 48) . 6 = 598
3x - 48 = 598 : 6 = 99,6
3x = 147,6
x = 49,2
(3x-48).6=33.33+22+32-122
(3x-48).6=36+4+9-144
(3x-48).6=729-131
(3x-48).6=598
3x-48=598:6
3x-48=\(\dfrac{299}{3}\)
3x=\(\dfrac{299}{3}\)+48
3x=\(\dfrac{443}{3}\)
\(\Leftrightarrow x=\dfrac{443}{9}\)