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-5/8 . 5/12 + -5/8 .7/12 + 17/8=(-5/8 + -5/8).(5/12 + 7/12).17/8 = 0 . 1 .17/8 = 0 .17/8 = 0
-5/12 . 2/7 + 7/12 . -3/4
= -10/84 + -21/48
= -5/42 + -7/16
= -40/336 + -147/336
= -187/336
\(\frac{-5}{12}\).\(\frac{2}{7}\)+\(\frac{7}{12}\).\(\frac{-3}{4}\)
=\(\frac{5}{12}\).\(\frac{-2}{7}\)+\(\frac{7}{12}\).\(\frac{-3}{4}\)
=\(\frac{5}{12}\).(\(\frac{-2}{7}\)+\(\frac{-3}{4}\))
\(\frac{5}{12}\).\(\frac{-29}{28}\)
=\(\frac{-145}{336}\)
((nho k cho mink nhe)
\(\left(-3,2\right).\frac{-15}{64}+\left(0,8-2\frac{4}{15}\right):3\frac{1}{2}=-\frac{16}{5}.-\frac{15}{64}+\left(\frac{4}{5}-\frac{34}{15}\right):\frac{7}{2}\)
\(=-\frac{3}{4}+\left(-\frac{22}{15}\right).\frac{2}{7}\)
\(=-\frac{3}{4}-\frac{44}{105}\)
\(=\frac{-315-176}{420}\)
\(=-\frac{491}{420}\)
\(\left(-3,2\right)\cdot\frac{-15}{64}+\left(0,8-2\frac{4}{15}\right):3\frac{1}{2}\)
\(=\frac{3}{4}+\frac{-22}{15}:\frac{7}{2}\)
\(=\frac{3}{4}+\frac{-44}{105}\)
\(=\frac{-315}{176}\)
=))
Ta có: \(2\frac{1}{3}+\frac{11}{5}:33-\frac{1}{50}.\left(-5\right)^2\)
\(=\frac{7}{3}+\frac{11}{5}.\frac{1}{33}-\frac{1}{50}.25\)
\(=\frac{7}{3}+\frac{11}{165}-\frac{25}{50}\)
\(=\frac{7}{3}+\frac{1}{15}-\frac{1}{2}\)
\(=\frac{70}{30}+\frac{2}{30}-\frac{15}{30}\)
\(=\frac{56}{30}=\frac{28}{15}\)
hỗn số thì tử phải lớn hơn mẫu thì chia tử với mẫu thì mới ra hỗn số
\(1:\frac{99}{100}:\frac{98}{99}:\frac{97}{98}:.........:\frac{2}{3}:\frac{1}{2}\)
\(=1.\frac{100}{99}.\frac{99}{98}.\frac{98}{97}......\frac{3}{2}.\frac{2}{1}\)
\(=\frac{1.100.99.98....3.2}{99.98.97......2.1}\)
\(=100\)
A=33. \(\left(1-\frac{2}{3}\right)\left(1-\frac{2}{5}\right)...\left(1-\frac{2}{99}\right)\)
A=33.\(\frac{1}{3}.\frac{3}{5}....\frac{97}{99}\)
A=33.\(\frac{1}{99}\)
A=\(\frac{33}{99}=\frac{1}{3}\)
\(\frac{-2}{5}\) \(.\) \(\frac{1}{8}\) = \(\frac{1}{8}\) \(.\) \(\frac{3}{5}\)= \(\frac{3}{40}\)
- Hok t -
Trả lời :
\(-\frac{2}{5}\cdot\frac{1}{8}=\frac{1}{8}\cdot\frac{3}{5}=\frac{3}{40}\)
1k đê
~HT~
\(\frac{1994.1993-2}{1992+1992.1994}=\frac{1994.1992+1994-2}{1992+1992.1994}=\frac{1994.1992+1992}{1992+1992.1994}=1\)
\(\frac{1994.1993-2}{1992+1991.1994}\)
= \(\frac{1994.1992-1994-2}{1992-1992.1994}\)
= \(\frac{1994.1992-1992}{1992-1992.1994}\)
= \(1\)