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a, đầu bài sai hay sao đó bn
b,\(\dfrac{2}{3}\).3x+1 - 7.3x = -405
3x(\(\dfrac{2}{3}\).3 - 7) = -405
3x . (-5) = -405
3x = 81 mà 81 = 34 suy ra x = 4
a) \(\frac{2}{3}.3^{x+1}-7.3^x=-405\)
=> \(\frac{2}{3}.3^x.3-7.3^x=-405\)
=> \(2.3^x-7.3^x=-405\)
=> \(3^x\left(2-7\right)=-405\)
=> \(3^x.\left(-5\right)=-405\)
=> \(3^x=-405:\left(-5\right)\)
=> \(3^x=81\)
=> \(x=4\)
b) \(\frac{3}{1-2x}=\frac{-5}{3x-2}\)
=> \(3\left(3x-2\right)=-5\left(1-2x\right)\)
=> \(9x-6=-5+10x\)
=> \(9x-10x=-5+6\)
=> \(-x=1\)
=> \(x=-1\)
a,\(\left(\dfrac{1}{5}-\dfrac{3}{2}x\right)^2=\dfrac{9}{4}\)
\(\dfrac{1}{5}-\dfrac{3}{2}x=\dfrac{3}{2}\)
\(\dfrac{3}{2}x=-\dfrac{13}{10}\)
\(x=-\dfrac{13}{15}\)
b,\(\left(3x+1\right)^3=-27\)
\(3x+1=-3\)
\(3x=-4\)
\(x=-\dfrac{4}{3}\)
a ) \(\left(\dfrac{1}{5}-\dfrac{3}{2}x\right)^2=\dfrac{9}{4}\)
\(\Leftrightarrow\left[{}\begin{matrix}\dfrac{1}{5}-\dfrac{3}{2}x=\dfrac{3}{2}\\\dfrac{1}{5}-\dfrac{3}{2}x=-\dfrac{3}{2}\end{matrix}\right.\)
\(\Leftrightarrow\left[{}\begin{matrix}\dfrac{3}{2}x=-\dfrac{13}{10}\\\dfrac{3}{2}x=\dfrac{17}{10}\end{matrix}\right.\)
\(\Leftrightarrow\left[{}\begin{matrix}x=-\dfrac{13}{15}\\x=\dfrac{17}{15}\end{matrix}\right.\)
Vậy .......
b ) \(\left(3x+1\right)^3=-27\)
\(\Leftrightarrow3x+1=-3\)
\(\Leftrightarrow3x=-4\Leftrightarrow x=-\dfrac{4}{3}\)
Vậy ..........
c ) \(7.3^{x-1}-3^{x+2}=-540\)
\(\Leftrightarrow7.3^{x-1}-3^{x-1}.3^3=-540\)
\(\Leftrightarrow3^{x-1}\left(7-27\right)=-540\)
\(\Leftrightarrow-20.3^{x-1}=-540\)
\(\Leftrightarrow3^{x-1}=27\)
\(\Leftrightarrow x=4\).
Vậy ..........
a, Theo đề ta có:
\(2.3^x-405=3^{x-1}\)
=> \(2.3^x-405=3^x:3\)
=> \(405=(2.3^x)-(3^x:3)\)
=>\(405=(2.3^x)-(3^x.\dfrac{1}{3})\)
=> \(405=3^x(2-\dfrac{1}{3})\)
=>\(405=3^x(\dfrac{6}{3}-\dfrac{1}{3})\)
=> \(405=3^x.\dfrac{5}{3}\)
=> \(3^x=405:\dfrac{5}{3}\)
=>\(3^x=405.\dfrac{3}{5}\)
=> \(3^x=81.3\)
=> \(3^x=243\)
=> \(3^x=3^5\)
=> x=5
Vậy:..............................
a: \(\Leftrightarrow\left(-2\right)^n=\dfrac{128}{2}=64\)
hay n=6
b: \(\Leftrightarrow3^x\cdot\dfrac{7}{3}=7\cdot3^4\)
\(\Leftrightarrow3^x=3^5\)
hay x=5
a)/4.x/-12.5=7.3
/4.x/-60=21
/4.x/=21+60
/4.x/=81
4.x=81 hoặc 4.x=-81
x=81:4 hoặc x=-81:4
x=20,25 hoặc x=-20,25
vậy ....
b)/x/+x=1/3
x+x=1/3
2x=1/3
x=1/3:2
x=1/6
=>/x/=1/6
=>x=+-1/6
c)/x/-x=3/4
TH1 x>=0 TH2 x<0
=>/x/-x khác 3/4 =>/x/-x=3/4
=>x thuộc rỗng =>/x/+x=3/4
=>2x=3/4=>x=3/8
d)/x-2/=x
=>x-2=+-x
=>x-2=x(vô lí) x-2=-x
ta thử có x=1 t/m yêu cầu
=>x =1
e)/x+2/=x
x+2=+-x
x+2=x(không t/m) x+2=-x
ta thử có x=-1 t/m
vậy x=-1
\(\dfrac{2}{3}.3^{x+1}-7.3^x=-405\)
\(\Rightarrow\dfrac{2}{3}.3^x.3^1-7.3^x=-405\)
\(\Rightarrow2.3^x-7.3^x=-405\)
\(\Rightarrow3^x.\left(2-7\right)=-405\)
\(\Rightarrow3^x.-5=-405\)
\(\Rightarrow3^x=\dfrac{-405}{-5}\)
\(\Rightarrow3^x=81\)
Vì \(3^4=81\) nên \(x=4\)
\(\dfrac{2}{3}.3^{x+1}-7.3^x=-405\)
\(\Leftrightarrow\dfrac{2}{3}.3.3^x-7.3^x=-405\)
\(\Leftrightarrow3^x\left(2-7\right)=-405\)
\(\Leftrightarrow3^x.\left(-5\right)=-405\)
\(\Leftrightarrow3^x=81\)
\(\Leftrightarrow3^x=3^4\)
\(\Leftrightarrow x=4\)
Vậy..