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Đặt A = \(\dfrac{1}{3}+\dfrac{1}{15}+\dfrac{1}{35}+\dfrac{1}{63}+\dfrac{1}{99}+\dfrac{1}{143}+\dfrac{1}{195}\)
\(=\dfrac{1}{1.3}+\dfrac{1}{3.5}+\dfrac{1}{5.7}+\dfrac{1}{7.9}+\dfrac{1}{9.11}+\dfrac{1}{11.13}+\dfrac{1}{13.15}\)
\(\Rightarrow2A=\)\(=\dfrac{2}{1.3}+\dfrac{2}{3.5}+\dfrac{2}{5.7}+\dfrac{2}{7.9}+\dfrac{2}{9.11}+\dfrac{2}{11.13}+\dfrac{2}{13.15}\)
\(\Rightarrow2A=\) \(\dfrac{1}{1}-\dfrac{1}{3}+\dfrac{1}{3}-\dfrac{1}{5}+...+\dfrac{1}{13}-\dfrac{1}{15}\)
\(\Rightarrow2A=\) \(\dfrac{1}{1}-\dfrac{1}{15}=\dfrac{14}{15}\)
\(\Rightarrow A=\dfrac{14}{15}:2=\dfrac{7}{15}\)
Câu 14)
\(a,\\ =-\dfrac{3}{8}+\dfrac{8}{17}+\dfrac{-5}{8}-\dfrac{3}{5}+\dfrac{9}{17}\\ =\left(\dfrac{-3}{8}+\dfrac{-5}{8}\right)+\left(\dfrac{8}{17}+\dfrac{9}{17}\right)-\dfrac{3}{5}\\ =\left(-1\right)+1-\dfrac{3}{5}=0-\dfrac{3}{5}=\dfrac{-3}{5}\\ b,\\ =\dfrac{7}{15}.\dfrac{-15}{14}+\left(\dfrac{27}{16}-\dfrac{1}{8}\right):\dfrac{5}{8}\)
\(=\dfrac{-1}{2}+\dfrac{25}{16}.\dfrac{8}{5}=\dfrac{-1}{2}+\dfrac{5}{2}=2\\ c,\\ =\dfrac{2}{2}-\dfrac{2}{3}+\dfrac{2}{3}-\dfrac{2}{4}+.....+\dfrac{2}{99}-\dfrac{2}{100}\\ =1-\dfrac{1}{50}=\dfrac{49}{50}\)
Câu 15
\(a,2x+\dfrac{-1}{4}=\dfrac{3}{2}\\ 2x=\dfrac{3}{2}-\dfrac{-1}{4}=\dfrac{7}{4}\\ x=\dfrac{7}{4}:2=\dfrac{7}{8}\\ b,\dfrac{15}{x}=\dfrac{-3}{4}\\ x=\dfrac{15.4}{-3}=-20\)
Giải:
Tên tam giác |
Tên 3 đỉnh |
Tên 3 góc |
Tên 3 cạnh |
ABI |
A,B,I |
|
AB, BI, IA |
AIC |
A,I,C |
|
AI, IC, CA |
ABC |
A,B,C |
|
AB, BC, CA |
50%x = x/2 ta có:
x/2 +2x/3 =x+4
x(1/2 +2/3) = x+4
7x/6 =x+4
7x = 6x+24
x = 24
50% = 1/2 rồi bn qui đồng mẫu số, sau đó chuyển vế là ra, bn làm đi cho giỏi, nếu k hiu chỗ nào mk giúp, thân ái
a)\(123-5:\left(x+4\right)=38\)
\(5:\left(x+4\right)=123-38\)
\(5:\left(x+4\right)=85\)
\(x+4=5:85\)
\(x=\dfrac{1}{17}-4\)
\(x=-\dfrac{67}{17}\)
b)\(70-5.\left(x-3\right)=45\)
\(5.\left(x-3\right)=70-45\)
\(5.\left(x-3\right)=35\)
\(x-3=35:5\)
\(x-3=7\)
\(x=7+3\)
\(x=10\)
a)\(\dfrac{-2}{17}+\dfrac{8}{17}=\dfrac{6}{17}\)
b) \(\dfrac{-9}{16}+\dfrac{7}{24}=\dfrac{-13}{48}\)
c)\(\dfrac{1}{8}+\dfrac{-5}{6}+\dfrac{7}{-36}=\dfrac{-17}{24}+\dfrac{7}{-36}=\dfrac{-65}{72}\)
a) =\(\dfrac{-2+8}{17}=\dfrac{6}{17}\)
b) =\(\dfrac{-27}{48}+\dfrac{14}{48}=\dfrac{-27+14}{48}=\dfrac{-13}{48}\)
c) \(=\dfrac{9}{72}+\dfrac{-60}{72}+\dfrac{-14}{72}=\dfrac{9+\left(-60\right)+\left(-14\right)}{72}=\dfrac{-65}{72}\)