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a,\(\frac{25}{42}-\frac{20}{63}=\frac{5}{18}\)
b,\(\frac{9}{50}-\frac{13}{75}-\frac{1}{6}\)
=\(\frac{1}{150}-\frac{1}{6}\)
=\(-\frac{4}{25}\)
c,\(\frac{2}{15}+\frac{-2}{65}-\frac{4}{39}\)
=\(\frac{32}{195}-\frac{4}{39}\)
=\(\frac{4}{65}\)
a,=75/126-40/126=35/126=5/18
b,=27/150-26/150-25/150=-4/25
c,=26/195+-6/195-20/195=0
\(a,\frac{11}{24}-\frac{5}{41}+\frac{13}{24}+0.5-\frac{36}{21}\)
\(=\frac{11}{24}+\frac{13}{24}-\frac{5}{41}+\frac{1}{2}-\frac{36}{21}\)
\(=\frac{24}{24}-\frac{5}{41}+\frac{1}{2}-\frac{12}{7}\)
Số hơi to??
\(b,-12:\left(\frac{3}{4}-\frac{5}{6}\right)^2\)
\(=-12:\left(\frac{9}{12}-\frac{10}{12}\right)^2\)
\(=-12:\left(-\frac{1}{12}\right)^2\)
\(=-12\cdot144\)
\(=-1728\)
\(a)=\left(\frac{11}{24}+\frac{13}{24}\right)-\left(\frac{5}{41}+\frac{36}{41}\right)+\frac{1}{2}\)
\(=\frac{24}{24}-\frac{41}{41}+\frac{1}{2}\)
\(=1-1+\frac{1}{2}\)
\(=\frac{1}{2}\)
MSC : 120
\(\frac{1}{2}+\frac{1}{3}+\frac{1}{4}+\frac{1}{5}+\frac{1}{6}\)
\(=\frac{60}{120}+\frac{40}{120}+\frac{30}{120}+\frac{24}{120}+\frac{20}{120}\)
\(=\frac{174}{120}\)
\(=1\frac{54}{120}=1\frac{9}{20}=1,45\)
\(\frac{-7}{25}.\frac{11}{13}+\frac{-7}{25}.\frac{2}{13}-\frac{18}{25}\)
\(=\frac{-7}{25}.\left(\frac{11}{13}+\frac{2}{13}\right)-\frac{18}{25}\)
\(=\frac{-7}{25}.1-\frac{18}{25}\)
\(=\frac{-7}{25}-\frac{18}{25}\)
\(=-1\)
\(5\frac{2}{5}.4\frac{2}{7}+5\frac{5}{7}.5\frac{2}{5}\)
\(=5\frac{2}{5}.\left(4\frac{2}{7}+5\frac{5}{7}\right)\)
\(=5,4.10=54\)
2^2.5^4.2^12.5^4.2^2.3^4/2^12.5^6.3^12=2^16.5^8.3^4/2^12.5^6.3^12=2^4.5^2/3^8=........
\(\frac{13}{25}+\frac{6}{41}-\frac{38}{25}+\frac{35}{41}-\frac{1}{2}\)
\(=\left(\frac{13}{25}-\frac{38}{25}\right)+\left(\frac{6}{41}+\frac{35}{41}\right)-\frac{1}{2}\)
\(=-1+1-\frac{1}{2}=0-\frac{1}{2}\)
\(=\frac{-1}{2}\)
\(1\frac{4}{23}+\frac{5}{21}-\frac{4}{23}+0,5+\frac{16}{21}\)
\(=\left(1\frac{4}{23}-\frac{4}{23}\right)+\left(\frac{5}{21}+\frac{16}{21}\right)+0,5\)
\(=1+1+0,5=2,5\)
\(\frac{13}{25}+\frac{4}{41}-\frac{38}{25}+\frac{35}{41}-\frac{1}{2}\)
= \(\left(\frac{13}{25}-\frac{38}{25}\right)+\left(\frac{6}{41}+\frac{35}{41}\right)-\frac{1}{2}\)
= \(-1+1-\frac{1}{2}=-\frac{1}{2}\)
\(1\frac{4}{23}+\frac{5}{21}-\frac{4}{23}+0,5+\frac{16}{21}\)
=\(\left(1\frac{4}{23}-\frac{4}{23}\right)+\left(\frac{5}{21}+\frac{16}{21}\right)+0,5\)
= \(1+1+0,5=2,5\)
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