Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.
Bài 1 : Tính nhẩm:
a) 1213 - 997 = (1213 + 3 ) - ( 997 + 3 )
= 1216 + 1000
= 2216
b) 28 . 25 = ( 28 : 4 ) . ( 25 . 4 )
= 7 . 100
= 700
c) 3000 : 125 = ( 3000 . 4 ) . ( 125 . 4 )
= 12000 . 500
= 24
d) 156 : 12 = ( 156 . 5 ) : ( 12 . 5 )
= 780 : 60
= 13
Bài 2 : Tìm x, biết :
a) x - 280 : 35 = 5 . 54
x - 280 : 35 = 270
x - 280 = 270 . 35
x - 280 = 9450
x = 9450 + 280
x = 9730
b) ( x - 280 ) : 35 = 56 : 5
x = 56 : 5 dư nên x bằng quả bí. Mk ko thích suy nghĩ
c) x : 15 + 42 = 13 + 25 . 8
x : 15 + 4 = 213
x : 15 = 213 - 4
x : 15 = 209
x = 209 . 15
x = 3135
d) 3636 : ( 12x - 91 ) = 36
12x - 91 = 3636 : 36
12x - 91 = 11
12x = 11 + 91
12x = 102
x = 102 : 12
x = 8,5
e) ( x : 23 + 45 ) . 67 = 8911
x : 23 + 45 = 8911 : 67
x : 23 + 45 = 133
x : 23 = 133 - 45
x : 23 = 88 . 23
= 2024
f) 64x + 36x = 1500
x( 64 + 26 ) = 1500
x . 90 = 1500
x = 1500 : 90
x = 150 / 90
Bài 1:
a) \(2^8.2.4=2^9.2^2=2^{11}\)
b) \(8^5:64=8^5:8^2=8^3\)
c) \(3^7:9=3^7:3^2=3^5\)
d) \(9^{17}.81=9^{17}.9^2=9^{19}\)
e) \(x^6.x.x^2=x^9\)
Bài 2:
a) \(2^x-15=17\)
\(\Rightarrow2^x=32\)
\(\Rightarrow2^x=2^5\)
\(\Rightarrow x=5\)
Vậy x = 5
b) \(2.3^x=162\)
\(3^x=162:2\)
\(3^x=81\)
\(\Rightarrow3^x=3^4\)
\(\Rightarrow x=4\)
Vậy x = 4
c) \(5.x.5^2=10\)
\(\Rightarrow x.5^3=10\)
\(\Rightarrow x.125=10\)
\(\Rightarrow x=10:125\)
\(\Rightarrow x=\frac{2}{25}\)
Vậy \(x=\frac{2}{25}\)
d) \(5.x^2-1=124\)
\(\Rightarrow5.x^2=125\)
\(\Rightarrow x^2=125:5\)
\(\Rightarrow x^2=5^2\)
\(\Rightarrow x=\pm5\)
Vậy \(x=\pm5\)
Câu 1:
a)28.2.4=28.2.22=211
b)85:64=85:82=83
c)37:9=37:32=35
d)917.81=917.92=919
e)x6.x.x2=x9
suy nghi nha
a)\(123-5:\left(x+4\right)=38\)
\(5:\left(x+4\right)=123-38\)
\(5:\left(x+4\right)=85\)
\(x+4=5:85\)
\(x=\dfrac{1}{17}-4\)
\(x=-\dfrac{67}{17}\)
b)\(70-5.\left(x-3\right)=45\)
\(5.\left(x-3\right)=70-45\)
\(5.\left(x-3\right)=35\)
\(x-3=35:5\)
\(x-3=7\)
\(x=7+3\)
\(x=10\)
câu a
\(\left(2x-2017\right)^2=289\\ < =>\left[\begin{matrix}2x-2017=17\\2x-2017=-17\end{matrix}\right.\\ < =>\left[\begin{matrix}x=1017\left(tm\right)\\x=1000\left(tm\right)\end{matrix}\right.\)
vậy...
câu b
\(\left(\left|x\right|+2016\right)\left(2018-2\left|x\right|\right)=0\\ < =>\left[\begin{matrix}\left|x\right|+2016=0\\2018-2\left|x\right|=0\end{matrix}\right.\\ < =>\left[\begin{matrix}\left[\begin{matrix}x=2016\\x=-2016\end{matrix}\right.\\\left[\begin{matrix}x=1009\\x=-1009\end{matrix}\right.\end{matrix}\right.\) (tm)
vậy ...
câu c
(x - 2016) (2y + 2017) = 5
<=> (x - 2016) (2y + 2017) = 1 . 5 = (-1) (-5)
xét thấy 2y + 2017 là số lẻ
=> \(\left[\begin{matrix}2y+2017=5\\2y+2017=-5\end{matrix}\right.\)
=> \(\left[\begin{matrix}\left\{\begin{matrix}x-2016=1\\2y+2017=5\end{matrix}\right.\\\left\{\begin{matrix}x-2016=-1\\2y+2017=-5\end{matrix}\right.\end{matrix}\right.\)
<=> \(\left[\begin{matrix}\left\{\begin{matrix}x=2017\\y=-1006\end{matrix}\right.\\\left\{\begin{matrix}x=2015\\y=-1011\end{matrix}\right.\end{matrix}\right.\) (tm)
vậy ...
số nguyên dương lớn nhất có 3 cs khác nhau là 987
=> lx-2l = 987
<=> x-2 = 987 hoặc x-2 = -987
<=> x=989 hoặc x=-985 (tm)
vậy ...
Câu 2:
b: \(\dfrac{1}{1\cdot2}+\dfrac{1}{2\cdot3}+...+\dfrac{1}{n\left(n+1\right)}\)
\(=1-\dfrac{1}{2}+\dfrac{1}{2}-\dfrac{1}{3}+...+\dfrac{1}{n}-\dfrac{1}{n+1}\)
\(=1-\dfrac{1}{n+1}=\dfrac{n}{n+1}\)
c: \(\dfrac{1}{20}+\dfrac{1}{30}+...+\dfrac{1}{110}\)
\(=\dfrac{1}{4}-\dfrac{1}{5}+\dfrac{1}{5}-\dfrac{1}{6}+\dfrac{1}{6}-...+\dfrac{1}{10}-\dfrac{1}{11}\)
\(=\dfrac{1}{4}-\dfrac{1}{11}=\dfrac{7}{44}\)
a, \(^{2^2}\) x- 49 = 5. \(^{3^2}\)
4x - 49 = 45
4x = 45+49
4x = 94
x = 94 :4
x = 26
b, 2\(^{^x}\) : 25 = 1
2\(^{^x}\) 5\(^{^2}\) = 1
2\(^{^x}\) = 2
x = 2 : 2
x = 1
a: \(=105-96=9\)
b: =225+108=333
c: =-8x9-8x(-27)
\(=-8\left(9-27\right)=144\)
d: \(=1\cdot5+\left(-8\right)\cdot6-\left(-27\right)\cdot7=5-48+189=146\)
Bài 1:
a, (-8) . 25. (-2) . 125 . (-5)
= [(-8) . 125] .[ 25 . (-5)]
= (-1000) . (-125)
= 125 000