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\(\frac{0,16}{x}=\frac{x}{25}\)
\(x.x=0,16.25\)
\(x.x=\left(0.4\right)^2.5^2\)
\(x=2;x=-2\)
0,16:x=x:36
0,16/x=x/36
x^2=144/25
x^2=(12/5)^2;x^2=-(12/5)^2
x=12/5. ; x=-12/5
tick nha bn
(x-1):0,16=-9.(1-x)
=>(x-1):0,16=-9:(-1):(x-1)
=>(x-1):0,16=9:(x-1)
=>(x-1).(x-1)=9.0,16
=>(x-1)2=1,44=1,22=(-1,2)2
=>x-1=1,2=>x=2,2
hoặc x-1=-1,2=>x=-0,2
Vậy x=2,2
x=0,2
Tính các góc của tam giác MNP biết M=80 độ ; N - P =30 độ
a, \(15\dfrac{1}{4}:\left(-\dfrac{5}{7}\right)-25\dfrac{1}{4}:\left(-\dfrac{5}{7}\right)\)
\(=15\dfrac{1}{4}.\left(-\dfrac{7}{5}\right)-25\dfrac{1}{4}.\left(-\dfrac{7}{5}\right)\)
\(=-\dfrac{7}{5}.\left(15\dfrac{1}{4}-25\dfrac{1}{4}\right)\)
\(=-\dfrac{7}{5}.\left(-10\right)\)
\(=\dfrac{7}{5}.10\)
\(=\dfrac{7}{1}.2\)
\(=14\)
b, \(\sqrt{0.16}-\sqrt{0.25}\)
\(=0.4-0.5\)
\(=-0.1\)
a) \(\frac{11}{10,5}=\frac{6,32}{-x}\)
\(6,32:\frac{11}{10,5}=x\)
\(\frac{1659}{275}=x\)
b) \(\frac{x-1}{x+5}=\frac{6}{7}\)
\(\Rightarrow7x-7=6x+30\)
\(7x-6x=30+7\)
\(x=37\)
c) \(\frac{x^2}{6}=\frac{24}{25}\)
\(x^2=\frac{144}{25}\)
\(x=\frac{12}{5}\)
d) \(x:0,16=9:x\)
\(\frac{x}{0,16}=\frac{9}{x}\)
\(x^2=1,44\)
\(x=1,2\)
a) (3x-2):\(1\frac{2}{5}\)=\(2\frac{3}{7}\)
(3x-2):\(\frac{7}{5}\)=\(\frac{17}{7}\)
3x-2 =\(\frac{17}{7}.\frac{7}{5}\)
3x-2 =\(\frac{17}{5}\)
3x =\(\frac{17}{5}+2\)
3x =\(\frac{27}{5}\)
x =\(\frac{27}{5}:3\)
x =\(\frac{27}{5}.\frac{1}{3}\)
x =\(\frac{9}{5}\)
b) x:0,16=9:x
x.x =9.0,16
x2 =\(\frac{36}{25}\)
x2 =\(\left(\frac{6}{5}\right)^2\)
⇒x =\(\frac{6}{5}\)
a) Ta có: \(\left(3x-2\right):1\frac{2}{5}=2\frac{3}{7}:2\frac{3}{5}\)
\(\Leftrightarrow\left(3x-2\right):\frac{7}{5}=\frac{17}{7}:\frac{13}{5}\)
\(\Leftrightarrow\left(3x-2\right)\cdot\frac{5}{7}=\frac{17}{7}\cdot\frac{5}{13}=\frac{85}{91}\)
\(\Leftrightarrow3x-2=\frac{85}{91}:\frac{5}{7}=\frac{85}{91}\cdot\frac{7}{5}=\frac{17}{13}\)
\(\Leftrightarrow3x=\frac{17}{13}+2=\frac{43}{13}\)
\(\Leftrightarrow x=\frac{43}{13}:3=\frac{43}{13}\cdot\frac{1}{3}\)
hay \(x=\frac{43}{39}\)
Vậy: \(x=\frac{43}{39}\)
b) ĐKXĐ: x≠0
Ta có: \(\frac{x}{0.16}=\frac{9}{x}\)
\(\Leftrightarrow x\cdot x=9\cdot0.16\)
\(\Leftrightarrow x^2=1.44\)
hay \(x\in\left\{1.2;-1.2\right\}\)(nhận)
Vậy: \(x\in\left\{1.2;-1.2\right\}\)
a) \(\frac{3x-2}{1\frac{2}{5}}=\frac{2\frac{3}{7}}{2\frac{3}{5}}\Rightarrow3x-2=1.\frac{2}{5}.\frac{2\frac{3}{7}}{2\frac{3}{5}}=\frac{7}{5}.\frac{17}{7}.\frac{5}{13}\)
\(3x-2=\frac{17}{13}\Rightarrow3x=2+\frac{17}{13}=\frac{43}{13}\Rightarrow x=\frac{43}{39}.\)
b) \(\frac{x}{0,16}=\frac{9}{x}\Rightarrow x^2=9.0,16=1,44\Rightarrow x=\pm1,2\)
\(\Rightarrow\)\(\frac{0,16}{x}=\frac{x}{0,25}\)
\(x.x=0,16\times0,25\)
\(x^2=0,04\)
\(\Rightarrow\)\(x=\pm0,02\)